Quantitative Aptitude Practice Question and Answer
8Q: 7, 11, 19, 35, ? Find the next number in the given number series? 2472 05b5cc6ace4d2b4197774d0bb
5b5cc6ace4d2b4197774d0bb- 1131false
- 294false
- 383false
- 467true
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Answer : 4. "67"
Explanation :
Answer: D) 67 Explanation: Here the given series 7, 11, 19, 35, ? follows a pattern that (x 2 - 3) i.e, 7 7 x 2 - 3 = 11 11 x 2 - 3 = 19 19 x 2 - 3 = 35 35 x 2 - 3 = 67 67 x 2 - 3 = 131 Hence the next number in the given number series is 67.
Q: A motorboat goes 8 km an hour in still water, but takes thrice as much time in going the same distance against the current than going with the current. Then find the speed of the current? 2332 05b5cc6ace4d2b4197774d09b
5b5cc6ace4d2b4197774d09b- 14 kmphtrue
- 26 kmphfalse
- 33 kmphfalse
- 42 kmphfalse
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Answer : 1. "4 kmph"
Explanation :
Answer: A) 4 kmph Explanation: Let the speed of current = 'C' km/hr Given the speed of boat in still water = 6 kmph Let 'd' kms be the distance it covers. According to the given data, Boat takes thrice as much time in going the same distance against the current than going with the current i.e, d8 - C = 3 × d8 + C ⇒ 24 - 3C = 8 + C⇒ 4C = 16⇒ C = 4 kmph Hence, the speed of the current C = 4 kmph.
Q: The calendar for the year 2018 will be the same for the year 2791 05b5cc6ace4d2b4197774d096
5b5cc6ace4d2b4197774d096- 12023false
- 22027false
- 32029true
- 42022false
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Answer : 3. "2029"
Explanation :
Answer: C) 2029 Explanation: How to find the years which have the same Calendars : Leap year calendar repeats every 28 years. Here 28 is distributed as 6 + 11 + 11. Rules: a) If given year is at 1st position after Leap year then next repeated calendar year is Givenyear+6. b) If given year is at 2nd position after Leap year then next repeated calendar year is Givenyear+11. c) If given year is at 3rd position after Leap year then next repeated calendar year is Givenyear+11. Now, the given year is 2018 We know that 2016 is a Leap year. 2016 2017 2018 2019 2020 Lp Y 1st 2nd 3rd Lp Y Here 2018 is at 2 nd position after the Leap year. According to rule b) the calendar of 2018 is repeated for the year is 2018 + 11 = 2029.
Q: Simplify the following and find the value of ? 13 of ? + 47 of 114 of 539 = 31% of 2000 1703 05b5cc6ace4d2b4197774d091
5b5cc6ace4d2b4197774d091- 11134true
- 21237false
- 31187false
- 41249false
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Answer : 1. "1134"
Explanation :
Answer: A) 1134 Explanation: 13 x ? + 47 x 114 x 539 = 31100 x 2000? = 378 x 3? = 1134
Q: What is the difference between the compound interests on Rs. 5000 for 11⁄2 years at 4% per annum compounded yearly and half-yearly? 1361 05b5cc6ace4d2b4197774d08c
5b5cc6ace4d2b4197774d08c- 1Rs. 1.80false
- 2Rs. 2.04true
- 3Rs. 3.18false
- 4Rs. 4.15false
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Answer : 2. "Rs. 2.04"
Explanation :
Answer: B) Rs. 2.04 Explanation: Compound Interest for 1 1⁄2 years when interest is compounded yearly = Rs.(5304 - 5000) Amount after 11⁄2 years when interest is compounded half-yearly Compound Interest for 1 1⁄2 years when interest is compounded half-yearly = Rs.(5306.04 - 5000) Difference in the compound interests = (5306.04 - 5000) - (5304 - 5000)= 5306.04 - 5304 = Rs. 2.04
Q: The average weight of 45 passengers in a bus is 52 kg. 5 of them whose average weight is 48 kg leave the bus and other 5 passengers whose average weight is 54 kg join the bus at the same stop. What is the new average weight of the bus? 5444 05b5cc6abe4d2b4197774d06c
5b5cc6abe4d2b4197774d06c- 154.21 kgsfalse
- 251.07 kgsfalse
- 352.66 kgstrue
- 453.45 kgsfalse
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Answer : 3. "52.66 kgs"
Explanation :
Answer: C) 52.66 kgs Explanation: Given total number of passengers in the bus = 45 First average weight of 45 passengers = 52 kgs Average weight of 5 passengers who leave bus = 48 Average weight of 5 passengers who joined the bus = 54 Therefore, the net average weight of the bus is given by = 45 x 52 - 5 x 48 + 5 x 5445 = 237045= 1583= 52.66 kgs.
Q: Chennai express left Hyderabad for Chennai at 14 : 30 hours, travelling at a speed of 60 kmph and Charminar Express left Hyderabad for Chennai on the same day at 16 : 30 hours, travelling at a speed of 80 kmph. How far away from Hyderabad will the two trains meet? 1789 05b5cc6abe4d2b4197774d067
5b5cc6abe4d2b4197774d067- 1360 kmsfalse
- 2480 kmstrue
- 3520 kmsfalse
- 4240 kmsfalse
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Answer : 2. "480 kms"
Explanation :
Answer: B) 480 kms Explanation: Now, the distance covered by Chennai express in 2 hrs = 60 x 2 = 120 kms Let the Charminar Express takes 't' hrs to catch Chennai express => 80 x t = 60 x (2 + t) => 80 t = 120 + 60t => t = 6 hrs Therefore, the distance away from Hyderabad the two trains meet = 80 x 6 = 480 kms.
Q: How many words can be formed with or without meaning by using three letters out of k, l, m, n, o without repetition of alphabets. 1278 05b5cc6abe4d2b4197774d058
5b5cc6abe4d2b4197774d058- 160true
- 2120false
- 3240false
- 430false
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Answer : 1. "60"
Explanation :
Answer: A) 60 Explanation: Given letters are k, l, m, n, o = 5 number of letters to be in the words = 3 Total number of words that can be formed from these 5 letters taken 3 at a time without repetation of letters = 5P3 ways. ⇒ 5P3 = 5 x 4 x 3 = 60 words.

