Quantitative Aptitude Practice Question and Answer
8Q: What is 15 of 80 with simple method and examples? 2106 05b5cc6b3e4d2b4197774d46d
5b5cc6b3e4d2b4197774d46d- 112.5%false
- 218.75%true
- 316.55%false
- 417.80%false
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Answer : 2. "18.75%"
Explanation :
Answer: B) 18.75% Explanation: Given that to find 15 of 80 => What % of 80 is 15 Let it be 'p' => p% of 80 = 15 => p x 80100 = 15⇒p = 15 x 10080⇒p = 150080 = 18.75 Therefore, 15 is 18.75% of 80 => 18.75% of 80 = 15 Example:: Now, in the similar way we can find 15% of 80 =? => 15x80/100 = p => p = 4 x 3 = 12 Therefore, 15% of 80 = 12
Q: Sambhu buys rice at Rs. 10/kg and puts a price tag on it so as to earn a profit of 20%. However, his faulty balance shows 1000 gm when it is actually 800 gm. What is his actual gain percentage ? 2105 05b5cc709e4d2b4197774f299
5b5cc709e4d2b4197774f299- 150%true
- 225%false
- 375%false
- 460%false
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Answer : 1. "50%"
Explanation :
Answer: A) 50% Explanation: CP of 1000gm = Rs. 10SP of 800gm = Rs. 12SP of 1000gm =12x1000/800 = Rs. 15 Now take 1000gm as reference to calculate profit.Profit=SP-CP=15-10=Rs. 5Profit % = 5x100/10 = 50%
Q: Two numbers are 35% and 42% are less than a third number .How much percent is the second number less than the first ? 2100 05b5cc6dce4d2b4197774e96f
5b5cc6dce4d2b4197774e96f- 110.769 %true
- 211.23 %false
- 310.4 %false
- 49.87 %false
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Answer : 1. "10.769 %"
Explanation :
Answer: A) 10.769 % Explanation: I II III 65 58 100 65 -------- 7100 ------ ? => 10.769%
Q: 640 ml of a mixture contains milk and water in ratio 6:2. How much of the water is to be added to get a new mixture containing half milk and half water ? 2099 05b5cc731e4d2b4197774f7e7
5b5cc731e4d2b4197774f7e7- 1360 mlfalse
- 2320 mltrue
- 3310 mlfalse
- 4330 mlfalse
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Answer : 2. "320 ml"
Explanation :
Answer: B) 320 ml Explanation: Here total parts of milk and water in the solution is 6+2 = 8 parts. 1part = 640/8 = 80 old mixture contains 6parts of milk and 2 parts of water(6:2). To get new mixture containing half milk and half water, add 4parts of water to the old mixture then 6:(2+4) to make the ratio same. i.e, 4 x 80 = 320 ml.
Q: A earns 50% of B's salary, B earns 80% of C's salary. If the total earnings for a month is Rs. 22000, then what is the earning for A ? 2098 05b5cc6c3e4d2b4197774dc3b
5b5cc6c3e4d2b4197774dc3b- 1Rs. 4000true
- 2Rs. 4200false
- 3Rs. 4400false
- 4Rs. 4600false
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Answer : 1. "Rs. 4000"
Explanation :
Answer: A) Rs. 4000 Explanation: Let C's salary be Rs. x Then B's salary = 80x/100 => A's salary = (50/100) * (80x/100) = 40x/100 But given total earnings in a month = 22000 => x + 80x/100 + 40x/100 = 22000 => x + 120x/100 = 22000 => x = 10000 => A's salary = 40 x 10000/100 = Rs. 4000
Q: The probability that a number selected at random from the first 100 natural numbers is a composite number is ? 2097 05b5cc6e3e4d2b4197774ec8e
5b5cc6e3e4d2b4197774ec8e- 13/2true
- 22/3false
- 31/2false
- 434/7false
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Answer : 1. "3/2"
Explanation :
Answer: A) 3/2 Explanation: The number of exhaustive events = 100 C₁ = 100. We have 25 primes from 1 to 100. Number of favourable cases are 75. Required probability = 75/50 = 3/2.
Q: The least number of complete years in which a sum of money put out at 20% C.I. will be more than doubled is ? 2096 05b5cc6e2e4d2b4197774ec25
5b5cc6e2e4d2b4197774ec25- 13 yearsfalse
- 24 yearstrue
- 32.5 yearsfalse
- 42 yearsfalse
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Answer : 2. "4 years"
Explanation :
Answer: B) 4 years Explanation: P1+20100n > 2P Now, (6/5 x 6/5 x 6/5 x 6/5) > 2. So, n = 4 years.
Q: Laxmi and Prasanna set on a journey. Laxmi moves northwards at a speed of 20kmph and Prasanna moves southward at a speed of 30 kmph. How far will be Prasanna from Laxmi after 60 minutes ? 2096 05b5cc74fe4d2b4197774fae0
5b5cc74fe4d2b4197774fae0- 124 kmfalse
- 250 kmtrue
- 342 kmfalse
- 430 kmfalse
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Answer : 2. "50 km"
Explanation :
Answer: B) 50 km Explanation: We know 60 min = 1 hrTotal northward Laxmi's distance = 20kmph x 1hr = 20 kmTotal southward Prasanna's distance = 30kmph x 1hr = 30 kmTotal distance between Prasanna and Laxmi is = 20 + 30 = 50 km.