Quantitative Aptitude Practice Question and Answer
8Q: A flagstaff 17.5 m high casts a shadow of length 40.25 m. What will be the height of a building, which casts a shadow of length 28.75 m under similar conditions ? 1697 15b5cc6f4e4d2b4197774f013
5b5cc6f4e4d2b4197774f013- 114 cmfalse
- 213.5 cmfalse
- 312.5 cmtrue
- 411.4 cmfalse
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Answer : 3. "12.5 cm"
Explanation :
Answer: C) 12.5 cm Explanation: Let the required height of the building be x meter More shadow length, More height(direct proportion) Hence we can write as (shadow length) 40.25 : 28.75 :: 17.5 : x⇒ 40.25 × x = 28.75 × 17.5⇒ x = 28.75 × 17.5/40.25= 2875 × 175/40250= 2875 × 7/1610= 2875/230= 575/46= 12.5 cm
Q: A student multiplied a number by 2/5 instead of 5/2. What is the percentage error in evaluation ? 1695 05b5cc6c0e4d2b4197774dae4
5b5cc6c0e4d2b4197774dae4- 152%false
- 264%false
- 384%true
- 477%false
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Answer : 3. "84%"
Explanation :
Answer: C) 84% Explanation: Let the number be 'x' Then, according to the given data, 52x-25x52xx100 = 2125x100 = 84%
Q: At what time, in minutes, between 3 o'clock and 4 o'clock, both the needles will coincide each other? A. 5111 B. 15415 C. 16411 D. 4415 1694 05b5cc77ae4d2b41977750133
5b5cc77ae4d2b41977750133- 1Option Afalse
- 2Option Bfalse
- 3Option Ctrue
- 4Option Dfalse
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Answer : 3. "Option C"
Explanation :
Answer: C) Option C Explanation: At 3 o'clock, the minute hand is 15 min. spaces apart from the hour hand. To be coincident, it must gain 15 min. spaces. 55 min. are gained in 60 min. Then 15 min spaces are gained in = 6055×15 min. Therefore, The hands are coincident at 16411 min. past 3 o'clock.
Q: The area of triangle is half the area of square. The perimeter of the square is 224 cm. What is the area of triangle?
1694 05d4aa1bf11160f2052371576
5d4aa1bf11160f2052371576- 11856 cm2false
- 21658 cm2false
- 31558 cm2false
- 41586 cm2false
- 5None of thesetrue
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Answer : 5. "None of these"
Explanation :
given 4a=224,
a=56, so that Area of square is=a2=56*56
so that Area of Triangle is a2/2=1568
Q: Square units 13 by 9 of an office area is 1693 05b5cc662e4d2b4197774be89
5b5cc662e4d2b4197774be89- 197false
- 2117true
- 3107false
- 4127false
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Answer : 2. "117"
Explanation :
Answer: B) 117 Explanation: Square units 13 by 9 of an office means office of length 13 units and breadth 9 units. Now its area is 13x 9 = 117 square units or units square.
Q: A can do a piece of work in 30 days. He works at it for 6 days and then B finishes it in 18 days. In what time can A and B together it ? 1693 05b5cc6d8e4d2b4197774e755
5b5cc6d8e4d2b4197774e755- 114 1/2 daysfalse
- 211 daysfalse
- 313 1/4 daysfalse
- 412 6/7 daystrue
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Answer : 4. "12 6/7 days"
Explanation :
Answer: D) 12 6/7 days Explanation: Let 'B' alone can do the work in 'x' days 6/30 + 18/x = 1 => x = 22.5 1/30 + 1/22.5 = 7/90 => 90/7 = 12 6/7 days
Q: The profit earned by selling an article for Rs.753 is equal to the loss incurred when the same article is sold for Rs.455.What should be the sale price for making 50% profit ? 1692 05b5cc783e4d2b41977750205
5b5cc783e4d2b41977750205- 1Rs.855false
- 2Rs.955false
- 3Rs.906true
- 4Rs.896false
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Answer : 3. "Rs.906"
Explanation :
Answer: C) Rs.906 Explanation: Let C.P =Rs. x Then as given, (753 - x ) = (x - 455) =>2x = 1208 => x = 604 There fore S.P= 150% of 604 => Rs. 150100×604= Rs.906
Q: Swetha when get married to Sudeer her age was 3/4 th of her husband's age. After 12 years her age became 5/6 th of her husband's age. Then what's the age of Swetha when she got married ? 1692 05b5cc71be4d2b4197774f55e
5b5cc71be4d2b4197774f55e- 118 yearstrue
- 221 yearsfalse
- 323 yearsfalse
- 417 yearsfalse
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Answer : 1. "18 years"
Explanation :
Answer: A) 18 years Explanation: At the time of marriage, let Sudeer's age be 4x, then Swetha's age is 3x12 years after:Age of Sudeer = 4x+12Age of Swetha = 3x+12Now the equation is 3x+12=5/6(4x+12)Solving equation we get x=6Hence Swetha got married at the age of 18.

