Sin (45 + θ) – Cos (45 – θ) is:

If tanx = cot(50+3x), then what is the value of x ?

$$(1+tan θ+secθ)(1+cotθ-cosecθ)\over (sec θ+tan θ)(1-sin θ) $$ is equal to :

$${sin^2θ\over cosθ(1+cosθ)}+{1+cosθ\over cosθ} =?$$

Evaluate the following.

sin 25° sin 65° – cos 25° cos 65°.

(sec A + tan A – 1) (sec A – tan A+1) =?

If secθ + tanθ = 3, then the value of secθ is:

If $${cos^2θ\over cot^2θ-cos^2θ}=3,$$ where $${0^0<θ<90^0}$$ then the value of θ is: