Trigonometry Question and Answers Practice Question and Answer
8 4 Q:
5d931dffbc45ad7944d99f37 4 Q:
5ef04e7e8022cc4acbba8b20 4 Q:
5d70e14bd8eebc768d116cb7 Answer : 2. "1"
4 Q:
5f155723cf79540a7533c1ca 4 Q:
5dd38171bfcbc45cddedd890 4 Q: What is the value of the following
5d70e27c9004b376a58c1e62 4 Q:
5eb4ece5336570304e19867b 4 Q:
5f06dd933f7f07047795e991 Answer : 2. "$$ tanθ+cotθ$$"
Q: If tan2θ +cot2θ = 2, then what is the value of 2secθ cosecθ?
1490 05d931dffbc45ad7944d99f37
5d931dffbc45ad7944d99f37- 10false
- 21false
- 32false
- 44true
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Answer : 4. "4"
Q: Find the value tanθ-cosθ in the given figure.

1488 05ef04e7e8022cc4acbba8b20
5ef04e7e8022cc4acbba8b20- 1$${4\over5}$$false
- 2$$-{4\over9}$$false
- 3$$-{1\over20}$$true
- 4$${3\over20}$$false
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Answer : 3. "$$-{1\over20}$$"
Q: What is the value of

1480 05d70e14bd8eebc768d116cb7
5d70e14bd8eebc768d116cb7
- 10false
- 21true
- 3-1false
- 42false
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Answer : 2. "1"
Explanation :
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Q: What is the value of sin2 60° + cos230°+ cot2 45° + sec2 60° – cosec2 30° + cos2 0°.
1471 05f155723cf79540a7533c1ca
5f155723cf79540a7533c1ca- 1$$ {7\over2}$$true
- 2$$ {7\over4}$$false
- 3$$ {7\over3}$$false
- 4$$ {7\over8}$$false
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Answer : 1. "$$ {7\over2}$$"
Q: If tan α = 2, then the value of $$ {cosec^2 α - sec^2 α}\over{cosec^2 α + sec^2 α} $$ is :
1461 05dd38171bfcbc45cddedd890
5dd38171bfcbc45cddedd890- 1$$ -{15\over 9} $$false
- 2$$ {3\over 5} $$false
- 3$$ -{3\over 5} $$true
- 4$$ {17\over 5} $$false
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Answer : 3. "$$ -{3\over 5} $$"
Q: What is the value of the following 
1448 05d70e27c9004b376a58c1e62
5d70e27c9004b376a58c1e62
- 1cosec Afalse
- 2cos Afalse
- 3secAtrue
- 4sinAfalse
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Answer : 3. "secA"
Q: If secθ – tanθ = 1/3 what is secθ + tanθ?
1444 05eb4ece5336570304e19867b
5eb4ece5336570304e19867b- 11false
- 29false
- 33true
- 41/9false
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Answer : 3. "3 "
Q: $$ \sqrt {sec^2{θ}+cosec^2{θ}}=?$$
1420 05f06dd933f7f07047795e991
5f06dd933f7f07047795e991- 1$$ {tan^2{θ}}+cot^2{θ}$$false
- 2$$ tanθ+cotθ$$true
- 3$$ sinθ+cosθ$$false
- 4None of thesefalse
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Answer : 2. "$$ tanθ+cotθ$$"
Explanation :
$$ \sqrt {sec^2{θ}+cosec^2{θ}}$$
We know that
$$ {1+tan^2{θ}}={sec^2θ}$$
$$ {1+cot^2{θ}}={cosec^2{θ}}$$
$$ \sqrt {1+tan^2{θ}+1+cot^2{θ}}$$