Quantitative Aptitude Practice Question and Answer
8Q: The length of a rectangle is 10 cm more than the breadth. Find the diagonal length of rectangle if perimeter is 44 cm ? 1177 05b5cc6cae4d2b4197774e06d
5b5cc6cae4d2b4197774e06d- 112.50 cmfalse
- 214.21 cmfalse
- 315.98 cmfalse
- 417.08 cmtrue
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Answer : 4. "17.08 cm"
Explanation :
Answer: D) 17.08 cm Explanation: Let the length of the rectangle = L cm Then the breadth of the rectangle = (L - 10) cm Perimeter of a rectangle = 2(L + B) cm => 44 = 2(L + L - 10) => 44 = 4L - 20 => 4L = 64 => L = 16 cm => B = L - 10 = 6 cm Diagonal = L2+B2 = 162+62 = 17.08 cm
Q: Mary is 12 years younger to Pinky. After 3 years, the ratio of their ages will be 5:8. If the present age of Sam is the sum of ages of Mary and Pinky, then what was the age of Sam 15 years back ? 1901 05b5cc6cae4d2b4197774e068
5b5cc6cae4d2b4197774e068- 131 yearstrue
- 237 yearsfalse
- 346 yearsfalse
- 429 yearsfalse
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Answer : 1. "31 years"
Explanation :
Answer: A) 31 years Explanation: Let the present age of Pinky be x years Then the age of Mary is x - 12 years After 3 years, Ratio of MaryPinky = x - 9x + 3 = 58 8x - 72 = 5x +15 => 3x = 87 => x = 29 => Age of Pinky = 29 years => Age of Mary = 29 - 12 = 17 years Present age of Sam = 29 + 17 = 46 Before 15 years Sam age = 46 - 15 = 31 years.
Q: Munna and Chinna are partners in a firm out of which Munna is sleeping partner and Chinna is working partner. Munna invests Rs. 1,40,000 and Chinna invests Rs. 80,000. Chinna receives 14.5% of profit for managing the business and the rest is shared between both in ratio of their investments. Munna's share in the profit of Rs. 19600 is ? 2046 05b5cc6cae4d2b4197774e04a
5b5cc6cae4d2b4197774e04a- 1Rs. 9580.25false
- 2Rs. 10600false
- 3Rs. 10664.15true
- 4Rs. 11060.48false
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Answer : 3. "Rs. 10664.15"
Explanation :
Answer: C) Rs. 10664.15 Explanation: Profit received by Chinna as working partner = 14.5% of Rs. 19600 = 14.5x19600/100 = Rs. 2842 Balance in profit = 19600-2842 = Rs. 16758 Ratio of investment of Chinna & Munna = 80,000 : 1,40,000 = 4 : 7 Hence share of Chinna in investment = 4x16758/100 = Rs. 6093.85 Therefore, Share of Munna = 19600 - 2842 - 6093.85 = Rs. 10664.15
Q: In how many ways the letters of the word OLIVER be arranged so that the vowels in the word always occur in the dictionary order as we move from left to right ? 1716 05b5cc6cae4d2b4197774e045
5b5cc6cae4d2b4197774e045- 1186false
- 2144false
- 3136false
- 4120true
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Answer : 4. "120"
Explanation :
Answer: D) 120 Explanation: In given word OLIVER there are 3 vowels E, I & O. These can be arranged in only one way as dictionary order E, I & O. There are 6 letters in thegiven word. First arrange 3 vowels. This can be done in 6C3 ways and that too in only one way.(dictionary order E, I & O) Remaining 3 letters can be placed in 3 places = 3! ways Total number of possible ways of arranging letters of OLIVER = 3! x C36 ways = 6x5x4 = 120 ways.
Q: Watson bought a book for Rs. 240 and sold to Johny at a profit of 50%. Johny wants to sell this book to Shekar so that he earns a profit of 25%. But Shekar is adamant at buying this book at a discount of 10%. What marked price should Johny quote to Shekar so as to achieve desired profit ? 1455 05b5cc6cae4d2b4197774e040
5b5cc6cae4d2b4197774e040- 1Rs. 450false
- 2Rs. 360false
- 3Rs. 415false
- 4Rs. 500true
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Answer : 4. "Rs. 500"
Explanation :
Answer: D) Rs. 500 Explanation: Watson bought the book for Rs. 240 and sold to Johny at a profit of 50%. S.P = C.P(1 + P%/100) => S.P for Watson = C.P for Johny = 240(1 + 50/100) = 240 x 1.5 = Rs. 360 Let Johny quoted the marked price of the book as Rs. M We know, SP = M.P(1 - Discount(%)/100) Here discount = 10% to Shekar, S.P for Johny = M(1 - 10/100) = 0.9M But Johny want to earn 25% profit, => S.P = C.P(1 + P%/100) => 0.9M = 360(1 + 25/100) => M = (360x1.25)/0.9 => M = Rs. 500 Therefore, Johny should quote Rs. 500 as the marked price of the book to get 25% profit and allowing 10% discount to Shekar.
Q: The total simple interest earned on a sum of money increases by Rs. 600 when the rate of interest increases by 2% per annum. If the investment was made for 5 years, find the sum of money that was invested ? 1564 05b5cc6cae4d2b4197774e03b
5b5cc6cae4d2b4197774e03b- 1Rs. 6000true
- 2Rs. 5550false
- 3Rs. 7500false
- 4Rs. 6580false
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Answer : 1. "Rs. 6000"
Explanation :
Answer: A) Rs. 6000 Explanation: Let the sum invested be Rs. P Let the rate of interest be R% per annum => Interest earned for 5 years = (P x 5 x R/100) = PR/20 Now, given that the interest earned increased by Rs. 600 if the Rate increased to (R+2)% => SI = (P x 5 x (R+2))/100 = PR/20 + 10P/100 Hence, PR/20 + 10P/100 = PR/20 + 600 => P = 6000 Therefore, the sum invested is Rs. 6000
Q: Simplify the following : 373+353+283-3x37x35x28372+352+282-37x35-35x28-37x28 ? 2826 05b5cc6cae4d2b4197774dffc
5b5cc6cae4d2b4197774dffc- 1100true
- 21false
- 34false
- 40false
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Answer : 1. "100"
Explanation :
Answer: A) 100 Explanation: Given 373+353+283-3x37x35x28372+352+282-37x35-35x28-37x28 It is in the form of a3+b3+c3-3abca2+b2+c2-ab-bc-ca= a + b + c Here a = 37, b = 35 & c = 28 => a + b + c = 37 + 35 + 28 = 100 Therefore, = 100
Q: Find the value of 1.21x0.91.1x0.11? 1139 05b5cc6cae4d2b4197774e001
5b5cc6cae4d2b4197774e001- 10false
- 21false
- 33true
- 45false
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Answer : 3. "3"
Explanation :
Answer: C) 3 Explanation: Given 1.21x0.91.1x0.11 = 1.21x100x0.9x101.1x10x0.11x100 = 9 = 3.

