Algebra Practice Question and Answer
8 Q: If x2 + x = 5 then the value of $${(x+3)^3}+{1\over (x+3)^3}$$ is
1163 0646609fc0827e80a9f9a8a76
646609fc0827e80a9f9a8a76- 1140false
- 2110true
- 3130false
- 4120false
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Answer : 2. "110 "
Q:Directions: In each of these questions, two equations (i) and (ii) are given, you have to solve both the equations and give answer accordingly.
(i) 3x² + 11x + 10 = 0
(ii) 2y² + 11y + 14 = 0
1161 064d5cec3bd50dd8e2e15c472
64d5cec3bd50dd8e2e15c472(ii) 2y² + 11y + 14 = 0
- 1x ≥ ytrue
- 2x ≤ yfalse
- 3x > yfalse
- 4x < yfalse
- 5x = y or no relation can be established between x & y.false
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Answer : 1. "x ≥ y"
Q: If $$x+{1\over x}=2 $$ then the value of $$x^{12}-{1\over x^{12}} $$ is
1157 0646607ee0827e80a9f9a7b64
646607ee0827e80a9f9a7b64- 12true
- 2– 4false
- 30false
- 44false
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Answer : 1. "2 "
Q: If m = – 4, n = – 2, then the value of m3 – 3m2 + 3m + 3n + 3n2 + n3 is
1152 064660782c899b466f455f5f4
64660782c899b466f455f5f4- 1– 126true
- 2124false
- 3– 124false
- 4126false
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Answer : 1. "– 126 "
Q:Directions: In each of these questions, two equations (i) and (ii) are given, you have to solve both the equations and give answer accordingly.
(i) 6x² – 11x + 4 = 0
(ii) 3y² – 5y + 2 = 0
1149 064d5cdd980ef1e74b4d61cce
64d5cdd980ef1e74b4d61cce(ii) 3y² – 5y + 2 = 0
- 1x ≤ yfalse
- 2x < yfalse
- 3x ≥ yfalse
- 4x > yfalse
- 5x = y or no relation can be established between x & y.true
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Answer : 5. "x = y or no relation can be established between x & y."
Q: If a = 2·361, b = 3·263 and c = 5·624, then the value of a3 + b3 – c3 + 3abc is
1145 06409cf73a37bb1a5e16e1b62
6409cf73a37bb1a5e16e1b62- 135·621false
- 20true
- 319·277false
- 41false
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Answer : 2. "0"
Q: If P = 99, then the value of P(P2+3P+3) is
1142 06343d790e76f2264c5df91ee
6343d790e76f2264c5df91ee- 1999false
- 2999999true
- 399999false
- 499false
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Answer : 2. "999999"
Q: If x = 2 - 21/3 + 22/3, then the value of x3– 6x2 + 18x + 18 is
1131 06409ce6f36c856ead79cb82a
6409ce6f36c856ead79cb82a- 122false
- 233false
- 340true
- 445false
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