Geometry Practice Question and Answer
8 Q: Let ΔABC ∼ Δ PQR and ar(∆ABC)/ar(∆PQR) =4/25. If AB = 12 cm, BC = 8 cm and AC = 9 cm, then QR is equal to:
1371 06450c27d223d4c08a7d9f0c9
6450c27d223d4c08a7d9f0c9- 120true
- 215false
- 317.5false
- 418false
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Answer : 1. "20"
Q: P is a point outside a circle and is 26 cm away from its centre. A secant PAB drawn form P intersects the circle at points A and B such that PB=32 cm and PA=18cm. The radius of the circle (in cm) is:
1366 06051cbaf528a962d2e3e4820
6051cbaf528a962d2e3e4820- 112false
- 213false
- 310true
- 48false
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Answer : 3. "10"
Q: If △ABC is right angled at B, AB = 12 cm and ∠CAB = 60°, determine the length of BC.
1361 0649d8782a0e013744d4c41a2
649d8782a0e013744d4c41a2- 1$$24\sqrt { 2} \ cm$$false
- 212false
- 3$$12\sqrt { 2} \ cm$$false
- 4$$12\sqrt { 3} \ cm$$true
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Answer : 4. "$$12\sqrt { 3} \ cm$$"
Q: If the circumradius of an equilateral triangle be 10 cm, then the measure of its in-radius is
1358 06332e06931300b7ce4904fad
6332e06931300b7ce4904fad- 15 cm.true
- 210 cm.false
- 320 cm.false
- 415 cm.false
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Answer : 1. "5 cm. "
Q: The diameter of the circle with center O is AB. PQ is the chord that does not intersect AB. Join AP and BQ. If ∠BAP = ∠ABQ, then what will be ABQP?
1357 063109e407c72c0778468d133
63109e407c72c0778468d133- 1cyclic squarefalse
- 2Cyclic Trapeziumtrue
- 3cyclic rhombusfalse
- 4circular rectanglefalse
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Answer : 2. "Cyclic Trapezium"
Q: If the ratio of the heights of two identical triangles is 4: 9, find the ratio of the areas of the two triangles.
1356 05f759216e487e60dcecd3581
5f759216e487e60dcecd3581- 116 : 81true
- 24 : 9false
- 39 :4false
- 481 : 16false
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Answer : 1. "16 : 81"
Q: It is given that ∆ABC ≅ ∆PQR, AB = 5 cm, ∠B = 40°, and ∠A = 80°. Which of the following options is true?
1352 064b5026d2dc867f593f531bd
64b5026d2dc867f593f531bd- 1PQ = 5 cm and ∠R = 60°true
- 2QR = 5 cm and ∠R = 60°false
- 3QR = 5 cm and ∠Q = 60°false
- 4PQ = 5 cm and ∠P = 60°false
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Answer : 1. "PQ = 5 cm and ∠R = 60°"
Q: An isosceles triangle ABC is right angled at B.D is a point inside the triangle ABC. P and Q are the feet of the perpendiculars drawn from D on the side AB and AC respectively of ∆ ABC. If AP = a cm, AQ = b cm and ∠BAD = 15°, sin 75°=
1337 0645ce3a019bbd20a9ac5550c
645ce3a019bbd20a9ac5550c- 1$${2b\over \sqrt {3} a}\ $$false
- 2$${a\over 2b} $$false
- 3$${ \sqrt {3} a\over 2b} $$true
- 4$${ 2b \over \sqrt {3} a} $$false
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