Direction: Equation number I and II are given. You have to solve both the question and answer.
$$ {I.x^{2}={144}}$$
$$ {II.y^{2}-24y+144=0}$$

In the following questions two equations numbered I and II are given. You have to solve both the equations and ____
I.$$\sqrt { 361} x+\sqrt { 16}=0 \ $$
II.$$\sqrt { 441} y+\ { 4}=0 \ $$
Give answer
(A) x> y
(B) x ≥ y
(C) x< y
(D) x ≤ y
(E) x=y or the relationship cannot be established

Direction: In the following questions two equations numbered I and II are given. You have to solve both the equations and give answer.
(A) x>y
(B) x≥y
(C) x˂y
(D) x≤y
(E) x=y or the relations ship cannot be established

I. $$ {4x^2=49}$$
II. $$ {9y^2-66y+121=0}$$

In the following questions two equations numbered I and II are given. You have to solve both the equations and ____
(A) x>y
(B) x≥y
(C) x<y
(D) x≤y
(E) x=y or the relationship cannot be established
I.\(20x^2 - x - 12 = 0\)
II.\(20y^2 + 27y + 9 = 0\)

In the following questions two equations numbered I and II are given. You have to solve both the equations and ____
I.$$ {7\over \sqrt {x}}+{5\over \sqrt {x}}=\sqrt {x}$$
II.$${y^2 - {12^{5/2}\over \sqrt {y}}}= 0$$
Give answer
(A) x > y
(B) x ≥ y
(C) x < y
(D) x ≤ y
(E) x=y or the relationship cannot be established

Direction: In the following questions two equations numbered I and II are given. You have to solve both the equations and Give answer

Give answer (A) If x > y
Give answer (B) if x ≥ y
Give answer (C) if x<y
Give answer (D) If x ≤ y
Give answer (E) if x=y or the relationship cannot be established.

 I. x² – 7x+ 12=0
II. y²-12y+32 =0

Find the exact value of the following question:

$$ 1280÷{2^3} + 1220÷{2^2}-182=?$$

If 3x+0.04x=0.608, find x.