Evaluate the following.

sin 25° sin 65° – cos 25° cos 65°.

If 2sinθ+cosθ= $${7\over3}$$ then the value of (tan²θ-sec²θ) is

$${sin^2θ\over cosθ(1+cosθ)}+{1+cosθ\over cosθ} =?$$

(sec A + tan A – 1) (sec A – tan A+1) =?

$$(1+tan θ+secθ)(1+cotθ-cosecθ)\over (sec θ+tan θ)(1-sin θ) $$ is equal to :

Sin (45 + θ) – Cos (45 – θ) is:

If sin²a = cos³a then the value of cot⁶ a – cot²a? 

(sinθ+cosecθ)²+(cos θ+ sec θ)²=?