The value of   $${sin23^0cos67^0+sec52^0sin38^0+cos23^0sin67^0+cosec52^0cos38^0}\over cosec^220^0-tan^270^0$$ is

Find the value of tan 27⁰ tan34⁰ + tan34⁰ tan29⁰ + tan29⁰ tan27⁰.

△ABC is right-angle triangle at B and tan A = $$3\over 4$$, then sin A + sin B + sin C will be equal to:

What is the value of cosecA(1 − cosA)(cosecA + cotA)?

The value of   $${cosθ+sin^6θ+3sin^2θ \ cos^2θ}\over cosecθsecθ(sinθ+cosθ-1)(sinθ+cosθ+1) $$

If x = a secθ cos∅, y = b secθ sin∅, z=c tanθ, then the value of $$ {x^2\over a^2}+{y^2\over b^2}-{z^2\over c^2} $$

Find the exact value of cos 120⁰.

If 4sin²θ=3(1+cosθ),0⁰<θ<90⁰, then what is the value of (2tanθ+4sinθ-secθ)?