Quantitative Aptitude Practice Question and Answer
8Q: The average of marks in 3 subjects is 224. The first subject marks is twice the second and the second subject marks is twice the third. Find the second subject marks ? 1684 05b5cc6cce4d2b4197774e17c
5b5cc6cce4d2b4197774e17c- 1384false
- 296false
- 3192true
- 4206false
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Answer : 3. "192"
Explanation :
Answer: C) 192 Explanation: Let the third subject marks be 'x'=> Second subject marks = 2x=> Third subject marks = 4xGiven avg = 224x + 2x + 4x = 224 x 3=> 7x = 224 x 3=> x = 96Hence, Second subject marks = 2x = 2 x 96 = 192.
Q: Lasya invested certain amount for two rates of simple interests at 5% p.a. and 4% p.a. What is the ratio of Lasya's investments if the interests from those investments are equal ? 1683 05b5cc6e2e4d2b4197774ec1b
5b5cc6e2e4d2b4197774ec1b- 14 : 5true
- 25 : 4false
- 37 : 6false
- 46 : 7false
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Answer : 1. "4 : 5"
Explanation :
Answer: A) 4 : 5 Explanation: Let x be the investment of Lasya in 5% and y be in 4% x(5)(n)/100 = y(4)(n)/100 => x/y = 4/5 x : y = 4 : 5
Q: What is the difference between the compound interests on Rs. 5000 for 11⁄2 years at 4% per annum compounded yearly and half-yearly? 1681 05b5cc6ace4d2b4197774d08c
5b5cc6ace4d2b4197774d08c- 1Rs. 1.80false
- 2Rs. 2.04true
- 3Rs. 3.18false
- 4Rs. 4.15false
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Answer : 2. "Rs. 2.04"
Explanation :
Answer: B) Rs. 2.04 Explanation: Compound Interest for 1 1⁄2 years when interest is compounded yearly = Rs.(5304 - 5000) Amount after 11⁄2 years when interest is compounded half-yearly Compound Interest for 1 1⁄2 years when interest is compounded half-yearly = Rs.(5306.04 - 5000) Difference in the compound interests = (5306.04 - 5000) - (5304 - 5000)= 5306.04 - 5304 = Rs. 2.04
Q: An owner of a Dry fruits shop sold small packets of mixed nuts for Rs. 150 each and large packets for Rs. 250 each. One day he sold 5000 packets, for a total of Rs. 10.50 lakh. How many small packets were sold ? 1681 05b5cc6cfe4d2b4197774e308
5b5cc6cfe4d2b4197774e308- 12000true
- 23000false
- 32500false
- 43500false
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Answer : 1. "2000"
Explanation :
Answer: A) 2000 Explanation: Let 's' be the number of small packets and 'b' the number of large packets sold on that day. Therefore, s + b = 5000 ... eqn (1) Each small packet was sold for Rs.150.Therefore, 's' small packets would have fetched Rs.150s. Each large packets was sold for Rs.250.Therefore, 'b' large packets would have fetched Rs.250b. Total value of sale = 150s + 250b = Rs. 10.5 Lakhs (Given) Or 150s + 250b = 10,50,000 ... eqn (2) Multiplying equation (1) by 150, we get 150s + 150b = 7,50,000 ... eqn (3) Subtracting eqn (3) from eqn (2), we get 100b = 3,00,000Or b = 3000 We know that s + b = 5000So, s = 5000 - b = 5000 - 3000 = 2000. 2000 small packets were sold.
Q: LCD of 12 and 18 1680 05b5cc6b8e4d2b4197774d66b
5b5cc6b8e4d2b4197774d66b- 136true
- 242false
- 312false
- 46false
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Answer : 1. "36"
Explanation :
Answer: A) 36 Explanation: LCD is nothing but Lowest or Least Common Denominator Here LCD of 12 and 18 means LCD of two fractions with denominators 12 and 18 respectively. Therefore, LCM of 12 & 18 = 6 x 3 x 2 = 36 How to calculate LCD :: The lowest common denominator or least common denominator (LCD) is the least common multiple (LCM) of the denominators of a set of fractions.
Q: Two letters are randomly chosen from the word TIME. Find the probability that the letters are T and M? 1679 05b5cc6ade4d2b4197774d10e
5b5cc6ade4d2b4197774d10e- 11/4false
- 21/6true
- 31/8false
- 44false
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Answer : 2. "1/6"
Explanation :
Answer: B) 1/6 Explanation: Required probability is given by P(E) = n(E)n(S) = 14C2 = 16
Q: Rs. 50000 is divided into two parts One part is given to a person with 10% interest and another part is given to a person with 20 % interest. At the end of first year he gets profit 7000 Find money given by 10% ? 1677 05b5cc711e4d2b4197774f3b9
5b5cc711e4d2b4197774f3b9- 1Rs. 20,000false
- 2Rs. 10,000false
- 3Rs. 30,000true
- 4Rs. 40,000false
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Answer : 3. "Rs. 30,000"
Explanation :
Answer: C) Rs. 30,000 Explanation: Let first part is 'K' and second part is 'L' then K + L = 50000---------eq1Total profit = profit on x + profit on y7000 = (K x 10 x 1)/100 + (L x 20 x 1)/10070000 = K + 2L-----------------------------------eq270000 = 50000 + Lso L = 20000 then K = 50000 - 20000 = 30000first part on 10% is = Rs.30000
Q: Find the sum to 200 terms of the series 2 + 5 + 7 + 6 + 12 + 7 + .... 1677 05b5cc754e4d2b4197774fb9f
5b5cc754e4d2b4197774fb9f- 130,400true
- 230,200false
- 334,600false
- 438,400false
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Answer : 1. "30,400"
Explanation :
Answer: A) 30,400 Explanation: we can treat every two consecutive terms as one.So, we will have a total of 100 terms of the nature:(2 + 5) + (7 + 6) + (12 + 7).... => 7, 13, 19,.... We know the sum of n terms nn+12 Now, a= 7, d=6 and n=100Hence the sum of the given series is S= 100/2 x[2 x 7 + 99 x 6]=> 50[608]=> 30,400.

