Quantitative Aptitude Practice Question and Answer

Q: Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 4 or 15 ? 1430 0

  • 1
    6/19
    Correct
    Wrong
  • 2
    3/10
    Correct
    Wrong
  • 3
    7/10
    Correct
    Wrong
  • 4
    6/17
    Correct
    Wrong
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Answer : 2. "3/10"
Explanation :

Answer: B) 3/10 Explanation: Here, S = {1, 2, 3, 4, ...., 19, 20}=> n(s) = 20Let E = event of getting a multiple of 4 or 15 =multiples od 4 are {4, 8, 12, 16, 20}And multiples of 15 means multiples of 3 and 5= {3, 6 , 9, 12, 15, 18, 5, 10, 15, 20}.= the common multiple is only (15).=> E = n(E)= 6Required Probability = P(E) = n(E)/n(S) = 6/20 = 3/10.

Q: Rs. 7444 is divided among 5 ladies, 3 gents and 3 girls. The ratio of share of a lady, a gents and a girl is 7: 4: 3. What is the share of gents ? 3561 0

  • 1
    Rs. 1595.14
    Correct
    Wrong
  • 2
    Rs. 1793.4
    Correct
    Wrong
  • 3
    Rs. 595.14
    Correct
    Wrong
  • 4
    Rs. 1551.5
    Correct
    Wrong
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Answer : 1. "Rs. 1595.14"
Explanation :

Answer: A) Rs. 1595.14 Explanation: Ratio of the share of a lady, a gents and a girl is 7 : 4 : 3No of ladies, gents and girls are 5, 3, 3Thus effective ratio of ladies, gents and girls is 7 x 5 : 4 x 3 : 3 x 3 = 35 : 12 : 9so part of gents = (12/56) x 7444 = Rs. 1595.142so part of 1 gents = 1595.142/3 = Rs. 531.71.

Q: The ages of Anushka, Kajal and Charu latha together are 57 years. Bharti is thrice as old as Anushka and Charu latha is 12 years older than Anushka. Then, the respective age of Anushka, Kajal and Charu latha is ? 3446 0

  • 1
    27, 9, 21
    Correct
    Wrong
  • 2
    9, 21, 27
    Correct
    Wrong
  • 3
    21, 27, 9
    Correct
    Wrong
  • 4
    9, 27, 21
    Correct
    Wrong
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Answer : 4. "9, 27, 21"
Explanation :

Answer: D) 9, 27, 21 Explanation: Let Anushka age = XCharu latha 12 yrs older than Anushka so Charu latha age = x+12Kajal is thrice as old as Anushka so Kajal age = 3xThe ages of Anushka, Kajal and Charu latha together are 57 yearsi.e x + (x+12) + 3x = 57=> 5x = 45:- x = 9Anushka age = 9Kajal age = 3x = 27Charu latha age = x+12 = 21

Q: When a number is divided by 138 the remainder is 26. What will be the remainder if the same number is divided by 23 ? 1501 0

  • 1
    4
    Correct
    Wrong
  • 2
    6
    Correct
    Wrong
  • 3
    3
    Correct
    Wrong
  • 4
    1
    Correct
    Wrong
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Answer : 3. "3"
Explanation :

Answer: C) 3 Explanation: Number = quotient x divisor + remainder;so, herenumber = 138 k + 26=> (23 x 6k) + (23+3)=> 23(6k+1)+3so, remainder is 3.

Q: A supplier supplies cartridges to a news paper publishing house. He earns a profit of 25% by selling cartridges for Rs. 1540. Find the cost price of the Cartridges ? 3160 0

  • 1
    Rs. 1100
    Correct
    Wrong
  • 2
    Rs. 1793.4
    Correct
    Wrong
  • 3
    Rs. 1440
    Correct
    Wrong
  • 4
    Rs. 1232
    Correct
    Wrong
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Answer : 4. "Rs. 1232"
Explanation :

Answer: D) Rs. 1232 Explanation: Let Cost Price(C.P) = Pgain% = {(S.P-C.P)/C.P} x 10025 = {(1540-P)/P} x 10025/100 = (1540-P)/P=> P = 4(1540)-4P=> 5P = 4(1540)=> P = 1232So, Cost Price = Rs. 1232

Q: On a school’s Annual day sweets were to be equally distributed amongst 112 children. But on that particular day, 32 children were absent. Thus the remaining children got 6 extra sweets. How many sweets was each child originally supposed to get ? 2185 0

  • 1
    14
    Correct
    Wrong
  • 2
    16
    Correct
    Wrong
  • 3
    12
    Correct
    Wrong
  • 4
    15
    Correct
    Wrong
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Answer : 4. "15"
Explanation :

Answer: D) 15 Explanation: Let 'K' be the total number of sweets.Given total number of students = 112If sweets are distributed among 112 children,Let number of sweets each student gets = 'L' => K/112 = L ....(1)But on that day students absent = 32 => remaining = 112 - 32 = 80Then, each student gets '6' sweets extra. => K/80 = L + 6 ....(2)from (1) K = 112L substitute in (2), we get112L = 80L + 48032L = 480L = 15 Therefore, 15 sweets were each student originally supposed to get.

Q: A company requires 12,100 strength. Present employees are 400 ladies and 6400 gents. To reach the target how many ladies required to maintain the same ratio ? 4505 0

  • 1
    400
    Correct
    Wrong
  • 2
    600
    Correct
    Wrong
  • 3
    900
    Correct
    Wrong
  • 4
    700
    Correct
    Wrong
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Answer : 3. "900"
Explanation :

Answer: C) 900 Explanation: 6,400 gents, 2400 ladies in that company.So total 8,800employees.for 8,800 employees, we want 2400 ladies.for 12,100employees we want how many ladies ?=> (12,100/8,800) x 2400 = 3300.So we want 3300 - 2400 = 900 more ladies.

Q: A secret can be told to only 3 persons in 3 minutes. Each person in turn tells 3 other persons in the next 3 minutes and the processes continues accordingly. In 30 minutes how many persons can be told this secret in this way ? 2721 0

  • 1
    88572
    Correct
    Wrong
  • 2
    77854
    Correct
    Wrong
  • 3
    99584
    Correct
    Wrong
  • 4
    55654
    Correct
    Wrong
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Answer : 1. "88572"
Explanation :

Answer: A) 88572 Explanation: Given a secret is told to 3 persons in 3 minutes.And if the process continues with each person saying 3 other persons,In 30 minutes => the rocess for 10 times because each person time is 3 minutes.Required number of persons = 3 + 32 + 33 + .... + 39 + 310   Now it forms a geometric progression,   Sum to n terms is S = arn - 1r - 1   Here a = 3, r = 3  => 59048 x 3 /2   = 88572.

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