Quantitative Aptitude Practice Question and Answer
8Q: A and B started a business investing the money in ratio 4:6, after 6 months B withdraw his investment and C joins him with twice the amount of B. At the end of the year total profit is Rs.3315. Find share of C ? 2037 05b5cc6c5e4d2b4197774ddd7
5b5cc6c5e4d2b4197774ddd7- 1Rs. 450false
- 2Rs. 1020false
- 3Rs. 765false
- 4Rs. 1530true
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Answer : 4. "Rs. 1530"
Explanation :
Answer: D) Rs. 1530 Explanation: Ratio of investments of A, B & C => Share of C = 1530 Share of B = 765 Share of A = 1020
Q: A man reduces his travelling time by a fraction of 2/5, as a result the distance covered by the man is increased by 20%, find the percentage increase in the speed of the man ? 1449 05b5cc6c5e4d2b4197774dddc
5b5cc6c5e4d2b4197774dddc- 177%false
- 288%false
- 3100%true
- 499%false
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Answer : 3. "100%"
Explanation :
Answer: C) 100% Explanation:
Q: Manideep purchases 30kg of barley at the rate of 11.50/kg and 20kg at the rate of 14.25/kg. He mixed the two and sold the mixture in the shop. At what price per kg should he sell the mixture to make 30% profit to him ? 1590 05b5cc6c5e4d2b4197774ddc3
5b5cc6c5e4d2b4197774ddc3- 115.84false
- 214.92false
- 313.98false
- 416.38true
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Answer : 4. "16.38"
Explanation :
Answer: D) 16.38 Explanation: Given, Manideep purchases 30kg of barley at the rate of 11.50/kg nad 20kg at the rate of 14.25/kg. Total cost of the mixture of barley = (30 x 11.50) + (20 x 14.25) => Total cost of the mixture = Rs. 630 Total kgs of the mixture = 30 + 20 = 50kg Cost of mixture/kg = 630/50 = 12.6/kg To make 30% of profit => Selling price for manideep = 12.6 + 30% x 12.6 => Selling price for manideep = 12.6 + 3.78 = 16.38/kg.
Q: There are two mixtures of honey and water in which the ratio of honey and water are as 1:3 and 3:1 respectively. Two litres are drawn from first mixture and 3 litres from second mixture, are mixed to form another mixture. What is the ratio of honey and water in it ? 8684 05b5cc6c5e4d2b4197774ddc8
5b5cc6c5e4d2b4197774ddc8- 1111:108false
- 211:9true
- 3103:72false
- 4Nonefalse
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Answer : 2. "11:9"
Explanation :
Answer: B) 11:9 Explanation: From the given data, The part of honey in the first mixture = 1/4 The part of honey in the second mixture = 3/4 Let the part of honey in the third mixture = x Then, 1/4 3/4 x (3/4)-x x-(1/4) Given from mixtures 1 & 2 the ratio of mixture taken out is 2 : 3 => 34-xx-14=23 => Solving we get the part of honey in the third mixture as 11/20 => the remaining part of the mixture is water = 9/20 Hence, the ratio of the mixture of honey and water in the third mixture is 11 : 9 .
Q: Prasanna invested certain amount in three different schemes X, Y and Z with the rate of interest 10% p.a, 12% p.a and 15% p.a respectively. If the total interest accrued in one year was Rs. 3200 and the amount invested in Scheme Z was 150% of the amount invested in Scheme X and 240% of the amount invested in Scheme Y, what was the amount invested in Scheme Y by Prasanna ? 1536 05b5cc6c5e4d2b4197774ddb9
5b5cc6c5e4d2b4197774ddb9- 1Rs.6000false
- 2Rs.4500false
- 3Rs.7500false
- 4Rs.5000true
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Answer : 4. "Rs.5000"
Explanation :
Answer: D) Rs.5000 Explanation: Let a, b and c be the amounts invested in schemes X, Y and Z respectively. Then, As we know: Simple interest (S.I.) = PTR/100 (a × 10 × 1/100) + (b × 12 × 1/100) + (c × 15 × 1/100) = 3200 = 10a + 12b + 15c = 320000 .........(1) Now, c = 240% of b = 12b/5 .........(2) And, c = 150% of a = 3a/2 => a = 2/3 c = (2 × 12)b/(3 × 5) = 8b/5 .......(3) From (1), (2) and (3), we have 16b + 12b + 36b = 320000 => 64b = 320000 => b = 5000 ∴ Sum invested in Scheme Y = Rs.5000.
Q: A room contains 3 brown, 5 black and 4 white chairs. Two chairs are picked and are put in the lawn. What is the probability that none of the chairs picked is white ? 1588 05b5cc6c5e4d2b4197774ddbe
5b5cc6c5e4d2b4197774ddbe- 114/33true
- 214/55false
- 312/55false
- 413/33false
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Answer : 1. "14/33"
Explanation :
Answer: A) 14/33 Explanation: Total number of chairs = (3 + 5 + 4) = 12. Let S be the sample space. Then, n(s)= Number of ways of picking 2 chairs out of 12 = 12×11/2×1 = 66 Let n(E) = number of events of selecting 2 chairs for selecting no white chairs. => 8C2 = 8×7/2×1 = 28 Therefore required probability = 28/66 = 14/33.
Q: The price of a car is increased by 25%, by how much percent, must the new price of this car be decreased to restore its original price ? 1314 05b5cc6c5e4d2b4197774dda0
5b5cc6c5e4d2b4197774dda0- 120%true
- 224%false
- 321%false
- 425%false
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Answer : 1. "20%"
Explanation :
Answer: A) 20% Explanation: Suppose that the original price of the car = Rs. x Then new price of the car => (x) + (x ×25/100) = Rs. 5x/4 To restore the original price, the new price must be decreased by 5x/4 − x = x/4 So required percentage =(x/4)/(5x/4) × 100% = 20%
Q: Find the odd one in the number series given below ? 17, 9, 10, 18.5, 35, 90 1651 05b5cc6c5e4d2b4197774dd91
5b5cc6c5e4d2b4197774dd91- 19false
- 210false
- 318.5true
- 490false
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Answer : 3. "18.5"
Explanation :
Answer: C) 18.5 Explanation: The given series pattern follows 17 9 10 18.5 35 90 × 0.5 + 0.5, × 1 + 1, × 1.5 + 1.5, × 2 + 2, × 2.5 + 2.5 So here 17x0.5 + 0.5 = 9 9x1 + 1 = 10 10x1.5 + 1.5 = 16.5 16.5x2 + 2 = 35 35x2.5 + 2.5 = 90 Here the odd man in the given series is 18.5

