Geometry Practice Question and Answer
8 Q: D, E, F are the mid - points of the sides BC, CA and AB respectively of a ΔABC. Then the ratio of the areas of DEF and ΔABC is D, E, F.
1404 05e60b222074319409eaef798
5e60b222074319409eaef798- 1$$ {1\over2}$$false
- 2$$ {1\over3}$$false
- 3$$ {1\over4}$$true
- 4$$ {1\over5}$$false
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Answer : 3. "$$ {1\over4}$$"
Q: If the perimeter of an equilateral triangle is 18 cm, then length of each median is
1402 05f1542594cff381d1625f503
5f1542594cff381d1625f503- 1$$ {3\sqrt{2}cm}$$false
- 2$$ {2\sqrt{3}cm}$$false
- 3$$ {3\sqrt{3}cm}$$true
- 4$$ {2\sqrt{2}cm}$$false
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Answer : 3. "$$ {3\sqrt{3}cm}$$"
Q: If two complementary angles are in the ratio of 2:3. find the ratio of square of smaller angle to square of greater?
1394 05ee06078ca41b347ed33138c
5ee06078ca41b347ed33138c- 13:2false
- 29:11false
- 34:5false
- 44:9true
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Answer : 4. "4:9 "
Q: The radius of the circumcircle of a right-angled triangle is 15 cm and the radius of its in circle is 6 cm. Find the sides of the triangle.
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5efeaa61d4461c5b47dce3d8- 130 , 24 , 25false
- 224 , 36 , 20false
- 330 , 40 , 41false
- 418 , 24 , 30true
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Answer : 4. "18 , 24 , 30 "
Q: A solid sphere of diameter 7 cm is cut into two equal halves. What will be the increase (in cm.2) in the total surface area?
1369 160fe2ff8f8986716bdf6937a
60fe2ff8f8986716bdf6937a- 1$$88 cm.^2$$false
- 2$$77 cm.^2$$true
- 3$$56 cm.^2$$false
- 4$$66 cm.^2$$false
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Answer : 2. "$$77 cm.^2$$ "
Q: The centroid of a ∆ABC is G. The area of ∆ABC is 60 cm². The area of ∆GBC is
1356 05dbfb49d17d85f0ae3787012
5dbfb49d17d85f0ae3787012- 130 cm²false
- 240 cm²false
- 310 cm²false
- 420 cm²true
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Answer : 4. "20 cm²"
Q: If the sum of the interior angles of a regular polygon be 1080 °, the number of sides of the polygon is
1345 05ed9e026f528050f91502569
5ed9e026f528050f91502569- 16false
- 28true
- 310false
- 412false
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Answer : 2. "8 "
Q: The diagonals AC and BD of a cyclic quadrilateral ABCD intersect each other at the point P. Then, it is always true that
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5efea615d4461c5b47dcc2d5- 1AP . BP = CP . DPfalse
- 2AP . CD = AB . CPfalse
- 3BP . AB = CD . CPfalse
- 4AP . CP = BP . DPtrue
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