Quantitative Aptitude Practice Question and Answer
8Q: What is 70 of 50? 1369 05b5cc675e4d2b4197774c13e
5b5cc675e4d2b4197774c13e- 135true
- 238false
- 342false
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Answer : 1. "35"
Explanation :
Answer: A) 35 Explanation: what is 70 of 50 means 70% of 50 ⇒70 x 50100= 7 x 5= 35 Hence, 70 of 50 is 35.
Q: From a group of 7 boys and 6 girls, five persons are to be selected to form a team, so that at least 3 girls are there in the team. In how many ways can it be done? 1459 05b5cc675e4d2b4197774c115
5b5cc675e4d2b4197774c115- 1427false
- 2531true
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Answer : 2. "531"
Explanation :
Answer: B) 531 Explanation: Given in the question that, there are 7 boys and 6 girls. Team members = 5 Now, required number of ways in which a team of 5 having atleast 3 girls in the team = 6C3 x 7C2 + 6C4 x 7C1 + 6C5= 6x5x43x2x1 x 7x62x1 + 6x5x4x34x3x2x1 x 7 + 6x5x4x3x25x4x3x2x1= 420 + 105 + 6= 531.
Q: Ashwin fires two bullets from the same place at an interval of 15 minutes but Rahul sitting in a bus approaching the place hears the second sound 14 minutes 30 seconds after the first. If sound travels at the speed of 330 meter per second, what is the approximate speed of bus? 2491 05b5cc670e4d2b4197774c060
5b5cc670e4d2b4197774c060- 1330/29 m/strue
- 2330 x 30 m/sfalse
- 3330/14 m/sfalse
- 4330/900 m/sfalse
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Answer : 1. "330/29 m/s"
Explanation :
Answer: A) 330/29 m/s Explanation: Second gun shot take 30 sec to reach rahul imples distance between two. given speed of sound = 330 m/s Now, distance = 330 m/s x 30 sec Hence, speed of the bus = d/t = 330x30/(14x60 + 30) = 330/29 m/s.
Q: Find the odd one out of the following number series? 9 5 6 14 56 488 2889 05b5cc66de4d2b4197774bfb0
5b5cc66de4d2b4197774bfb0- 156true
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Answer : 1. "56"
Explanation :
Answer: A) 56 Explanation: The given number series follows a pattern that, 9 9 x 0.5 + 0.5 = 5 5 x 1 + 1 = 6 6 x 2 + 2 = 14 14 x 4 + 4 = 60 (not equals to 56) 60 x 8 + 8 = 488. Hence, the odd one in the given number series is 56.
Q: Third proportion of 10 and 20 is 1386 05b5cc66de4d2b4197774bfa0
5b5cc66de4d2b4197774bfa0- 130false
- 240true
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Answer : 2. "40"
Explanation :
Answer: B) 40 Explanation: The third proportional of two numbers p and q is defined to be that number r such that p : q = q : r. Here, required third proportional of 10 & 20, and let it be 'a' => 10 : 20 = 20 : a 10a = 20 x 20 => a = 40 Hence, third proportional of 10 & 20 is 40.
Q: 80% of 900 + 162 x 4 x ? = 113 - 99 2984 05b5cc669e4d2b4197774bf6d
5b5cc669e4d2b4197774bf6d- 10.5true
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Answer : 1. "0.5"
Explanation :
Answer: A) 0.5 Explanation: 80x900/100 + 256 x 4 x ? = 1331 - 99 720 + 1024 x ? = 1232 ? = 1232 - 720/1024 ? = 512/1024 = 0.5 ? = 0.5
Q: A, B and C can do a piece of work in 72, 48 and 36 days respectively. For first p/2 days, A & B work together and for next ((p+6))/3days all three worked together. Remaining 125/3% of work is completed by D in 10 days. If C & D worked together for p day then, what portion of work will be remained? 1738 05b5cc669e4d2b4197774bf4d
5b5cc669e4d2b4197774bf4d- 11/5false
- 21/6true
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Answer : 2. "1/6"
Explanation :
Answer: B) 1/6 Explanation: Total work is given by L.C.M of 72, 48, 36 Total work = 144 units Efficieny of A = 144/72 = 2 units/day Efficieny of B = 144/48 = 3 units/day Efficieny of C = 144/36 = 4 units/day According to the given data, 2 x p/2 + 3 x p/2 + 2 x (p+6)/3 + 3 x (p+6)/3 + 4 x (p+6)/3 = 144 x (100 - 125/3) x 1/100 3p + 4.5p + 2p + 3p + 4p = 84 x 3 - 54 p = 198/16.5 p = 12 days. Now, efficency of D = (144 x 125/3 x 1/100)/10 = 6 unit/day (C+D) in p days = (4 + 6) x 12 = 120 unit Remained part of work = (144-120)/144 = 1/6.
Q: Find the next number in the given number series? 50, 51, 47, 56, 40, ? 3040 05b5cc669e4d2b4197774bf52
5b5cc669e4d2b4197774bf52- 158false
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Answer : 2. "65"
Explanation :
Answer: B) 65 Explanation: The given number series is 50, 51, 47, 56, 40, ? 5050 + 12 = 5151 - 22 = 4747 + 32 = 5656 - 42 = 4040 + 52 = 65 Hence, the next number in the given number series is 65.