Join Examsbook
1127 0

Q: The length of a class room floor exceeds its breadth by 25 m. The area of the floor remains unchanged when the length is decreased by 10 m but the breadth is increased by 8 m. The area of the floor is

  • 1
    5100 sq.m
  • 2
    4870 sq.m
  • 3
    4987 sq.m
  • 4
    4442 sq.m
  • Show AnswerHide Answer
  • Workspace

Answer : 1. "5100 sq.m"
Explanation :

Answer: A) 5100 sq.m Explanation: Let the breadth of floor be 'b' m. Then, length of the floor is 'l = (b + 25)' Area of the rectangular floor = l x b = (b + 25) × b According to the question, (b + 15) (b + 8) = (b + 25) × b b2 + 8b + 15b + 120 = b2 + 25b 2b = 120 b = 60 m. l = b + 25 = 60 + 25 = 85 m.   Area of the floor = 85 × 60 = 5100 sq.m.

Are you sure

  Report Error

Please Enter Message
Error Reported Successfully