Algebra Practice Question and Answer
8 Q: If (x + 6y) = 8, and xy = 2, where x > O, what is the value of (x3+216y3)?
1113 0646dd723c899b466f467fe29
646dd723c899b466f467fe29- 1476false
- 2288false
- 3224true
- 4368false
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Answer : 3. "224"
Q: If x = z = 225 and y = 226 then the value of : x3 + y3 + z3 – 3xyz is
1112 064660a6b0827e80a9f9a8cbf
64660a6b0827e80a9f9a8cbf- 1765false
- 2676true
- 3576false
- 4674false
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Answer : 2. "676 "
Q:Directions: In each of these questions, two equations (i) and (ii) are given, you have to solve both the equations and give answer accordingly.
(i) 12x² + 11x + 2 = 0
(ii) 12y²+ 7y + 1 = 0
1106 064d5cf55bd50dd8e2e15c604
64d5cf55bd50dd8e2e15c604(ii) 12y²+ 7y + 1 = 0
- 1x ≥ yfalse
- 2x > yfalse
- 3x < yfalse
- 4x ≤ yfalse
- 5x = y or no relation can be established between x & y.true
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Answer : 5. "x = y or no relation can be established between x & y."
Q: What is the value of a2+b2+c2-2ab-2bc+2ca?
1090 064805a7923e51f477704d402
64805a7923e51f477704d402- 1(2a + b + c)2false
- 2true
(a − b + c)2
- 3false
(a − b − 2c)2
- 4false
(a + 2b − c)2
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Answer : 2. "(a − b + c)2
"
Q:Directions: In each of these questions, two equations (i) and (ii) are given, you have to solve both the equations and give answer accordingly.
(i) 21x² + 10x + 1 = 0
(ii) 24y²+ 26y + 5 = 0
1054 064d5cfffa79837744725ae33
64d5cfffa79837744725ae33(ii) 24y²+ 26y + 5 = 0
- 1x ≤ yfalse
- 2x ≥ yfalse
- 3x > yfalse
- 4x < yfalse
- 5x = y or no relation can be established between x & y.true
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Answer : 5. "x = y or no relation can be established between x & y."
Q: if 2x + 3y = 17 and 2x+2 – 3y+1 = 5, then :
1048 064b5019c36fc1bf576507e45
64b5019c36fc1bf576507e45- 1x = 1, y = 3false
- 2x = 3, y = 3false
- 3x = 3, y = 2true
- 4x = 1, y = 2false
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Answer : 3. "x = 3, y = 2"
Q: If a = 2·361, b = 3·263 and c = 5·624, then the value of a3 + b3 – c3 + 3abc is
1043 06409cf73a37bb1a5e16e1b62
6409cf73a37bb1a5e16e1b62- 135·621false
- 20true
- 319·277false
- 41false
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Answer : 2. "0"
Q:Directions: In each of these questions, two equations (i) and (ii) are given, you have to solve both the equations and give answer accordingly.
(i) 3x² + 11x + 10 = 0
(ii) 2y² + 11y + 14 = 0
1033 064d5cec3bd50dd8e2e15c472
64d5cec3bd50dd8e2e15c472(ii) 2y² + 11y + 14 = 0
- 1x ≥ ytrue
- 2x ≤ yfalse
- 3x > yfalse
- 4x < yfalse
- 5x = y or no relation can be established between x & y.false
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