Percentage Practice Question and Answer

Q:

If X is 20% less than Y, then find the value of $${Y-X\over Y}$$ and $${X\over X-Y }$$

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  • 1
    $${3\over5},-{3\over5}$$
    Correct
    Wrong
  • 2
    $${1\over5},-4$$
    Correct
    Wrong
  • 3
    $$5,-{1\over4}$$
    Correct
    Wrong
  • 4
    $${2\over5},-{5\over2}$$
    Correct
    Wrong
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Answer : 2. "$${1\over5},-4$$"

Q:

A book seller allowed 10 % discount on printed price. He gets 30 % commission from publisher. His profit in percent will be? 

1571 0

  • 1
    20%
    Correct
    Wrong
  • 2
    25%
    Correct
    Wrong
  • 3
    $$ 28{4\over7}\% $$
    Correct
    Wrong
  • 4
    $$ 26{3\over7}\% $$
    Correct
    Wrong
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Answer : 3. "$$ 28{4\over7}\% $$"

Q:

In an examination in which full marks were 500. A got 25% more than C, C got 20% less than D. If A got 360 marks. What percentage of full marks was obtained by D ? 

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  • 1
    72%
    Correct
    Wrong
  • 2
    80%
    Correct
    Wrong
  • 3
    60%
    Correct
    Wrong
  • 4
    50%
    Correct
    Wrong
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Answer : 1. "72% "

Q:

The sum of weights of A and B is 80 kg. 50% of A's weight is $${5\over6}$$ times the weight of B. Find the difference between their weights. 

1569 0

  • 1
    20 kg
    Correct
    Wrong
  • 2
    10 kg
    Correct
    Wrong
  • 3
    25 kg
    Correct
    Wrong
  • 4
    15 kg
    Correct
    Wrong
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Answer : 1. "20 kg"
Explanation :

Let's denote the weight of A as 𝑥x kg and the weight of B as 𝑦y kg.

Given:

  1. 𝑥+𝑦=80x+y=80 (Sum of weights of A and B is 80 kg)
  2. 0.5𝑥=56𝑦0.5x=65y (50% of A's weight is 5665 times the weight of B)

We can solve these two equations to find the values of 𝑥x and 𝑦y, and then calculate the difference between their weights.

From equation 2: 0.5𝑥=56𝑦0.5x=65y Multiply both sides by 2 to get rid of the fraction: 𝑥=56𝑦×2x=65y×2 𝑥=106𝑦x=610y 𝑥=53𝑦x=35y

Now substitute this expression for 𝑥x into equation 1: 53𝑦+𝑦=8035y+y=80 83𝑦=8038y=80 Multiply both sides by 3883: 𝑦=80×38y=80×83 𝑦=30y=30

Now that we have found the weight of B, we can find the weight of A using equation 1: 𝑥+30=80x+30=80 𝑥=80−30x=80−30 𝑥=50x=50

So, the weight of A is 50 kg and the weight of B is 30 kg.

Now, let's find the difference between their weights: Difference=Weight of A−Weight of BDifference=Weight of A−Weight of B Difference=50−30Difference=50−30 Difference=20Difference=20

Therefore, the difference between their weights is 20 kg.

Q:

The price of sugar increases by 15%. By what percentage should the consumption of sugar be decreased so that the expenditure on the purchase of sugar remains the same? [Give your answer correct to 2 decimal places.]

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  • 1
    11.11%
    Correct
    Wrong
  • 2
    12.5%
    Correct
    Wrong
  • 3
    14.16%
    Correct
    Wrong
  • 4
    13.04%
    Correct
    Wrong
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Answer : 4. "13.04%"
Explanation :

To solve this problem, let's denote:

  • Initial price of sugar = P
  • Initial quantity consumed = Q
  • Initial expenditure = PQ

After the price increases by 15%, the new price becomes 1.15P.

To keep the expenditure constant, the new quantity consumed (let's call it Q') can be calculated using the formula:

New expenditure = New price × New quantity

Setting the new expenditure equal to the initial expenditure:

PQ = (1.15P) * Q'

Now, solve for Q':

Q' = PQ / (1.15P)

Simplify:

Q' = Q / 1.15

Now, let's find the percentage decrease in consumption:

Percentage decrease = [(Q - Q') / Q] * 100

Substituting the value of Q':

Percentage decrease = [(Q - (Q / 1.15)) / Q] * 100

Percentage decrease = [(Q * (1 - 1/1.15)) / Q] * 100

Percentage decrease ≈ [(1 - 0.8696) * 100] ≈ 13.04%

Therefore, the consumption of sugar should be decreased by approximately 13.04% to keep the expenditure on the purchase of sugar the same after a 15% increase in price.

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Answer : 2. "60 "

Q:

A man gives 20% of his money to his eldest son, 30% of remaining he gives to his younger son. 10% of the remaining he gives in a school for poor boys still he has Rs.100.80. Find his total sum. 

1544 0

  • 1
    Rs.800
    Correct
    Wrong
  • 2
    Rs.600
    Correct
    Wrong
  • 3
    Rs.400
    Correct
    Wrong
  • 4
    Rs.200
    Correct
    Wrong
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Answer : 4. "Rs.200"

Q:

If $$ {66{2\over 3}}{ \%}$$ of 75 % of one-eighth of a certain number is 179, then $$ {33{1\over 3}}{ \%}$$ of three – fourth of that number is:

1539 0

  • 1
    537
    Correct
    Wrong
  • 2
    787.6
    Correct
    Wrong
  • 3
    859.2
    Correct
    Wrong
  • 4
    716
    Correct
    Wrong
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Answer : 4. "716"

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