Quantitative Aptitude Practice Question and Answer
8Q: Out of seven consonants and 4 vowels, how many words of 3 consonants and 2 vowels can be formed ? 2024 05b5cc774e4d2b41977750007
5b5cc774e4d2b41977750007- 125200true
- 225000false
- 325225false
- 424752false
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Answer : 1. "25200"
Explanation :
Answer: A) 25200 Explanation: Number of ways of selecting (3 consonants out of 7) and (2 vowels out of 4) =( C37×C24 ) = 210. Number of groups, each having 3 consonants and 2 vowels =210 Each group contains 5 letters. Number of ways of arranging 5 letters among themselves = 5! = 120. Required number of words = (210 x 120) = 25200.
Q: Four person A, B, C and D. The sum of their present age is 176. Four years ago ratio of their age was 11: 9 : 6 : 14, then find who is eldest and youngest among them ? 2023 05b5cc6c1e4d2b4197774db82
5b5cc6c1e4d2b4197774db82- 1A is eldest & C is youngestfalse
- 2D is eldest & C is youngesttrue
- 3C is eldest & A is youngestfalse
- 4A is eldest & B is youngestfalse
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Answer : 2. "D is eldest & C is youngest"
Explanation :
Answer: B) D is eldest & C is youngest Explanation: Given sum of present ages of A, B, C & D A + B + C + D = 176 and also given that, (A-4) : (B-4) : (C-4) : (D-4) = 11 : 9 : 6 : 14 Let the ratio = x => A-4 + B-4 + C-4 + D-4 = 11x + 9x + 6x + 14x => (A + B + C + D ) - 16 = 40x => 176 - 16 = 40x => x = 4 => A = 44 + 4 = 48 => B = 40 => C = 28 => D = 60 Therefore, from the above conclusions D is eldest with 60 years and C is youngest with 28 years of ages.
Q: How many 4-letter words with or without meaning, can be formed out of the letters of the word, 'LOGARITHMS', if repetition of letters is not allowed ? 2023 05b5cc731e4d2b4197774f805
5b5cc731e4d2b4197774f805- 15040true
- 22525false
- 32052false
- 44521false
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Answer : 1. "5040"
Explanation :
Answer: A) 5040 Explanation: The Word LOGARITHMS contains 10 letters. To find how many 4 letter words we can form from that = P410 =10x9x8x7 = 5040.
Q: There are four prime numbers written in ascending order of magnitude. The product of the first three is 385 and of the last three is 1001. Find the fourth number ? 2020 05b5cc6dce4d2b4197774e974
5b5cc6dce4d2b4197774e974- 117false
- 219false
- 313true
- 411false
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Answer : 3. "13"
Explanation :
Answer: C) 13 Explanation: (385/1001) = 5/13 First Number is 5 => Fourth number is 13
Q: A teacher multiplies 987 by a certain number and obtains 556781 as her answer. If in the answer, both 6 and 7 are wrong but the other digits are correct, then the correct answer will be 2020 05b5cc754e4d2b4197774fb8b
5b5cc754e4d2b4197774fb8b- 1553681false
- 2555181false
- 3556581false
- 4555681true
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Answer : 4. "555681"
Explanation :
Answer: D) 555681 Explanation: Given number is 987 = 3 x 7 x 47. So, required number must be divisible by each one of 3, 7, 47. None of the numbers in 553681 and 555181 are divisible by 3. While 556581 is not divisible by 7.Correct answer is 555681.
Q: Three maths classes: A, B and C take an algebra test. The average score of class A is 83. The average score of class B is 76. The average score of class C is 85. The average score of class A and B is 79 and average score of class B and C is 81. What is the average score of classes A, B, C ? 2019 05b5cc75ee4d2b4197774fcb6
5b5cc75ee4d2b4197774fcb6- 181false
- 278false
- 380.5false
- 481.5true
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Answer : 4. "81.5"
Explanation :
Answer: D) 81.5 Explanation: Let the number of students in classes A, B and C be P, Q and R respectively.Then, total score of A = 83P, total score of B = 76Q, total score of C = 85R.Also given that,(83P + 76Q) / (P + Q) = 79=>4P = 3Q.(76Q + 85R)/(Q + R) = 81=>4R = 5Q,=>Q = 4P/3 and R = 5P/3Therefore, average score of A, B, C = ( 83P + 76Q + 85R ) / (P + Q + R) = 978/12 = 81.5
Q: 640 ml of a mixture contains milk and water in ratio 6:2. How much of the water is to be added to get a new mixture containing half milk and half water ? 2017 05b5cc731e4d2b4197774f7e7
5b5cc731e4d2b4197774f7e7- 1360 mlfalse
- 2320 mltrue
- 3310 mlfalse
- 4330 mlfalse
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Answer : 2. "320 ml"
Explanation :
Answer: B) 320 ml Explanation: Here total parts of milk and water in the solution is 6+2 = 8 parts. 1part = 640/8 = 80 old mixture contains 6parts of milk and 2 parts of water(6:2). To get new mixture containing half milk and half water, add 4parts of water to the old mixture then 6:(2+4) to make the ratio same. i.e, 4 x 80 = 320 ml.
Q: The probability that a number selected at random from the first 100 natural numbers is a composite number is ? 2016 05b5cc6e3e4d2b4197774ec8e
5b5cc6e3e4d2b4197774ec8e- 13/2true
- 22/3false
- 31/2false
- 434/7false
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Answer : 1. "3/2"
Explanation :
Answer: A) 3/2 Explanation: The number of exhaustive events = 100 C₁ = 100. We have 25 primes from 1 to 100. Number of favourable cases are 75. Required probability = 75/50 = 3/2.