Quantitative Aptitude Practice Question and Answer
8Q: The average marks of a student in 7 subjects is 85. His average marks in 6 subjects except English is 83. What is his marks in English ? 1510 05b5cc6c2e4d2b4197774dbf5
5b5cc6c2e4d2b4197774dbf5- 197true
- 298false
- 392false
- 493false
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Answer : 1. "97"
Explanation :
Answer: A) 97 Explanation: Marks in English = 85×7 – 83×6 = 595 – 498 = 97
Q: In how many ways can the letters of the word 'LEADER' be arranged ? 1510 05b5cc71ee4d2b4197774f58b
5b5cc71ee4d2b4197774f58b- 1360true
- 2420false
- 3576false
- 4220false
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Answer : 1. "360"
Explanation :
Answer: A) 360 Explanation: No. of letters in the word = 6No. of 'E' repeated = 2Total No. of arrangement = 6!/2! = 360
Q: You drive to the store at 20 kmph and return by the same route at 30 kmph. Discounting the time spent at the store, what was your average speed ? 1509 05b5cc745e4d2b4197774fa4a
5b5cc745e4d2b4197774fa4a- 125 kmphfalse
- 224 kmphtrue
- 326 kmphfalse
- 422 kmphfalse
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Answer : 2. "24 kmph"
Explanation :
Answer: B) 24 kmph Explanation: Average speed=total distance/total timeLet distance to store be Kthen, total time =(K/20)+(K/30)=K/12and, total time =(2K)so average speed= 2K / (K/12) = 24kmph.
Q: 3 : 12 :: 5 : ? 1502 05b5cc6b9e4d2b4197774d702
5b5cc6b9e4d2b4197774d702- 117false
- 230true
- 326false
- 432false
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Answer : 2. "30"
Explanation :
Answer: B) 30 Explanation: 332 + 3 = 12552 + 5 = 30
Q: A can do a work in 9 days, B can do a work in 7 days, C can do a work in 5 days. A works on the first day, B works on the second day and C on the third day respectively that is they work on alternate days. When will they finish the work ? 1496 05b5cc73de4d2b4197774f94d
5b5cc73de4d2b4197774f94d- 1[7 + (215/345)] daysfalse
- 2[6 + (11/215)] daysfalse
- 3[6 + (261/315)] daystrue
- 4[5 + (112/351)] daysfalse
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Answer : 3. "[6 + (261/315)] days"
Explanation :
Answer: C) [6 + (261/315)] days Explanation: After day 1, A finishes 1/9 of the work. After day 2, B finishes 1/7 more of the total work. (1/9) + (1/7) is finished. After day 3, C finishes 1/5 more of total work. Total finished is 143/315. So, after day 6, total work finished is 286/315. Now remaining work = 29 /315 On day 7, A will work again Work will be completed on day 7 when A is working. He must finish 29/315 of total remaining work. Since he takes 9 days to finish the total task, he will need 261/315 of the day. Total days required is 6 + (261/315) days.
Q: Two trains running in opposite directions cross a pole placed on the platform in 47 seconds and 31 seconds respectively. If they cross each other in 33 seconds, what is the ratio of their speeds? 1493 05b5cc764e4d2b4197774fd85
5b5cc764e4d2b4197774fd85- 11:7true
- 27:1false
- 32:3false
- 43:2false
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Answer : 1. "1:7"
Explanation :
Answer: A) 1:7 Explanation: Let the speed of the trains be x and y respectively length of train1 = 47xlength of train2 = 31yRelative speed= x + yTime taken to cross each other = 33 s=> 47x+31yx+y= 33=> (47x + 31 y) = 33(x + y)=> 14x = 2y=> x/y = 2/14 = 1/7 = 1:7
Q: Two dice are rolled simultaneously. Find the probability of getting the sum of numbers on the on the two faces divisible by 3 or 4? 1492 05b5cc6bbe4d2b4197774d811
5b5cc6bbe4d2b4197774d811- 13/7false
- 27/11false
- 35/9true
- 46/13false
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Answer : 3. "5/9"
Explanation :
Answer: C) 5/9 Explanation: Here n(S) = 6 x 6 = 36 E={(1,2),(1,5),(2,1),(2,4),(3,3),(3,6),(4,2),(4,5),(5,1),(5,4),(6,3) ,(6,6),(1,3),(2,2),(2,6),(3,1),(3,5), (4,4),(5,3),(6,2)} => n(E)=20 Required Probability n(P) = n(E)/n(S) = 20/36 = 5/9.
Q: How many words can be formed with or without meaning by using three letters out of k, l, m, n, o without repetition of alphabets. 1492 05b5cc6abe4d2b4197774d058
5b5cc6abe4d2b4197774d058- 160true
- 2120false
- 3240false
- 430false
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Answer : 1. "60"
Explanation :
Answer: A) 60 Explanation: Given letters are k, l, m, n, o = 5 number of letters to be in the words = 3 Total number of words that can be formed from these 5 letters taken 3 at a time without repetation of letters = 5P3 ways. ⇒ 5P3 = 5 x 4 x 3 = 60 words.