GATE Practice Question and Answer
8Q: Which of the following is a Heterogeneous Mixture? 2271 05b5cc6b5e4d2b4197774d50b
5b5cc6b5e4d2b4197774d50b- 1Airfalse
- 2Table saltfalse
- 3Sodatrue
- 4Brassfalse
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Answer : 3. "Soda"
Explanation :
Answer: C) Soda Explanation: Here Soda is a Heterogenous Mixture. A Heterogeneous Mixture is a mixture having a non-uniform composition i.e, the mixture contains components in different phases. Using various means, the parts in the mixture can be separated from one another.
Q: In how many ways the word 'SCOOTY' can be arranged such that 'S' and 'Y' are always at two ends? 2271 05b5cc619e4d2b4197774b705
5b5cc619e4d2b4197774b705- 1720false
- 2360false
- 3120false
- 424true
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Answer : 4. "24"
Explanation :
Answer: D) 24 Explanation: Given word is SCOOTY ATQ, Except S & Y number of letters are 4(C 2O's T) Hence, required number of arrangements = 4!/2! x 2! = 4! = 4 x 3 x 2 = 24 ways.
Q: Which of the following is not an aerosol? 2271 05b5cc699e4d2b4197774c691
5b5cc699e4d2b4197774c691- 1mudtrue
- 2dustfalse
- 3smokefalse
- 4fogfalse
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Answer : 1. "mud"
Explanation :
Answer: A) mud Explanation: Among the given options, mud is not an aerosol. An aerosol is a suspension of fine solid particles or liquid droplets, in the air or another gas. Aerosols can be natural or anthropogenic. Examples of natural aerosols are fog, dust, forest exudates and geyser steam. Examples of anthropogenic aerosols are haze, particulate air pollutants, and smoke.
Q: Rs. 69 were divided among 115 family members so that each lady gets 50 paise less than each gentleman, and each gentleman received twice the paise as each lady received. Find the number of gentlemen in the family? 2268 05b5cc67be4d2b4197774c1f0
5b5cc67be4d2b4197774c1f0- 123true
- 292false
- 348false
- 452false
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Answer : 1. "23"
Explanation :
Answer: A) 23 Explanation: Total number of female members = 115 Let the number of males = x Number of females = y => x + y = 115 ......(1) According to the given data, x + y(0.50) = 69 ......(2) From (1) & (2), we get 0.5y = 46 => y = 46 x 2 = 92 => x = 115 - 92 = 23 Hence, required number of gentlemen in the family = x = 23.
Q: In a 40 litre mixture of alcohol & water, the ratio of alcohol and water is 5 : 3. If 20% of this mixture is taken out and the same amount of water is added then what will be the ratio of alcohol and water in final mixture? 2268 05b5cc6b2e4d2b4197774d3be
5b5cc6b2e4d2b4197774d3be- 11:1true
- 22:1false
- 33:1false
- 41:2false
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Answer : 1. "1:1"
Explanation :
Answer: A) 1:1 Explanation: Quantity of alohol in the mixture = 40 x 5/8 = 25 lit Quantity of water = 40 - 25 = 15 lit According to question, Required ratio = 20 - 40 x 20100 x 5815 - 40 x 20100 x 38 + 40 x 20100 = 2015 - 3 + 8 = 1 : 1
Q: Rushi and Arun are two business partners. They invest their capital in the ratio 7 : 9. After 6 months, a third person Ram joins them with a capital of two third of that of Arun. After a year, profit share of Rushi was Rs. 5600, then find total profit? 2266 05b5cc619e4d2b4197774b70f
5b5cc619e4d2b4197774b70f- 126,250false
- 219,200false
- 318,650,false
- 415,200true
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Answer : 4. "15,200"
Explanation :
Answer: D) 15,200 Explanation: Ratio of investment of all the three members = (7 x 12) : (9 x 12) : (2/3 x 9 x 6) = 7 : 9 : 3 Given Rushi's one year profit = Rs. 5600 => Let the total profit = Rs. P Then, P x 7/19 = 5600 Total profit P = 19 x 5600/7 = Rs. 15,200.
Q: An intelligent boy is doing a jigsaw with 275 pieces. Each day that he fits pieces together there are fewer pieces left, and it is reasonable to assume that he fits more pieces each day because the number left to sort out diminishes progressively. Hence he is able to fit an extra piece as each day goes by. On the first day he fits 20 pieces. How many days does it take for him to complete the puzzle ? 2264 05b5cc71ee4d2b4197774f59a
5b5cc71ee4d2b4197774f59a- 111 daystrue
- 215 daysfalse
- 313 daysfalse
- 416 daysfalse
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Answer : 1. "11 days"
Explanation :
Answer: A) 11 days Explanation: Let 'n' number of days it take to complete. we know that sum of n number= n/2[2a+(n-1)d]where a=20,d=1;n/2[2x20+(n-1)1]=275n[n+39]=550n2 + 39n - 550 = 0 n2+ 50n - 11n - 550 = 0(n-11) (n-50) = 0n-11 = 0;n = 11(Days).
Q: A man saves 20% of his monthly salary. If an account of dearness of things he is to increase his monthly expenses by 15%, he is only able to save Rs. 400 per month. What is his monthly salary ? 2255 05b5cc6e1e4d2b4197774ebf2
5b5cc6e1e4d2b4197774ebf2- 1Rs. 6000false
- 2Rs. 4500false
- 3Rs. 5000true
- 4Rs. 6500false
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Answer : 3. "Rs. 5000"
Explanation :
Answer: C) Rs. 5000 Explanation: Income = Rs. 100 Expenditure = Rs. 80 Savings = Rs. 20 Present Expenditure 80x(15/100) = Rs. 12 = 80 + 12 = Rs. 92 Present Savings = 100 – 92 = Rs. 8 100 ------ 8? --------- 400 => 5000 His salary = Rs. 5000