Quantitative Aptitude Practice Question and Answer
8Q: The average marks of a student in 7 subjects is 85. His average marks in 6 subjects except English is 83. What is his marks in English ? 1227 05b5cc6c2e4d2b4197774dbf5
5b5cc6c2e4d2b4197774dbf5- 197true
- 298false
- 392false
- 493false
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Answer : 1. "97"
Explanation :
Answer: A) 97 Explanation: Marks in English = 85×7 – 83×6 = 595 – 498 = 97
Q: A can do a work in 9 days, B can do a work in 7 days, C can do a work in 5 days. A works on the first day, B works on the second day and C on the third day respectively that is they work on alternate days. When will they finish the work ? 1227 05b5cc73de4d2b4197774f94d
5b5cc73de4d2b4197774f94d- 1[7 + (215/345)] daysfalse
- 2[6 + (11/215)] daysfalse
- 3[6 + (261/315)] daystrue
- 4[5 + (112/351)] daysfalse
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Answer : 3. "[6 + (261/315)] days"
Explanation :
Answer: C) [6 + (261/315)] days Explanation: After day 1, A finishes 1/9 of the work. After day 2, B finishes 1/7 more of the total work. (1/9) + (1/7) is finished. After day 3, C finishes 1/5 more of total work. Total finished is 143/315. So, after day 6, total work finished is 286/315. Now remaining work = 29 /315 On day 7, A will work again Work will be completed on day 7 when A is working. He must finish 29/315 of total remaining work. Since he takes 9 days to finish the total task, he will need 261/315 of the day. Total days required is 6 + (261/315) days.
Q: Two persons start running simultaneously around a circular track of length 600 m from the same point at speeds of 25 kmph and 35 kmph. When will they meet for the first time any where on the track ? 1227 05b5cc6d3e4d2b4197774e54a
5b5cc6d3e4d2b4197774e54a- 154 secfalse
- 236 sectrue
- 372 secfalse
- 411 secfalse
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Answer : 2. "36 sec"
Explanation :
Answer: B) 36 sec Explanation: Time taken to meet the first time = length of track/relative speed Given the length of the track is 600 m The relative speed = 25 + 35 = 60 kmph = 60 x 5/18 m Therefore Time = 60025+35518= 600/60 x (18/5) = 36 sec.
Q: 54, 60 LCM is 1219 05b5cc6bce4d2b4197774d891
5b5cc6bce4d2b4197774d891- 1600false
- 2540true
- 360false
- 454false
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Answer : 2. "540"
Explanation :
Answer: B) 540 Explanation: Here the LCM of 54, 60 is => 2 x 3 x 3 x 3 x 10 = 6 x 9 x 10 = 54 x 10 = 540.
Q: What value will come in place of question mark (?) in following number series? 12, 16, 32, 68, ? 1219 05b5cc6bee4d2b4197774d9c4
5b5cc6bee4d2b4197774d9c4- 1198false
- 2164false
- 3132true
- 4118false
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Answer : 3. "132"
Explanation :
Answer: C) 132 Explanation: Given series is 12 16 32 68 ? Here it follows a pattern that, 12 12 + (2x2) = 16 16 + (4x4) = 32 32 + (6x6) = 68 68 + (8x8) = 132
Q: A salesman calculated his profit on the marked price and finds it to be 30%. He forgets the fact that he gave a discount of 20%. What is his actual profit percentage? 1219 05b5cc6bae4d2b4197774d7ad
5b5cc6bae4d2b4197774d7ad- 1260/11%false
- 218.4%false
- 322.5%false
- 4100/7%true
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Answer : 4. "100/7%"
Explanation :
Answer: D) 100/7% Explanation: When profit is calculated on Marked Price (M.P) then, C.P = M.P - P% Let M.P = 100 => C.P = 100 - 30 = 70 But S.P = Rs. 80 as he gave 20% discount, Now, Actual Profit = 80-7070x100 = 100/7 %
Q: There are 1650 students in a college. The difference between the number of boys and girls in the college is 400. What is the percentage of girls in the college ? 1215 05b5cc6c5e4d2b4197774dd1e
5b5cc6c5e4d2b4197774dd1e- 149false
- 234false
- 343false
- 438true
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Answer : 4. "38"
Explanation :
Answer: D) 38 Explanation: Let no. of boys be 'B' and no. of girls be 'G' Here from given data, B + G = 1650 .....(1) B - G = 400 .....(2) From (1) & (2), we get 2B = 2050 => B = 1025 => G = 1650 - 1025 = 625 Hence, the % of girls = 625 x 100/1650 => 38% (approx).
Q: A boat whose speed in still water is 9 kmph, goes 12 km downstream and comes back in 3 hrs. Find the speed of the stream? 1214 05b5cc6bfe4d2b4197774da7e
5b5cc6bfe4d2b4197774da7e- 11 kmphfalse
- 23 kmphtrue
- 35 kmphfalse
- 44 kmphfalse
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Answer : 2. "3 kmph"
Explanation :
Answer: B) 3 kmph Explanation: Let the speed of the stream = x kmph From the given data, 129+x+129-x=3 hrs 3x2 = 27 => x = 3 kmph Therefore, the speed of the stream = 3 kmph