Simplify the following expression.

 25-(4÷2)+11.5+9.5

If $$ {(x-2)^{2}+(y-{1\over2})^{2}}=0$$, then the value of $$ {x\over y}$$ is

25.6% of 250 +√ ? = 119

Solve: 12–[26–{2+5×(6–3)}]

Direction : What should come in place of the question (?) in the following question.

$$ {\sqrt{441}}+ {(71)^{2}} -{(?)^{2}}=2707 $$

If p = 8.15, q = 9.06 and r = −17.21, then the value of p³+q³+r³-3pqr

Find the value of $$ (2 {1\over6}+1 {13\over18}-{1\over6}) × {16÷4}$$

$$ {\sqrt{5929}}+\sqrt{8464}=(?)^{2}$$