Quantitative Aptitude Practice Question and Answer
8Q: Two goods trains each 520 m long, are running in opposite directions on parallel tracks. Their speeds are 42 km/hr and 36 km/hr respectively. Find the time taken by the slower train to cross the driver of the faster one ? 3142 05b5cc76fe4d2b4197774ff3f
5b5cc76fe4d2b4197774ff3f- 160 secfalse
- 248 sectrue
- 345 secfalse
- 434 secfalse
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Answer : 2. "48 sec"
Explanation :
Answer: B) 48 sec Explanation: Relative speed = 42 + 36 = 78 km/hr = 653 m/s Distance = (520 + 520) =1040 mts. Time = 1040×365= 48 sec
Q: A train moving at 2/3 rd of its normal speed reaches its destination 20 minutes late. Find the normal time taken ? 3135 05b5cc71ee4d2b4197774f57c
5b5cc71ee4d2b4197774f57c- 14/3 hrsfalse
- 22/3 hrstrue
- 33/2 hrsfalse
- 41/4 hrsfalse
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Answer : 2. "2/3 hrs"
Explanation :
Answer: B) 2/3 hrs Explanation: Let the original speed and time is S and Tthen distance = S x TNow the speed changes to 2/3S and T is T+20As the distance is sameS x T = 2/3Sx(T+20)solving this we get t = 40 minutes =40/60 = 2/3 hour
Q: Amith can row a boat d km upstream and the same distance downstream in 5 hours 15 minutes. Also, he can row the boat 2d km upstream in 7 hours. How long will it take to row the same distance 2d km downstream for Amith ? 3134 05b5cc6c3e4d2b4197774dc63
5b5cc6c3e4d2b4197774dc63- 14 hrs 10 minfalse
- 23 hrs 15 minfalse
- 33 hrs 30 mintrue
- 44 hrs 1 minfalse
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Answer : 3. "3 hrs 30 min"
Explanation :
Answer: C) 3 hrs 30 min Explanation: Let the speed of boat and stream be x and y kmph respectively. According to question d/x+y + d/x-y = 5h 15m or 21/4 hrs ......(i) and 2d/x-y = 7...... (ii) From eq. (i) and (ii) 2d/x+y = 7/2 Hence, Amith will take to row 2d km distance downstream in 7/2 hrs = 3.5 hrs = 3 hrs 30 min.
Q: Find the odd one out of the following number series? 9 5 6 14 56 488 3128 05b5cc66de4d2b4197774bfb0
5b5cc66de4d2b4197774bfb0- 156true
- 26false
- 314false
- 45false
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Answer : 1. "56"
Explanation :
Answer: A) 56 Explanation: The given number series follows a pattern that, 9 9 x 0.5 + 0.5 = 5 5 x 1 + 1 = 6 6 x 2 + 2 = 14 14 x 4 + 4 = 60 (not equals to 56) 60 x 8 + 8 = 488. Hence, the odd one in the given number series is 56.
Q: Rs. 7444 is divided among 5 ladies, 3 gents and 3 girls. The ratio of share of a lady, a gents and a girl is 7: 4: 3. What is the share of gents ? 3127 05b5cc741e4d2b4197774f9cc
5b5cc741e4d2b4197774f9cc- 1Rs. 1595.14true
- 2Rs. 1793.4false
- 3Rs. 595.14false
- 4Rs. 1551.5false
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Answer : 1. "Rs. 1595.14"
Explanation :
Answer: A) Rs. 1595.14 Explanation: Ratio of the share of a lady, a gents and a girl is 7 : 4 : 3No of ladies, gents and girls are 5, 3, 3Thus effective ratio of ladies, gents and girls is 7 x 5 : 4 x 3 : 3 x 3 = 35 : 12 : 9so part of gents = (12/56) x 7444 = Rs. 1595.142so part of 1 gents = 1595.142/3 = Rs. 531.71.
Q: If the rate increases by 2%, the simple interest received on a sum of money increases by Rs. 108. If the time period is increased by 2 years, the simple interest on the same sum increases by Rs.180. The sum is ? 3121 05b5cc767e4d2b4197774fe0b
5b5cc767e4d2b4197774fe0b- 1Rs. 540false
- 2Rs. 415false
- 3Rs. 404false
- 4Data is not sufficienttrue
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Answer : 4. "Data is not sufficient"
Explanation :
Answer: D) Data is not sufficient Explanation: Let the sum be Rs. p, rate be R% p.a. and time be T years. Then, P×T×(R+2)100-P×T×R100=108 ⇒2PT= 10800 ...... (1) And, P×R×(T+2)100-P×R×T100=180 ⇒2PR = 18000 ......(2) Clearly, from (1) and (2), we cannot find the value of pSo, the data is not sufficient.
Q: Find the next number in the series 143 143 136 110 ? 3113 05b5cc6b6e4d2b4197774d5a8
5b5cc6b6e4d2b4197774d5a8- 191false
- 235false
- 347true
- 469false
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Answer : 3. "47"
Explanation :
Answer: C) 47 Explanation: The next number in the series is 143 143 136 110 0 7 26 (Differences) 13 - 1 , 23 - 1, 33 - 1, 43 - 1,...Now the next number is given by110 - (43 - 1) = 110 - 63 = 47.
Q: The circumferences of two circles are 264 meters and 352 meters. Find the difference between the areas of the larger and the smaller circles ? 3106 05b5cc6dee4d2b4197774ea79
5b5cc6dee4d2b4197774ea79- 12413 sq.mfalse
- 21234 sq.mfalse
- 34312 sq.mtrue
- 42143 sq.mfalse
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Answer : 3. "4312 sq.m"
Explanation :
Answer: C) 4312 sq.m Explanation: Let the radii of the smaller and the larger circles be 's' m and 'l' m respectively. 2πs = 264 and 2πl = 352 s = 2642π and l = 3522π Difference between the areas =πl2-πs2 = π1762π2-1322π2 = 1762π-1322π = (176 - 132)(176 + 132) / π = (44 x 308) / (22/7) = 4312 sq.m