Quantitative Aptitude Practice Question and Answer
8Q: If the price of a commodity is decreased by 20% and its consumption is increased by 10%, what will be the increase or decrease in the expenditure on the commodity? 1398 05b5cc6a2e4d2b4197774cb70
5b5cc6a2e4d2b4197774cb70- 1increase 12%false
- 2decrease 12%true
- 3increase 16%false
- 4decrease 16%false
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Answer : 2. "decrease 12%"
Explanation :
Answer: B) decrease 12% Explanation: Given the price of a commodity is decreased by p = 20% And its consumption is increased by q = 10% Now, required increase or decrease in the expenditure on the commodity can be p + q + pq/100 = -20 + 10 - 200/100 = -10 - 2 = -12%. Hence, decrease in the expenditure = 12%
Q: Value of vehicle at end of each year depreciates at the rate of 3/5th of value at the beginning. If Initial value is 10,000Rs then at the end of three years its value is ? 1395 05b5cc715e4d2b4197774f472
5b5cc715e4d2b4197774f472- 1Rs. 6000false
- 2Rs. 3600false
- 3Rs. 2160true
- 4Rs. 415false
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Answer : 3. "Rs. 2160"
Explanation :
Answer: C) Rs. 2160 Explanation: End of first year : 10000 x (3/5) = Rs. 6000End of second year : 6000 x (3/5) = Rs. 3600End of third year : 3600 x (3/5) = Rs. 2160
Q: The total of the ages of Ashok, Akbar and Anil is 65 years. What was the total of their ages six years ago ? 1394 05b5cc723e4d2b4197774f695
5b5cc723e4d2b4197774f695- 159false
- 243false
- 357false
- 447true
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Answer : 4. "47"
Explanation :
Answer: D) 47 Explanation: Let their ages be x, y, zHence given that x + y + z = 65Now, six years ago x age is x - 6, y is y - 6 and that of z is z - 6Then the sum of their ages six years ago is (x + y + z) - (6 + 6 + 6) = 65 - 18 = 47
Q: 12 men complete a work in 9 days. After they have worked for 6 days, 4 more men join them. How many days will they take to complete the remaining work ? 1394 05b5cc6d7e4d2b4197774e700
5b5cc6d7e4d2b4197774e700- 12 daysfalse
- 22.5 daysfalse
- 32.25 daystrue
- 43 daysfalse
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Answer : 3. "2.25 days"
Explanation :
Answer: C) 2.25 days Explanation: 1 man's 1 day work = 1/108 12 men's 6 day's work = 1/9 x 6 = 2/3 Remaining work = 1 - 2/3 = 1/3 16 men's 1 day work = 1/108 x 16 = 4/274/27 work is done by them in 1 day. 1/3 work is done by them in 27/4 x 1/3 = 9/4 days.
Q: Find the Missing number in the given Series ? 2, 3, 6, 15, ? , 157.5 1393 05b5cc6bce4d2b4197774d8ac
5b5cc6bce4d2b4197774d8ac- 187false
- 278.5false
- 356.5false
- 445true
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Answer : 4. "45"
Explanation :
Answer: D) 45 Explanation: Here given 2, 3, 6, 15, ? , 157.5 2 x 1.5 = 3 3 x 2 = 6 6 x 2.5 = 15 15 x 3 = 45 45 x 3.5 = 157.5 Therefore, the missing number is 45
Q: 83% of 2350 = ? 1391 05b5cc6bce4d2b4197774d87c
5b5cc6bce4d2b4197774d87c- 11889.95false
- 21912.35false
- 31875.25false
- 41950.50true
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Answer : 4. "1950.50"
Explanation :
Answer: D) 1950.50 Explanation: 83% of 2350 = ? 83/100 x 2350 =8.3 x 235 =1950.50
Q: There are two numbers such that the sum of twice the first number and thrice the second number is 100 and sum of thrice the first number and twice the second number is 120. Which is the larger number ? 1391 05b5cc736e4d2b4197774f892
5b5cc736e4d2b4197774f892- 132true
- 224false
- 326false
- 438false
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Answer : 1. "32"
Explanation :
Answer: A) 32 Explanation: Let the first number be K and second number be LThen, 2K + 3L = 100.....(1)3K + 2L = 120.......(2)solving (1)&(2), we getK = 32 and L = 12 Hence the largest number is 32.
Q: Hemavathi gets 3 marks for each right sum and loses 2 marks for each wrong sum. He attempts 35 sums and obtains 60 marks. The number of sums attempted correctly is ? 1390 05b5cc73de4d2b4197774f90c
5b5cc73de4d2b4197774f90c- 123false
- 224false
- 325false
- 426true
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Answer : 4. "26"
Explanation :
Answer: D) 26 Explanation: Let, Hema attempted 'k' sum correctly, then k x 3 -2 x(35-k) = 605k = 130k = 26 so 26 correct sums.