Find the value of $$ {5^{1\over2}-[3^{1\over4}+6-4÷2]}$$

Find the value of given equations

$$\left({216\over1} \right) ^{-{2\over3}}÷\left({27\over1} \right) ^{-{4\over3}}=? $$

$$ \sqrt{0.00004761} $$   equal to

The Value of $$ {\sqrt{6-\sqrt{17-2\sqrt{72}}}}$$ is closest to:

If $$ {0.7\over 1-6c}=-0.2$$ then what is the value of c.

3x² = 36 then what is the value of x?

Direction: What approximate value will come in place of the question mark (?) in the following question? (You are not expected to calculate the exact value)

(31.99)^1/5 × (80.78)^1/4 × (5.15)² = ? × 2.29

The value of x in the given equation
$$ {23 ^2 + \sqrt{x}=625}$$