Quantitative Aptitude Practice Question and Answer
8Q: A train is moving and crossing a man who is running on a platform of 100 m at a speed of 8 kmph in the direction of the train, in 9 sec. If the speed of the train is 74 kmph. Find the length of the train ? 1361 05b5cc6c3e4d2b4197774dc27
5b5cc6c3e4d2b4197774dc27- 1202 mtsfalse
- 2188 mtsfalse
- 3165 mtstrue
- 4156 mtsfalse
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Answer : 3. "165 mts"
Explanation :
Answer: C) 165 mts Explanation: Let the length of the train = L mts Relative speed of train and man = 74 - 8 = 66 kmph = 66 x 5/18 m/s => 66 x 5/18 = L/9 => L = 165 mts.
Q: Two dice are rolled simultaneously. Find the probability of getting the sum of numbers on the on the two faces divisible by 3 or 4? 1357 05b5cc6bbe4d2b4197774d811
5b5cc6bbe4d2b4197774d811- 13/7false
- 27/11false
- 35/9true
- 46/13false
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Answer : 3. "5/9"
Explanation :
Answer: C) 5/9 Explanation: Here n(S) = 6 x 6 = 36 E={(1,2),(1,5),(2,1),(2,4),(3,3),(3,6),(4,2),(4,5),(5,1),(5,4),(6,3) ,(6,6),(1,3),(2,2),(2,6),(3,1),(3,5), (4,4),(5,3),(6,2)} => n(E)=20 Required Probability n(P) = n(E)/n(S) = 20/36 = 5/9.
Q: If two dice are thrown together, the probability of getting an even number on one die and an odd number on the other is ? 1353 05b5cc6ebe4d2b4197774ee64
5b5cc6ebe4d2b4197774ee64- 11false
- 21/2true
- 30false
- 43/5false
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Answer : 2. "1/2"
Explanation :
Answer: B) 1/2 Explanation: The number of exhaustive outcomes is 36.Let E be the event of getting an even number on one die and an odd number on the other. Let the event of getting either both even or both odd then = 18/36 = 1/2P(E) = 1 - 1/2 = 1/2.
Q: Simplify 413 + 215 + 414 = ? 1351 05b5cc6afe4d2b4197774d235
5b5cc6afe4d2b4197774d235- 110 47/60true
- 211 45/73false
- 311 47/36false
- 410 35/48false
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Answer : 1. "10 47/60"
Explanation :
Answer: A) 10 47/60 Explanation: The given equation is in Mixed fraction. Now to solve this type of fractions, 413 + 215 + 414 =?? = 4 + 2 + 4 + 13 + 15 + 14 ? = 10 + 4760? = 104760
Q: In how many different ways could couples be picked from 6 men and 9 women ? 1347 05b5cc728e4d2b4197774f728
5b5cc728e4d2b4197774f728- 126false
- 254true
- 352false
- 428false
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Answer : 2. "54"
Explanation :
Answer: B) 54 Explanation: Number of mens = 8 Number of womens = 5 Different ways could couples be picked = C16× 9C1 = 9 x 6 = 54 ways.
Q: 4 men and 6 women can complete a work in 8 days, while 3 men and 7 women can complete it in 10 days. In how many days will 10 women complete it ? 1343 05b5cc6dfe4d2b4197774eb02
5b5cc6dfe4d2b4197774eb02- 140 daystrue
- 236 daysfalse
- 332 daysfalse
- 434 daysfalse
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Answer : 1. "40 days"
Explanation :
Answer: A) 40 days Explanation: Let 1 man's 1 day work = x and 1 woman's 1 day work = y.Then, 4x + 6y = 1/8 and 3x + 7y = 1/10Solving these two equations, we get:x = 11/400 and y = 1/40010 woman's 1 day work = (1/400 x 10) = 1/40. Hence, 10 women will complete the work in 40 days.
Q: Two persons start running simultaneously around a circular track of length 600 m from the same point at speeds of 25 kmph and 35 kmph. When will they meet for the first time any where on the track ? 1342 05b5cc6d3e4d2b4197774e54a
5b5cc6d3e4d2b4197774e54a- 154 secfalse
- 236 sectrue
- 372 secfalse
- 411 secfalse
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Answer : 2. "36 sec"
Explanation :
Answer: B) 36 sec Explanation: Time taken to meet the first time = length of track/relative speed Given the length of the track is 600 m The relative speed = 25 + 35 = 60 kmph = 60 x 5/18 m Therefore Time = 60025+35518= 600/60 x (18/5) = 36 sec.
Q: Uma sold an article for 3400 and got a profit of 25%. If he had sold the article for Rs. 3265. How much profit% would Uma have got ? 1338 05b5cc6c7e4d2b4197774deb4
5b5cc6c7e4d2b4197774deb4- 122%false
- 227%false
- 320%true
- 418%false
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Answer : 3. "20%"
Explanation :
Answer: C) 20% Explanation: Given 125% ---- 3400 => 100% ---- ? => ? = 3400x100/125 = 2720 => Cost price of the article = Rs. 2720 Profit when article sold at Rs. 3265 = 3265 - 2720 = 545 Hence, Profit% = Gain x 100/cost price => P% = 545 x 100/2720 => P% = 20%

