The value of x in the given equation
$$ {23 ^2 + \sqrt{x}=625}$$

3x² = 36 then what is the value of x?

If  $$\sqrt{2}=1.414$$, the value of $${ \sqrt{2}-1\over\sqrt{2}+1}$$  is nearest to 

The smallest number that must be subtracted from 1000 to make the resulting number a perfect square is 

25.6% of 250 +√ ? = 119

On simplification of   $$ {(2.664)^2-(2.356)^2\over0.288}$$

Simplify  $$ ^{3}\sqrt{-2197} × ^{3}\sqrt{{-125}} \ ÷ ^{3}\sqrt{27\over512}$$.

  $$25\% \ of (50\% \ of \ 30\% \ of \ 150)\over 40\% of \ 2250$$ is equal to: