Trigonometry Question and Answers Practice Question and Answer
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Q: $$ {3tan^{2}30°}-{4\over 3}{sin^{2}60°}- {1\over2}{cosec^{2}45°}+{4\over3}{sin^{2}90°=?}$$
1202 05f76cd32e487e60dced9212c
5f76cd32e487e60dced9212c- 1$$ {2\over3}$$false
- 2$$ {1\over3}$$true
- 3$$ {4\over3}$$false
- 4$$ {5\over4}$$false
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Answer : 2. "$$ {1\over3}$$"
Q: If 3 + cos2θ= 3(cot2θ + Sin2θ), 0°<θ<90°, then what is the value of (cosθ +2sinθ)?
1202 05fbf73c64f2f6c622be747fa
5fbf73c64f2f6c622be747fa- 1$$ {2\sqrt{3}+1\over {2}}$$true
- 2$$ {3\sqrt{2}}$$false
- 3$$ {3\sqrt{3}+1\over {2}}$$false
- 4$$ {\sqrt{3}+2\over 2}$$false
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Answer : 1. "$$ {2\sqrt{3}+1\over {2}}$$"
Q: If $$ secθ-tanθ={1\over\sqrt{3}}$$, the value of secθ.tanθ=?
1202 05dccdc38e9d33d6509c0ab1a
5dccdc38e9d33d6509c0ab1a- 1$$ {4\over\sqrt{3}}$$false
- 2$$ {2\over\sqrt{3}}$$false
- 3$$ {2\over3}$$true
- 4$$ {1\over\sqrt{3}}$$false
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Answer : 3. "$$ {2\over3}$$ "
Q: Which of the following simplification value of $$ {(secA-cosA)^{2}}+{(cosecA-sinA)^{2}}-{(cotA-tanA)^{2}}$$ ?
1201 05f2e3f9eb6a1cb7a831ba681
5f2e3f9eb6a1cb7a831ba681- 14false
- 22false
- 31true
- 43false
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Answer : 3. "1"
Q: If Cos A + Cos2 A = 1, then Sin2 A + Sin4 A=?
1195 06099029ec4aedb3e80669631
6099029ec4aedb3e80669631- 10false
- 21true
- 3$$ {1\over 2}$$false
- 4-1false
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Answer : 2. "1"
Q: If a=tanθ + 1 and b=sinθ+cosθ then find (b2-1)a=?
1188 0605c564922ce9764eb4d0d5e
605c564922ce9764eb4d0d5e- 1abfalse
- 22bsecθfalse
- 32bfalse
- 42bsin θtrue
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Answer : 4. "2bsin θ"
Q: If tan A=n tan B and Sin A= m Sin B, then the value of Cos2A is
1180 05f4df246081699374e855fcf
5f4df246081699374e855fcf- 1$$ {m^{2}+1\over {n^{2}+1}}$$false
- 2$$ {m^{2}+1\over {n^{2}-1}}$$false
- 3$$ {m^{2}-1\over {n^{2}-1}}$$true
- 4$$ {m^{2}-1\over {n^{2}+1}}$$false
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Answer : 3. "$$ {m^{2}-1\over {n^{2}-1}}$$"
Q: If $$ {1+sinθ\over {1-sinθ}}={p^{2}\over{q^{2}}}$$, then sec θ is equal to:
1168 05f40dfa24c9a9415f7cdfc3b
5f40dfa24c9a9415f7cdfc3b- 1$$ {2p^{2}{q^{2}}\over {p^{2}+{q^{2}}}}$$false
- 2$${1\over 2}\left({q\over p}+{p\over q} \right)$$true
- 3$$ {1\over {p^{2}}}+{1\over {q^{2}}}$$false
- 4$$ {p^{2}q^{2}}\over{p^{2}+q^{2}}$$false
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Answer : 2. "$${1\over 2}\left({q\over p}+{p\over q} \right)$$"
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