Directions: In each of these questions, two equations (i) and (ii) are given, you have to solve both the equations and give answer accordingly.

(i) 2x³ = $$ \sqrt {256}$$
 (ii) 2y² – 9y + 10 = 0

Directions: In each of these questions, two equations (i) and (ii) are given, you have to solve both the equations and give answer accordingly.

(i) 6x² – 11x + 4 = 0
 (ii) 3y² – 5y + 2 = 0

When a number x is divided by a divisor it is seen that the divisor = 4 times the quotient=double the remainder. If the remainder is 80 then the value of x is

$$ {1\over {^3\sqrt{4}+{^3\sqrt{2}}}+1}=a^3\sqrt{4}+ b^3\sqrt{2}+c $$ and a, b, c are rational numbers, then a + b + c is equal to

If (x + y)³ +8 (x - y)³ = (3x+ Ay)(3x²+ Bxy+ Cy²), then the value of A+B+C is:

If x² + x = 5 then the value of   $${(x+3)^3}+{1\over (x+3)^3}$$ is

if $${{5x-7}\over 3}+2={{4x-3}\over 4}+4x$$, then the value of (8x+5) is

$$x+{1\over x}=2$$ and x is real, then the value of $$x^{17}+{1\over x^{19}}$$ is