Quantitative Aptitude Practice Question and Answer
8Q: The length of a class room floor exceeds its breadth by 25 m. The area of the floor remains unchanged when the length is decreased by 10 m but the breadth is increased by 8 m. The area of the floor is 2007 05b5cc6b6e4d2b4197774d577
5b5cc6b6e4d2b4197774d577- 15100 sq.mtrue
- 24870 sq.mfalse
- 34987 sq.mfalse
- 44442 sq.mfalse
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Answer : 1. "5100 sq.m"
Explanation :
Answer: A) 5100 sq.m Explanation: Let the breadth of floor be 'b' m. Then, length of the floor is 'l = (b + 25)' Area of the rectangular floor = l x b = (b + 25) × b According to the question, (b + 15) (b + 8) = (b + 25) × b b2 + 8b + 15b + 120 = b2 + 25b 2b = 120 b = 60 m. l = b + 25 = 60 + 25 = 85 m. Area of the floor = 85 × 60 = 5100 sq.m.
Q: How many seconds will a 600 m long train take to cross a man walking with a speed of 7 km/hr in the direction of the moving train if the speed of the train is 67 km/hr ? 2005 05b5cc6dfe4d2b4197774eb20
5b5cc6dfe4d2b4197774eb20- 129 secfalse
- 258 secfalse
- 336 sectrue
- 444 secfalse
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Answer : 3. "36 sec"
Explanation :
Answer: C) 36 sec Explanation: Speed of train relative to man = 67 - 7 = 60 km/hr.= 60 x 5/18 = 50/3 m/sec. Time taken to pass the man = 600 x 3/50 = 36 sec.
Q: Prasanna invested certain amount in three different schemes X, Y and Z with the rate of interest 10% p.a, 12% p.a and 15% p.a respectively. If the total interest accrued in one year was Rs. 3200 and the amount invested in Scheme Z was 150% of the amount invested in Scheme X and 240% of the amount invested in Scheme Y, what was the amount invested in Scheme Y by Prasanna ? 2005 05b5cc6c5e4d2b4197774ddb9
5b5cc6c5e4d2b4197774ddb9- 1Rs.6000false
- 2Rs.4500false
- 3Rs.7500false
- 4Rs.5000true
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Answer : 4. "Rs.5000"
Explanation :
Answer: D) Rs.5000 Explanation: Let a, b and c be the amounts invested in schemes X, Y and Z respectively. Then, As we know: Simple interest (S.I.) = PTR/100 (a × 10 × 1/100) + (b × 12 × 1/100) + (c × 15 × 1/100) = 3200 = 10a + 12b + 15c = 320000 .........(1) Now, c = 240% of b = 12b/5 .........(2) And, c = 150% of a = 3a/2 => a = 2/3 c = (2 × 12)b/(3 × 5) = 8b/5 .......(3) From (1), (2) and (3), we have 16b + 12b + 36b = 320000 => 64b = 320000 => b = 5000 ∴ Sum invested in Scheme Y = Rs.5000.
Q: The difference between two numbers is 3355. When the larger number is divided by the smaller one, the quotient is 6 and the remainder is 15. The smaller number and larger number respectively ? 2003 05b5cc754e4d2b4197774fb81
5b5cc754e4d2b4197774fb81- 1546, 3901false
- 2415, 3770false
- 3668, 4023true
- 4404, 3759false
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Answer : 3. "668, 4023"
Explanation :
Answer: C) 668, 4023 Explanation: Let the smaller number be k.Then, larger number = (3355 + k)Therefore 3355 + k = (6k + 15)‹=› 5k = 3340‹=› k = 668. Therefore, the smaller number k = 668 and now the larger number = 3355+668 = 4023.
Q: In how many different ways can the letters of the word 'HAPPYHOLI' be arranged? 2000 05b5cc6a7e4d2b4197774ce0e
5b5cc6a7e4d2b4197774ce0e- 189,972false
- 290,720true
- 372,000false
- 481,000false
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Answer : 2. "90,720"
Explanation :
Answer: B) 90,720 Explanation: The given word HAPPYHOLI has 9 letters These 9 letters can e arranged in 9! ways. But here in the given word letters H & P are repeated twice each Therefore, Number of ways these 9 letters can be arranged is 9!2! x 2! = 9 x 8 x 7 x 6 x 5 x 4 x 32 = 90,720 ways.
Q: Find the odd letter/word from the given alternatives. 2000 05b5cc6cae4d2b4197774dff2
5b5cc6cae4d2b4197774dff2- 1Horsetrue
- 2Ewefalse
- 3Hindfalse
- 4Bitchfalse
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Answer : 1. "Horse"
Explanation :
Answer: A) Horse Explanation: Except Horse, remaining all belong to female category. Hind - Female Deer Ewe - Female Sheep Bitch - Female Dog.
Q: 5 sin(x)+ 12 cos(x) + r is always greater than or equal to zero. What is the smallest value satisfied by 'r' ? 1998 05b5cc77fe4d2b419777501bf
5b5cc77fe4d2b419777501bf- 1-13false
- 211false
- 313true
- 4-11false
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Answer : 3. "13"
Explanation :
Answer: C) 13 Explanation: Given, 5sinx + 12cosx ≥ -r ⇒13513sin x + 1213cos x ≥ -rcosx) ≥ -r 513= cosA => sinA =1213 => 13(sinx cosA + sinA cosx) ≥ -r => 13(sin(x + A)) ≥ -r we know that , -1 ≤ sin (angle) ≤ 1 => 13sin (x + A) ≥ -13 ⇒rmin =13
Q: Excluding the stoppages, the speed of a bus is 64 km/hr and including the stoppages the speed o the bus is 48km/hr. For how many minutes does the bus stop per hour? 1996 05b5cc7c7e4d2b41977750daa
5b5cc7c7e4d2b41977750daa- 112.5 minutesfalse
- 215 minutestrue
- 310 minutesfalse
- 418 minutesfalse
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Answer : 2. "15 minutes"
Explanation :
Answer: B) 15 minutes Explanation: