Solve it $$ {sin \ θ\over 1+cos\ θ}+{1+cosθ\over sin\ θ}=?$$

If sin²a = cos³a then the value of cot⁶ a – cot²a? 

Evaluate the following.

sin 25° sin 65° – cos 25° cos 65°.

if 2sinθ + 2sin²θ = 2, then the value of 2 cos⁴θ + 2cos²θ is:

The value of $$ {(cos {\ 9°}+sin{\ 81°}})({sec {\ {9°}+cosec{\ 81°}}})\over{sin{\ 56°}sec{\ 34° }}+ {cos{\ 25°}cosec{\ 65°}}$$ is:

$${1+sinθ}\over cosθ $$ is equal to which of the following (where $$θ ≠ {π\over2} $$

Simplify $$ ({Sinθ\over{1+cosθ}}+{1+cosθ\over sinθ})({1\over (tanθ+cotθ)})$$

In △ABC, right angle at B, if   $$tan\ A={1\over 2}$$, then the value of $$sinA(cosC+cosA)\over cosC(sin C-sinA)$$ is :