The least number which when divided by 4, 6, 8, 12 and 16 leaves a remainder of 2 in each case is: 

Two numbers are in the ratio 3 : 5 and their HCF is 20. Their LCM is

The LCM of two numbers is 12 times their HCF. The sum of the HCF and the LCM is 403. If one of the number is 93, then the other number is. 

The product of the LCM and HCF of two numbers is 24. The difference of the two numbers is 2. Find the numbers? 

The HCF and LCM of two numbers are 12 and 924 respectively. Then the number of such pairs is: 

The smallest number, which when increased by 5 is divisible by each of 24, 32, 36 and 54, is 

Two numbers are in the ratio 3: 4. If their LCM is 240, the E smaller of the two numbers is: 

What least number must be subtracted from 1936 so that the resulting number when divided by 9, 10 and 15 will leave in each case the same remainder 7?