Percentage Practice Question and Answer
8 Q: Peter bought an item at 20% discount on its original price. He sold it with 40% increase on the price he bought it. The new sale price is greater than the original price (in percent) by:
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5e86cebfb22d214bc7c92c8c- 110false
- 28false
- 37.5false
- 412true
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Answer : 4. "12"
Q: A man saves 20% of his monthly salary. If an account of dearness of things he is to increase his monthly expenses by 20%, he is only able to save Rs. 200 per month. What is his monthly salary?
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5ed7414122579c3900507cc6- 1Rs.5000true
- 2Rs.25000false
- 3Rs.7500false
- 4Rs.8500false
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Answer : 1. "Rs.5000"
Q: Given that, 10 % of A's income = 15 % of B's income = 20 % of C's income. If sum of their incomes is ₹ 7800, then B's income is :
1285 05ef1528c2c39485d739de4e4
5ef1528c2c39485d739de4e4- 1₹ 3600false
- 2₹ 2400true
- 3₹ 3000false
- 4₹ 1800false
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Answer : 2. "₹ 2400 "
Q: The sum of weights of A and B is 80 kg. 50% of A's weight is $${5\over6}$$ times the weight of B. Find the difference between their weights.
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64ccef6ba919c8488e304799- 120 kgtrue
- 210 kgfalse
- 325 kgfalse
- 415 kgfalse
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Answer : 1. "20 kg"
Explanation :
Let's denote the weight of A as 𝑥x kg and the weight of B as 𝑦y kg.
Given:
- 𝑥+𝑦=80x+y=80 (Sum of weights of A and B is 80 kg)
- 0.5𝑥=56𝑦0.5x=65y (50% of A's weight is 5665 times the weight of B)
We can solve these two equations to find the values of 𝑥x and 𝑦y, and then calculate the difference between their weights.
From equation 2: 0.5𝑥=56𝑦0.5x=65y Multiply both sides by 2 to get rid of the fraction: 𝑥=56𝑦×2x=65y×2 𝑥=106𝑦x=610y 𝑥=53𝑦x=35y
Now substitute this expression for 𝑥x into equation 1: 53𝑦+𝑦=8035y+y=80 83𝑦=8038y=80 Multiply both sides by 3883: 𝑦=80×38y=80×83 𝑦=30y=30
Now that we have found the weight of B, we can find the weight of A using equation 1: 𝑥+30=80x+30=80 𝑥=80−30x=80−30 𝑥=50x=50
So, the weight of A is 50 kg and the weight of B is 30 kg.
Now, let's find the difference between their weights: Difference=Weight of A−Weight of BDifference=Weight of A−Weight of B Difference=50−30Difference=50−30 Difference=20Difference=20
Therefore, the difference between their weights is 20 kg.
Q: In a company, there are 75% skilled workers and remaining ones are unskilled. 80% of skilled workers and 20% of unskilled workers are permanent. If number of temporary workers is 126, then what is the number of total workers?
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60585e6819447609ff02c0c5- 1480false
- 2510false
- 3360true
- 4377false
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Answer : 3. "360"
Q: Two numbers are respectively 20% and 50% of a third number. What percent is the first number of the second?
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5ef45d72d7fe81732198d339- 130%false
- 240%true
- 310%false
- 420%false
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Answer : 2. "40%"
Q: A man gives 20% of his money to his eldest son, 30% of remaining he gives to his younger son. 10% of the remaining he gives in a school for poor boys still he has Rs.100.80. Find his total sum.
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60a213b2b1d2440614b906a9- 1Rs.800false
- 2Rs.600false
- 3Rs.400false
- 4Rs.200true
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Answer : 4. "Rs.200"
Q: In a village, 70 percent of the households have a mobile. 20 percent of the households have TV and 15 percent of the families have both TV and mobile. If the total number of families is 116, then how many families have neither mobile nor TV?
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5f058b93b864a45d9076abed- 132false
- 229true
- 323false
- 424false
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