Quantitative Aptitude Practice Question and Answer
8Q: The average age of husband, wife and their child 3 years ago was 24 years and that of wife and child 5 years ago was 25 years. The present age of the husband is: 1772 05b5cc6bce4d2b4197774d8d4
5b5cc6bce4d2b4197774d8d4- 121 yrstrue
- 227 yrsfalse
- 329 yrsfalse
- 431 yrsfalse
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Answer : 1. "21 yrs"
Explanation :
Answer: A) 21 yrs Explanation: Sum of ages of husband, wife and child= (24 × 3) + 9 = 81 years Sum of ages of wife and child => 25 × 2 + 10 = 50 + 10 = 60 years Age of husband = 81 - 60 = 21 years.
Q: R enter into a partnership in the ratio 2 : 3 : 5 . After 2 months, P increases his share 20% and Q by 10%. If the total profit at the end of one year is Rs 1,90,500, what amount will 'R' receive at the end of year as share in profit ? 1771 05b5cc6cbe4d2b4197774e0fe
5b5cc6cbe4d2b4197774e0fe- 1Rs. 90500false
- 2Rs. 87500false
- 3Rs. 88900false
- 4Rs. 90000true
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Answer : 4. "Rs. 90000"
Explanation :
Answer: D) Rs. 90000 Explanation: Ratio of investments for 1 year => (P : Q : R) = (2x2 + 2.4x10) : (3x2 + 3.3x10) : (5x12) => (P : Q : R) = 28 : 39 : 60 Now R share = 190500 x 60/127 = Rs. 90000.
Q: If 25% of a number is subtracted from a second number, the second number reduces to its four-sixth. What is the ratio of the first number to the second number ? 1770 05b5cc6dee4d2b4197774ea46
5b5cc6dee4d2b4197774ea46- 14:3true
- 22:3false
- 33:2false
- 45:3false
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Answer : 1. "4:3"
Explanation :
Answer: A) 4:3 Explanation: Let the numbers be p & q q-p/4 = 4q/6 => q-4q/6 = p/4 => 2q/6 = p/4 => p/q = 4/3
Q: The least number of complete years in which a sum of money put out at 20% C.I. will be more than doubled is ? 1770 05b5cc6e2e4d2b4197774ec25
5b5cc6e2e4d2b4197774ec25- 13 yearsfalse
- 24 yearstrue
- 32.5 yearsfalse
- 42 yearsfalse
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Answer : 2. "4 years"
Explanation :
Answer: B) 4 years Explanation: P1+20100n > 2P Now, (6/5 x 6/5 x 6/5 x 6/5) > 2. So, n = 4 years.
Q: A man walks at a speed of 2 km/hr and runs at a speed of 6 km/hr. How much time will the man require to cover a distance of 20 1/2 km, if he completes half of the distance, i.e., (10 1/4) km on foot and the other half by running ? 1769 05b5cc6dfe4d2b4197774eaf8
5b5cc6dfe4d2b4197774eaf8- 112.4 hrsfalse
- 211.9 hrstrue
- 310.7 hrsfalse
- 49.9 hrsfalse
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Answer : 2. "11.9 hrs"
Explanation :
Answer: B) 11.9 hrs Explanation: We know that Time = Distance/speedRequired time = (10 1/4)/2 + (10 1/4)/6 = 41/8 + 41/6= 287/24 = 11.9 hours.
Q: In how many different ways can the letters of the word 'THERAPY' be arranged so that the vowels never come together? 1769 05b5cc69de4d2b4197774c919
5b5cc69de4d2b4197774c919- 11440false
- 2720false
- 32250false
- 43600true
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Answer : 4. "3600"
Explanation :
Answer: D) 3600 Explanation: Given word is THERAPY. Number of letters in the given word = 7 These 7 letters can be arranged in 7! ways. Number of vowels in the given word = 2 (E, A) The number of ways of arrangement in which vowels come together is 6! x 2! ways Hence, the required number of ways can the letters of the word 'THERAPY' be arranged so that the vowels never come together = 7! - (6! x 2!) ways = 5040 - 1440 = 3600 ways.
Q: If 5 men and 2 boys working together, can do four times as much work per hour as a man and a boy together. Find the ratio of the work done by a man and that of a boy for a given time ? 1767 05b5cc6e2e4d2b4197774ec4d
5b5cc6e2e4d2b4197774ec4d- 11:2false
- 21:3false
- 33:1false
- 42:1true
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Answer : 4. "2:1"
Explanation :
Answer: D) 2:1 Explanation: 5M + 2B = 4(1M + 1B) 5M + 2B = 4M + 4B 1M = 2B The required ratio of work done by a man and a boy = 2:1
Q: A earns 50% of B's salary, B earns 80% of C's salary. If the total earnings for a month is Rs. 22000, then what is the earning for A ? 1765 05b5cc6c3e4d2b4197774dc3b
5b5cc6c3e4d2b4197774dc3b- 1Rs. 4000true
- 2Rs. 4200false
- 3Rs. 4400false
- 4Rs. 4600false
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Answer : 1. "Rs. 4000"
Explanation :
Answer: A) Rs. 4000 Explanation: Let C's salary be Rs. x Then B's salary = 80x/100 => A's salary = (50/100) * (80x/100) = 40x/100 But given total earnings in a month = 22000 => x + 80x/100 + 40x/100 = 22000 => x + 120x/100 = 22000 => x = 10000 => A's salary = 40 x 10000/100 = Rs. 4000