Time and Distance Question Practice Question and Answer

Q:

Shyam covers a distance of 400 km in 5 hours. He traveled for some time at a speed of 85 km / h and the rest at a speed of 55 km / h. How long did he travel at high speed?

1591 0

  • 1
    4 hour 15 minute
    Correct
    Wrong
  • 2
    4 hour 35 minute
    Correct
    Wrong
  • 3
    4 hour 25 minute
    Correct
    Wrong
  • 4
    4 hour 20 minute
    Correct
    Wrong
  • Show Answer
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Answer : 4. "4 hour 20 minute"

Q:

I walk a certain distance and ride back taking a total time of 37 minutes. I could walk both ways in 55 minutes. How long would it take me to ride both ways?

1589 0

  • 1
    17 minute
    Correct
    Wrong
  • 2
    19 minute
    Correct
    Wrong
  • 3
    19.5 minute
    Correct
    Wrong
  • 4
    29 minute
    Correct
    Wrong
  • Show Answer
  • Workspace

Answer : 2. "19 minute"

Q:

The distance between two cities A and B is 330 km. A train starts from A at 8 a.m. and travels towards Bat 60 km / hr. Another train starts from Bat 9 a.m. and travels towards A at 75 km/hr. At what time do they meet?

1577 0

  • 1
    10 : 00 am
    Correct
    Wrong
  • 2
    10 : 30 am
    Correct
    Wrong
  • 3
    11 : 00 am
    Correct
    Wrong
  • 4
    11 : 30 am
    Correct
    Wrong
  • Show Answer
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Answer : 3. "11 : 00 am "

Q:

A runner starts running from a point at 6:00 am with a speed of 8km / hr. Another racer starts from the same point at 8:30 am in the same direction with a speed of 10km / hr. At what time of the day (in P.M.) will the second racer will overtake the other runner? 

1558 0

  • 1
    8 : 00
    Correct
    Wrong
  • 2
    4 : 00
    Correct
    Wrong
  • 3
    6 : 30
    Correct
    Wrong
  • 4
    5 : 30
    Correct
    Wrong
  • Show Answer
  • Workspace

Answer : 3. "6 : 30 "

Q:

A 160-meter-long train running at a speed of 90 km/h crosses a platform is 18 s. What is the length of the platform in metre?

1556 0

  • 1
    210
    Correct
    Wrong
  • 2
    240
    Correct
    Wrong
  • 3
    290
    Correct
    Wrong
  • 4
    310
    Correct
    Wrong
  • 5
    None of these
    Correct
    Wrong
  • Show Answer
  • Workspace

Answer : 3. "290"

Q:

A policeman starts to chase a thief. When the thief goes 10 steps the policeman moves 8 steps and 5 steps of the policeman are equal to 7 steps of the thief. The ratio of the speeds of the policeman and the thief is: 

1533 0

  • 1
    28 : 25
    Correct
    Wrong
  • 2
    56 : 25
    Correct
    Wrong
  • 3
    25 : 28
    Correct
    Wrong
  • 4
    25 : 26
    Correct
    Wrong
  • Show Answer
  • Workspace

Answer : 1. "28 : 25 "

Q:

Akhil takes 30 minutes extra to cover a distance of 150 km if he drives 10 km/h slower than his usual speed. How much time will he take to drive 90 km if he drives 15 km per hours slower than his usual speed?

1519 0

  • 1
    2h 45m
    Correct
    Wrong
  • 2
    2h 30m
    Correct
    Wrong
  • 3
    2h
    Correct
    Wrong
  • 4
    2h 15m
    Correct
    Wrong
  • Show Answer
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Answer : 3. "2h "
Explanation :

Let's use the information given to calculate Akhil's usual speed first.

We know that Akhil takes 30 minutes (0.5 hours) extra to cover a distance of 150 km when he drives 10 km/h slower than his usual speed.

Let "S" be Akhil's usual speed in km/h. So, his slower speed would be (S - 10) km/h.

The time taken to cover a distance is equal to the distance divided by the speed: Time = Distance / Speed

At his usual speed, it takes him: Time at usual speed = 150 km / S hours

At the slower speed, it takes him: Time at slower speed = 150 km / (S - 10) hours

The difference in time between these two scenarios is 0.5 hours (30 minutes): Time at slower speed - Time at usual speed = 0.5 hours

Now, we can set up the equation and solve for S:

(150 km / (S - 10)) - (150 km / S) = 0.5

To solve this equation, we'll first get a common denominator: [150S - 150(S - 10)] / [S(S - 10)] = 0.5

Now, simplify and solve for S: [150S - 150S + 1500] / [S(S - 10)] = 0.5

1500 / [S(S - 10)] = 0.5

Now, cross-multiply: 2 * 1500 = S(S - 10)

3000 = S^2 - 10S

S^2 - 10S - 3000 = 0

Now, we can solve this quadratic equation for S using the quadratic formula:

S = [-(-10) ± √((-10)^2 - 4(1)(-3000))] / (2(1))

S = [10 ± √(100 + 12000)] / 2

S = [10 ± √12100] / 2

S = [10 ± 110] / 2

Now, we have two possible values for S, but we'll take the positive one because speed cannot be negative:

S = (10 + 110) / 2 = 120/2 = 60 km/h

So, Akhil's usual speed is 60 km/h.

Now, we want to find out how much time he will take to drive 90 km when he drives 15 km/h slower than his usual speed, which would be (60 - 15) = 45 km/h.

Time = Distance / Speed Time = 90 km / 45 km/h = 2 hours

Akhil will take 2 hours to drive 90 km when he drives 15 km/h slower than his usual speed.

Q: A Train when moves at an average speed of 40 kmph, reaches its destination on time. When its average speed becomes 35 kmph, then it reaches its destination 15 minutes late. Find the length of journey. 1515 0

  • 1
    30 km
    Correct
    Wrong
  • 2
    40 km
    Correct
    Wrong
  • 3
    70 km
    Correct
    Wrong
  • 4
    80 km
    Correct
    Wrong
  • Show Answer
  • Workspace

Answer : 3. "70 km"

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