Quantitative Aptitude Practice Question and Answer
8Q: Three friends, P, Q and R started a partnership business investing money in the ratio of 5 : 4 : 2 respectively for a period of 3 years. What is the amount received by P as his share in the total profit ? a. Total amount invested in the business in Rs. 22,000. b. Profit earned at the end of 3 years is 3/8 of the total investment. c. The average amount of profit earned per year is Rs. 2750. 3529 05b5cc70be4d2b4197774f2e1
5b5cc70be4d2b4197774f2e1- 1Only c is sufficientfalse
- 2Both a & b are sufficientfalse
- 3Both A & B gives resulttrue
- 4Nonefalse
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Answer : 3. "Both A & B gives result"
Explanation :
Answer: C) Both A & B gives result Explanation: a and b give, profit after 3 years = Rs.(3/8 x 22000) = Rs.8250. From c also, profit after 3 years = Rs. (2750 x 3) = Rs. 8250. ∴ P's share = Rs.(8250 x 5/11) = Rs. 3750. Thus, (either C is redundant) or (a and b are redundant).
Q: Find the number of factors of 9321 ? 3529 05b5cc736e4d2b4197774f832
5b5cc736e4d2b4197774f832- 14false
- 25false
- 37false
- 48true
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Answer : 4. "8"
Explanation :
Answer: D) 8 Explanation: 9321 = 3 x 13 x 239 = 31 x 13 1 x 239 1 ; add one to all the powers ie., (1+1) x (1+1) x (1+1)= 8 ; we get eight factors.
Q: In an exam, a candidate secured 504 marks out of the maximum mark of 'M'. If the maximum mark 'M' is converted into 800 marks, he would have secured 384 marks. What is the value of 'M' ? 3526 05b5cc6ebe4d2b4197774ee9b
5b5cc6ebe4d2b4197774ee9b- 1910false
- 21000false
- 3970false
- 4None of the abovetrue
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Answer : 4. "None of the above"
Explanation :
Answer: D) None of the above Explanation: 504/M = 384/800 (504 x 800) / 384 = M M = 1050
Q: If a trader sold two cars each at Rs. 325475 and gains 12% on the first and loses 12% on the second, then his profit or loss percent on the whole is ? 3517 05b5cc6ebe4d2b4197774ee78
5b5cc6ebe4d2b4197774ee78- 11.44% losstrue
- 214.4% lossfalse
- 30%false
- 414.4% profitfalse
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Answer : 1. "1.44% loss"
Explanation :
Answer: A) 1.44% loss Explanation: SP of each car is Rs. 325475, he gains 12% on first car and losses 12% on second car.In this case, there will be loss and percentage of loss is given by = [(profit%)(loss%)]/100 = (12)(12)/100 % = 1.44%
Q: Length of train A is 50 % more than the train B coming from its opposite direction. Speed of train A is 40 km/hour and that of for train B is 32 km/hour and they took 15 sec time to cross each other. Find the length of train B 3512 05d15fa5c5fdb2c68495d9df9
5d15fa5c5fdb2c68495d9df9- 1150 metrefalse
- 2120 metrefalse
- 3130 metrefalse
- 4180 metretrue
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Answer : 4. "180 metre"
Q: A Certain sum of money an amounts to Rs 2500 in a span Of 5 years and further to Rs.3000 in a span of 7 years at simple interest The sum is ? 3508 05b5cc73de4d2b4197774f972
5b5cc73de4d2b4197774f972- 1Rs. 1800false
- 2Rs. 2000false
- 3Rs. 1400false
- 4Rs. 1250true
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Answer : 4. "Rs. 1250"
Explanation :
Answer: D) Rs. 1250 Explanation: 2500 in 5th year and 3000 in 7th year So in between 2 years Rs. 500 is increased => for a year 500/2 = 250So, per year it is increasing Rs.250 then in 5 years => 250 x 5 = 1250Hence, the initial amount must be 2500 - 1250 = Rs. 1250
Q: The average age of a class is 19 years. While the average age of girls is 18 and that of boys is 21. If the number of girls in the class is 16, Find the number of Boys in the class? 3496 05b5cc6bce4d2b4197774d8a2
5b5cc6bce4d2b4197774d8a2- 112false
- 210false
- 38true
- 46false
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Answer : 3. "8"
Explanation :
Answer: C) 8 Explanation: Let the number of boys = x From the given data, => [21x + 16(18)]/(x+16) = 19 => 21x - 19x = 19(16) - 16(18) => 2x = 16 => x = 8 Therefore, the number of boys in the class = 8.
Q: A milkman claims to sell milk at its cost price, still, he is making a profit of 30% since he has mixed some amount of water in the milk. What is the % of milk in the mixture? 3495 05b5cc6bbe4d2b4197774d844
5b5cc6bbe4d2b4197774d844- 171.02%false
- 276.92%true
- 363.22%false
- 486.42%false
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Answer : 2. "76.92%"
Explanation :
Answer: B) 76.92% Explanation: Let the milk he bought is 1000 ml Let C.P of 1000 ml is Rs. 100 Here let he is mixing K ml of water He is getting 30% profit => Now, the selling price is also Rs. 100 for 1000 ml => 100 : K% = 100 : 30 10 : 3 is ratio of milk to water => Percentage of milk = 10 x 100/13 = 1000/13 = 76.92%