Answer: D) 84.8 Explanation: Let 'M' be the maximum marks in the examination. Therefore, Madhu got 32% of M = 32M/100 = 0.32MAnd Kumar got 42% of M = 42M/100 = 0.42M.In terms of the maximum marks Kumar got 0.42M - 0.32M = 0.1M more than Madhu. ---- (1) The problem however, states that Kumar got 16 marks more than the cut-off mark and Madhu got 8 marks less than the cut-off mark. Therefore, Kumar has got 16 + 8 = 24 marks more than Madhu. ---- (2) Now, Equating (1) and (2), we get0.1M = 24 => M = 24/0.1 = 240'M' is the maximum mark and is equal to 240 marks.We know that Madhu got 32% of the maximum marks.Therefore, Madhu got 32 x 240/100 = 76.8 marks.We also know that Madhu got 8 marks less than the cut-off marks. Therefore, the cut-off marks will be 8 marks more than what Madhu got = 76.8 + 8 = 84.8.

Answer: B) 168 Explanation: we can select the 5 member team out of the 8 in 8C5 ways = 56 ways. The captain can be selected from amongst the remaining 3 players in 3 ways. Therefore, total ways the selection of 5 players and a captain can be made = 56x3 = 168 ways.   (or)   Alternatively, A team of 6 members has to be selected from the 8 players. This can be done in 8C6 or 28 ways. Now, the captain can be selected from these 6 players in 6 ways. Therefore, total ways the selection can be made is 28x6 = 168 ways.

Answer: A) Rs. 80 Explanation: The servant worked for 9 days instead of 12 days, he should receive 9/12 of his total payment Let the price of 1 shirt be Rs. S  i.e., 3/4 (400 + S). However, the question states that the servant receive Rs. 280 + S where S is the price of the shirt. By equating the two equations we get 3/4 (400 + S) = 280 + S. Therefore, Price of the shirt S = Rs. 80.

Answer: D) 2048 Explanation: Given 11 questions of type True or False   Then, Each of these questions can be answered in 2 ways (True or false)   Therefore, no. of ways of answering 11 questions = 211 = 2048 ways.

Answer: B) Friday Explanation: On 31st December, 2005 it was Monday. Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days. On 31st December 2009, it was Thursday. Thus, on 1st Jan, 2010 it is Friday.

Answer: B) 137 Explanation: This can be done as,   (11 × 92)  -  (5 × 89)  -  (5 × 86)    = 1012- 445 - 430 = 137

Answer: A) 24 Explanation: Given that the month begins on a Friday and has 31 days   Sundays = 3rd, 10th, 17th, 24th, 31st=> Total Sundays = 5   Every second & fourth Saturday is holiday. 2nd & 4th Saturday in every month = 2   Total days in the month = 31   Total working days = 31 - (5 + 2) = 24 days.

Answer: C) 48/5 days Explanation: Amount of work K can do in 1 day = 1/16 Amount of work L can do in 1 day = 1/12 Amount of work K, L and M can together do in 1 day = 1/4 Amount of work M can do in 1 day = 1/4 - (1/16 + 1/12) = 3/16 – 1/12 = 5/48 => Hence M can do the job on 48/5 days = 9 (3/5) days