Quantitative Aptitude Practice Question and Answer

Q: If the average height of boys in a hall is 180 cm and that of girls is 150 cm. If the average height of the gathering is 165 cm, then find the number of girls present in the hall if the number of boys present in the hall are 78 ? 1622 0

  • 1
    56
    Correct
    Wrong
  • 2
    64
    Correct
    Wrong
  • 3
    87
    Correct
    Wrong
  • 4
    78
    Correct
    Wrong
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Answer : 4. "78"
Explanation :

Answer: D) 78 Explanation: Using Trial and error method, we get the number of girls in the hall = 78

Q: Rajeev's age is four more than the age of Shilpa. The age of Shilpa can be obtained by subtracting four times her age 4 years ago from the four times her age after 4 years. What was Rajeev's age before 4 years ? 1384 0

  • 1
    36 years
    Correct
    Wrong
  • 2
    28 years
    Correct
    Wrong
  • 3
    32 years
    Correct
    Wrong
  • 4
    40 years
    Correct
    Wrong
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Answer : 3. "32 years"
Explanation :

Answer: C) 32 years Explanation: Let Shilpa's present age is p years According to question, p = 4(x+4) – 4(x–4) p = 4x+16 – 4x+16 p = 32 Shilpa's present age = 32 years Rajeev is four years older than Shilpa => Shilpa's present age = Rajeev's age 4 years before. => Rajeev's age 4 years before = 32 years.

Q: A man purchases two articles, on selling one at loss of 20% while the other at a profit of 25%, he gains the overall profit of 5% than find the ratio of their selling price ? 1307 0

  • 1
    8 : 62.5
    Correct
    Wrong
  • 2
    55 : 8
    Correct
    Wrong
  • 3
    8 : 65
    Correct
    Wrong
  • 4
    64.4 : 9
    Correct
    Wrong
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Answer : 1. "8 : 62.5"
Explanation :

Answer: A) 8 : 62.5 Explanation:                       Article I                   Article II                         -20                         25%                                        5%                         20%                       25%                                                4              :              5 Now, Selling of first article = (4-20%) = 0.8 Selling of second article = (5+25%) =  6.25 Therefore the ratio of selling price = 8 : 62.5

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Answer : 2. "20%"
Explanation :

Answer: B) 20% Explanation: Let the Cost of Production of the article = 100 Then, Labour Cost = 20 Raw Material = 10 Other Expenditure = 100 - 10 – 20 = 70 Selling Price of the article  = 120 After increasing Labour and Raw material cost by 40% & 20% respectively, New Labour cost = 28 New Raw material cost = 12 New Cost of Production = 70 + 28 + 12 = 110 Then, New SP = 110% of 120 = 120 x 110/100 = 132 => New Gain = 132 - 110 = 22 => New Profit % = 22 x 100/110 = 20%

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Answer : 3. "109"
Explanation :

Answer: C) 109 Explanation: From given data, R : M = 5 : 7 M : A = 5 : 7 R : M : A = 25 : 35 : 49 25 + 35 + 49 = 109

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Answer : 1. "99"
Explanation :

Answer: A) 99 Explanation: Let, Distance between A and B = d   Distance travelled by P while it meets Q = d + 11   Distance travelled by Q while it meets P = d – 11   Distance travelled by Q while it meets R = d + 9   Distance travelled by R while it meets Q = d – 9   Here the ratio of speeds of P & Q => SP : SQ = d + 11 : d – 11   The ratio of speeds of Q & R => SQ : SR = d + 9 : d – 9   But given Ratio of speeds of P & R => P : R = 3 : 2  SPSR = SPSQxSQSR = d+11d+9d-11d-9   => d+11d+9d-11d-9 = 3/2   =>  d = 1, 99   => d = 99 satisfies.   Therefore, Distance between A and B = 99

Q: In what ratio must a merchant mix two varieties of oils worth Rs. 60/kg and Rs. 65/kg, so that by selling the mixture at Rs. 68.20/kg, he may gain 10% ? 1377 0

  • 1
    2:3
    Correct
    Wrong
  • 2
    4:3
    Correct
    Wrong
  • 3
    3:4
    Correct
    Wrong
  • 4
    3:2
    Correct
    Wrong
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Answer : 4. "3:2"
Explanation :

Answer: D) 3:2 Explanation: Let he mixes the oils in the ratio = x : y Then, the cost price of the oils = 60x + 65y Given selling price = Rs. 68.20 => Selling price = 68.20(x+y) Given profit = 10% = SP - CP => 10/100 (60x + 65y) = 68.20(x+y)-(60x + 65y) => 6x + 6.5y = 8.20x + 3.20y =>2.2x = 3.3y => x : y = 3 : 2

Q: The average age of a couple and their son was 40 years, the son got married and a child was born just two years after their marriage. When child turned to 10 years, then the average age of the family becomes 38 years. What was the age of the daughter in law at the time of marriage ? 2906 0

  • 1
    12 years
    Correct
    Wrong
  • 2
    10 years
    Correct
    Wrong
  • 3
    14 years
    Correct
    Wrong
  • 4
    13 years
    Correct
    Wrong
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Answer : 1. "12 years"
Explanation :

Answer: A) 12 years Explanation: Given the average age of couple and their son = 40 => Sum of age (H +W +S) = 40×3 Let the age of daughter in law at the time of marriage = D years Now after 10 years, (H + S +W) + 3×12 + D +12 + 10 = 38×5 178 + D = 190 D = 190 -178 = 12 years

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