Quantitative Aptitude Practice Question and Answer
8Q: A person takes a loan of Rs. 200 at 5% simple interest. He returns Rs.100 at the end of one year. In order clear his dues at the end of 2 years, he would pay : 3215 05b5cc77fe4d2b419777501d8
5b5cc77fe4d2b419777501d8- 1Rs. 100false
- 2Rs. 105false
- 3Rs. 115true
- 4Rs. 110false
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 3. "Rs. 115"
Explanation :
Answer: C) Rs. 115 Explanation: Amount to be paid = Rs.100+200×5×1100+100×5×1100= Rs. 115.
Q: How many prime numbers exist in 65×359×113 ? 3214 05b5cc77fe4d2b419777501ab
5b5cc77fe4d2b419777501ab- 129false
- 231true
- 333false
- 427false
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 2. "31"
Explanation :
Answer: B) 31 Explanation: Given 65×359×113 ⇒2×35×5×79×113 ⇒25×35×59×79×113 Thus, there are (5 + 5 + 9 + 9 + 3)= 31 prime numbers.
Q: Simplify the following : 373+353+283-3x37x35x28372+352+282-37x35-35x28-37x28 ? 3210 05b5cc6cae4d2b4197774dffc
5b5cc6cae4d2b4197774dffc- 1100true
- 21false
- 34false
- 40false
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 1. "100"
Explanation :
Answer: A) 100 Explanation: Given 373+353+283-3x37x35x28372+352+282-37x35-35x28-37x28 It is in the form of a3+b3+c3-3abca2+b2+c2-ab-bc-ca= a + b + c Here a = 37, b = 35 & c = 28 => a + b + c = 37 + 35 + 28 = 100 Therefore, = 100
Q: The concentration of glucose in three different mixtures (glucose and alcohol) is 12,35 and 45 respectively. If 2 litres, 3 litres and 1 litre are taken from these three different vessels and mixed. What is the ratio of glucose and alcohol in the new mixture? 3205 05b5cc6b9e4d2b4197774d76b
5b5cc6b9e4d2b4197774d76b- 13:2true
- 24:3false
- 32:3false
- 43:4false
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 1. "3:2"
Explanation :
Answer: A) 3:2 Explanation: Concentration of glucose are in the ratio = 12:35:45 Quantity of glucose taken from A = 1 liter out of 2 Quantity of glucose taken from B = 3/5 x 3 = 1.5 lit Quantity of glucose taken from C = 0.8 lit So, total quantity of glucose taken from A,B and C = 3.6 lit So, quantity of alcohol = (2 + 3 + 1) - 3.6 = 2.4 lit Ratio of glucose to alcohol = 3.6/2.4 = 3:2
Q: A bus is running at 75 kmph without any stoppage. But, with stoppages its average speed is 60 kmph. Find the time of stoppage by bus per hour. 3189 05d15ed1d5fdb2c68495d9dee
5d15ed1d5fdb2c68495d9dee- 110 minutesfalse
- 215 minutesfalse
- 312 minutestrue
- 420 minutesfalse
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 3. "12 minutes"
Q: There are several peacocks and deers in a cage (with no other types of animals). There are 72 heads and 200 feet inside the cage. How many peacocks are there, and how many deers ? 3188 05b5cc73de4d2b4197774f95d
5b5cc73de4d2b4197774f95d- 142 & 24false
- 238 & 26false
- 336 & 24false
- 444 & 28true
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 4. "44 & 28"
Explanation :
Answer: D) 44 & 28 Explanation: Letx = peacocks y = deers 2x + 4y = 200 x + y = 72 y = 72 - x 2x + 288 - 4x = 200 x = 44 peacocks y = 28 deers
Q: Mr. Khanna took a loan of Rs 10,000 on simple interest for two years at the rate 3% per annum. The total amount that he will be paying as interest in 2 year is 3% of his monthly salary. What his monthly salary?
3184 05d4a9a6c11160f2052371025
5d4a9a6c11160f2052371025- 1Rs 30,000false
- 2Rs 16,000false
- 3Rs 20,000true
- 4Rs 12,000false
- 5None of thesefalse
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 3. "Rs 20,000"
Explanation :
3% of SI=PRT/100
10,000*3*2/100= 3 of x
then x =20,000
Q: P alone can complete a piece of work in 6 days. Work done by Q alone in one day is equal to one-third of the work done by P alone in one day. In how many days can the work be completed if P and Q work together ? 3173 05b5cc6d8e4d2b4197774e737
5b5cc6d8e4d2b4197774e737- 15 (2/3)false
- 26 (3/4 )false
- 34 (1/2)true
- 43false
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 3. "4 (1/2)"
Explanation :
Answer: C) 4 (1/2) Explanation: Work done by P alone in one day = 1/6th of the total work done by Q alone in one day = 1/3(of that done by P in one day) = 1/3(1/6 of the total) = 1/18 of the total. Work done by P and Q, working together in one day = 1/6 + 1/18 = 4/18 = 2/9 They would take 9/2 days = 4 (1/2) days to complete the work working together.