if $$tan(A+B)=\sqrt { 3} \ $$ and $$ tan(A-B)= {1\over \sqrt { 3} \   }; 0^0<(A+B)<90^0;A>B, $$ then the value of A and B are

If $${secθ+tanθ\over secθ-tanθ}={5\over 3}$$ then sinθ is equal to ;

If x = a secθ cos∅, y = b secθ sin∅, z=c tanθ, then the value of $$ {x^2\over a^2}+{y^2\over b^2}-{z^2\over c^2} $$

$$\left({1\over cosecθ}-{1\over sinθ} \right)+{1\over {cosecθ-cotθ}} -{1\over secθ+tanθ} =?$$

cosA(sec A – cosA)(cotA+tanA)=?

Find the value of tan 27⁰ tan34⁰ + tan34⁰ tan29⁰ + tan29⁰ tan27⁰.

What is the value of cosecA(1 − cosA)(cosecA + cotA)?

△ABC is right-angle triangle at B and tan A = $$3\over 4$$, then sin A + sin B + sin C will be equal to: