Quantitative Aptitude Practice Question and Answer
8Q: 30% of 500 rupees is? 1872 05b5cc690e4d2b4197774c460
5b5cc690e4d2b4197774c460- 1Rs. 180false
- 2Rs. 150true
- 3Rs. 120false
- 4Rs. 240false
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Answer : 2. "Rs. 150"
Explanation :
Answer: B) Rs. 150 Explanation: Given 30% of 500 = 30100 x 500= 30 x 5= 150 Hence, 30% of Rs. 500 = Rs. 150.
Q: A jogger running at 9 kmph alongside a railway track is 240 metres ahead of the engine of a 120 metre long train running at 45 kmph in the same direction. In how much time will the train pass the jogger ? 1871 05b5cc6dee4d2b4197774ea5b
5b5cc6dee4d2b4197774ea5b- 110 secfalse
- 248 secfalse
- 336 sectrue
- 456 secfalse
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Answer : 3. "36 sec"
Explanation :
Answer: C) 36 sec Explanation: Given speed of jogger = 9 kmph Speed of train = 45 kmphAs they are in same direction, Relative speed = 45 - 9 = 36 kmph = 36x5/18 = 10 m/sDistance = 240 + 120 = 360 mts Time = distance/speed = 360/10 = 36 sec.
Q: A drink vendor has 368 liters of Maaza, 80 liters of Pepsi and 144 liters of Sprite. He wants to pack them in cans, so that each can contains the same number of liters of a drink, and doesn't want to mix any two drinks in a can. What is the least number of cans required ? 1870 05b5cc6e1e4d2b4197774ebc5
5b5cc6e1e4d2b4197774ebc5- 147false
- 246false
- 337true
- 435false
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Answer : 3. "37"
Explanation :
Answer: C) 37 Explanation: The number of liters in each can = HCF of 80, 144 and 368 = 16 liters.Number of cans of Maaza = 368/16 = 23Number of cans of Pepsi = 80/16 = 5Number of cans of Sprite = 144/16 = 9The total number of cans required = 23 + 5 + 9 = 37 cans.
Q: The profit earned by selling an article for Rs.753 is equal to the loss incurred when the same article is sold for Rs.455.What should be the sale price for making 50% profit ? 1868 05b5cc783e4d2b41977750205
5b5cc783e4d2b41977750205- 1Rs.855false
- 2Rs.955false
- 3Rs.906true
- 4Rs.896false
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Answer : 3. "Rs.906"
Explanation :
Answer: C) Rs.906 Explanation: Let C.P =Rs. x Then as given, (753 - x ) = (x - 455) =>2x = 1208 => x = 604 There fore S.P= 150% of 604 => Rs. 150100×604= Rs.906
Q: A man covered a certain distance at some speed. Had he moved 3 kmph faster, he would have taken 40 minutes less. If he had moved 2 kmph slower, he would have taken 40 minutes more. The distance (in km) is 1867 05b5cc6d9e4d2b4197774e816
5b5cc6d9e4d2b4197774e816- 130false
- 236false
- 340true
- 442false
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Answer : 3. "40"
Explanation :
Answer: C) 40 Explanation: Let distance = x km and usual rate = y kmph.Then, x/y - x/(y+3) = 40/60 --> 2y (y+3) = 9x ----- (i)Also, x/(y-2) - x/y = 40/60 --> y(y-2) = 3x -------- (ii)On dividing (i) by (ii), we get: x = 40 km.
Q: A Bus is running at 9/10 of its own speed reached a place in 22 hours. How much time could be saved if the bus would run at its own speed ? 1867 05b5cc6dde4d2b4197774ea00
5b5cc6dde4d2b4197774ea00- 11.5 hrsfalse
- 21.7 hrsfalse
- 32.2 hrstrue
- 43.5 hrsfalse
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Answer : 3. "2.2 hrs"
Explanation :
Answer: C) 2.2 hrs Explanation: Let the original Speed be "s" kmphAnd the usual time be "t" hrsGiven that if the bus is running at 9s/10 kmph the time is 22 hrs=> [9s/10] x 22 = t x s=> 99/5 = t => t = 19.8 hrs Hence, if bus runs at its own speed, the time saved = 22 - 19.8 = 2.2 hrs.
Q: The length, breadth and height of a room are in the ratio 7:3:1. If the breadth and height are doubled while the length is halved, then by what percent the total area of the 4 walls of the room will be increased ? 1867 05b5cc6c6e4d2b4197774de18
5b5cc6c6e4d2b4197774de18- 190%true
- 288%false
- 385%false
- 484%false
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Answer : 1. "90%"
Explanation :
Answer: A) 90% Explanation: Let length, breadth and height of the room be 7, 3, 1 unit respectively. Area of walls = 2(l+b)xh = 2(7+3)x1 = 20 sq. unit. Now, length, breadth and height of room will become 3.5, 6 and 2 respectively. Area of walls = 2(l+b)xh = 2(3.5+6)x2 = 38 sq. unit. % Increase in the area of walls = (38-20)x100/20 = 90%.
Q: 50 men can build a tank in 40days, but though they begin the work together, 5 men quit every ten days. The time needed to build the tank is ? 1867 05b5cc76fe4d2b4197774ff71
5b5cc76fe4d2b4197774ff71- 150 daystrue
- 248 daysfalse
- 347.5 daysfalse
- 449 daysfalse
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Answer : 1. "50 days"
Explanation :
Answer: A) 50 days Explanation: 50 men can build a tank in 40 days Assume 1 man does 1 unit of work in 1 day Then the total work is 50×40 = 2000 units 50 men work in the first 10 days and completes 50×10 = 500 units of work 45 men work in the next 10 days and completes 45×10 = 450 units of work 40 men work in the next 10 days and completes 40×10 = 400 units of work 35 men work in the next 10 days and completes 35×10 = 350 units of work So far 500 + 450 + 400 + 350 = 1700 units of work is completed and Remaining work is 2000 - 1700 = 300 units 30 men work in the next 10 days. In each day, they does 30 units of work. Therefore, additional days required = 300/30 =10 Thus, total 10+10+10+10+10 = 50 days required.