Percentage Practice Question and Answer
8 Q: A student got 30% marks in an examination and failed because he got 12 marks less. Another student got 40% marks in the same examination and got 18 marks more than the minimum passing marks. Must have marks to pass
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Answer : 3. "102"
Q: In a village, 70 percent of the households have a mobile. 20 percent of the households have TV and 15 percent of the families have both TV and mobile. If the total number of families is 116, then how many families have neither mobile nor TV?
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5f058b93b864a45d9076abed- 132false
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Answer : 2. "29"
Q: Two numbers are respectively 20% and 50% of a third number. What percent is the first number of the second?
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5ef45d72d7fe81732198d339- 130%false
- 240%true
- 310%false
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Answer : 2. "40%"
Q: A man saves 20% of his monthly salary. If an account of dearness of things he is to increase his monthly expenses by 20%, he is only able to save Rs. 200 per month. What is his monthly salary?
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5ed7414122579c3900507cc6- 1Rs.5000true
- 2Rs.25000false
- 3Rs.7500false
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Answer : 1. "Rs.5000"
Q: Given that, 10 % of A's income = 15 % of B's income = 20 % of C's income. If sum of their incomes is ₹ 7800, then B's income is :
1223 05ef1528c2c39485d739de4e4
5ef1528c2c39485d739de4e4- 1₹ 3600false
- 2₹ 2400true
- 3₹ 3000false
- 4₹ 1800false
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Answer : 2. "₹ 2400 "
Q: If price of the table is increased by 25%, then a person can buy 25 table less for Rs 25000. What is the original price (in Rs) of the table?
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Answer : 3. "200"
Q: The sum of weights of A and B is 80 kg. 50% of A's weight is $${5\over6}$$ times the weight of B. Find the difference between their weights.
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64ccef6ba919c8488e304799- 120 kgtrue
- 210 kgfalse
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Answer : 1. "20 kg"
Explanation :
Let's denote the weight of A as 𝑥x kg and the weight of B as 𝑦y kg.
Given:
- 𝑥+𝑦=80x+y=80 (Sum of weights of A and B is 80 kg)
- 0.5𝑥=56𝑦0.5x=65y (50% of A's weight is 5665 times the weight of B)
We can solve these two equations to find the values of 𝑥x and 𝑦y, and then calculate the difference between their weights.
From equation 2: 0.5𝑥=56𝑦0.5x=65y Multiply both sides by 2 to get rid of the fraction: 𝑥=56𝑦×2x=65y×2 𝑥=106𝑦x=610y 𝑥=53𝑦x=35y
Now substitute this expression for 𝑥x into equation 1: 53𝑦+𝑦=8035y+y=80 83𝑦=8038y=80 Multiply both sides by 3883: 𝑦=80×38y=80×83 𝑦=30y=30
Now that we have found the weight of B, we can find the weight of A using equation 1: 𝑥+30=80x+30=80 𝑥=80−30x=80−30 𝑥=50x=50
So, the weight of A is 50 kg and the weight of B is 30 kg.
Now, let's find the difference between their weights: Difference=Weight of A−Weight of BDifference=Weight of A−Weight of B Difference=50−30Difference=50−30 Difference=20Difference=20
Therefore, the difference between their weights is 20 kg.
Q: What is the 15 % of 34?
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