Quantitative Aptitude Practice Question and Answer
8Q: A bus is running at 75 kmph without any stoppage. But, with stoppages its average speed is 60 kmph. Find the time of stoppage by bus per hour. 2639 05d15ed1d5fdb2c68495d9dee
5d15ed1d5fdb2c68495d9dee- 110 minutesfalse
- 215 minutesfalse
- 312 minutestrue
- 420 minutesfalse
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Answer : 3. "12 minutes"
Q: A man can row against the current three fourth of a kilometer in 15 min and returns same distance in 10 min, then ratio of his speed to that of current? 2634 05b5cc6a8e4d2b4197774ce95
5b5cc6a8e4d2b4197774ce95- 15:1true
- 23:1false
- 34:1false
- 42:1false
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Answer : 1. "5:1"
Explanation :
Answer: A) 5:1 Explanation: Let the speed of the man in still water = p kmph Speed of the current = s kmph Now, according to the questions (p + s) x 10 = (p - s) x 15 2p + 2s = 3p - 3s => p : s = 5 : 1 Hence, ratio of his speed to that of current = 5:1.
Q: An alloy contains gold and silver in the ratio 5 : 8 and another alloy contains gold and silver in the ratio 5 : 3. If equal amount of both the alloys are melted together, then the ratio of gold and silver in the resulting alloy is ? 2624 05b5cc67be4d2b4197774c1eb
5b5cc67be4d2b4197774c1eb- 1113/108false
- 2105/103true
- 3108/115false
- 4103/113false
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Answer : 2. "105/103"
Explanation :
Answer: B) 105/103 Explanation: As given equal amounts of alloys are melted, let it be 1 kg. Required ratio of gold and silver = 513 + 58813 + 38 = 105103. Hence, ratio of gold and silver in the resulting alloy = 105/103.
Q: Althaf borrows Rs. 1500 from two moneylenders. He pays interest at the rate of 12% per annum for one loan and at the rate of 14% per annum for the other. The total interest he pays for the entire year is Rs. 186. How much does he borrow at the rate of 12% ? 2622 05b5cc6fee4d2b4197774f166
5b5cc6fee4d2b4197774f166- 1Rs. 300false
- 2Rs. 400false
- 3Rs. 1200true
- 4Rs. 1100false
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Answer : 3. "Rs. 1200"
Explanation :
Answer: C) Rs. 1200 Explanation: Let Althaf lent Rs. A at 14% per year.Hence, Money lent at 12% = (1500-A);Given, total interest = Rs. 186.{(A x 14x 1)/100} + {[(1500-A) x 12 x 1/100]} = 186;14A/100 + (18000 -12A)/100 = 186;14A + 18000 - 12A = 186x100;2A = 18600-18000;A = 600/2 = Rs. 300.Hence, money lent at 12% = 1500-300 = Rs. 1200.
Q: At a certain rate of interest the compound interest of 3 years and simple interest of 5 years for certain sum of money is respectively Rs. 1513.2 and Rs. 2400. Find the common rate of interest per annum ? 2611 05b5cc6cde4d2b4197774e1cc
5b5cc6cde4d2b4197774e1cc- 15%true
- 26%false
- 34%false
- 43%false
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Answer : 1. "5%"
Explanation :
Answer: A) 5% Explanation: Given compound interest for 3 years = Rs. 1513.2 and simple interest for 5 years = Rs. 2400 Now, we know that C.I = P1+R100n - 1 => 1513.2 = P1+R1003 - 1 ...........(A) And S.I = PTR/100 => 2400 = P5R/100 ..................(B) By solving (A) & (B), we get R = 5%.
Q: 5 men and 3 boys can together cultivate a 23 acre field in 4 days and 3 men and 2 boys together can cultivate a 7 acre field in 2 days. How many boys will be needed together with 7 men, if they cultivate 45 acre of field in 6 days. 2609 05b5cc69de4d2b4197774c8ad
5b5cc69de4d2b4197774c8ad- 16false
- 24false
- 32true
- 43false
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Answer : 3. "2"
Explanation :
Answer: C) 2 Explanation: Let work done by 1 man in i day be m and Let work done by 1 boy in 1 day be b From the given data, 4(5m + 3b) = 23 20m + 12b = 23....(1) 2(3m + 2b) = 7 6m + 4b = 7 ....(2) By solving (1) & (2), we get m = 1, b = 1/4 Let the number of required boys = n 6(7 1 + n x 1/4) = 45 => n = 2.
Q: What approximate value should come in place of the question mark(?) in the following question?
105.003+307.993+ 215.630=?
2604 05d4aac9111160f205237393c
5d4aac9111160f205237393c105.003+307.993+ 215.630=?
- 1610false
- 2650false
- 3660false
- 4670false
- 5630true
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Answer : 5. "630"
Explanation :
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Q: 5% people of a village in India died by dengue, 15% of the remainder left the village on account of fear. If now the population is reduced to 3553, how much was it in the beginning ? 2602 05b5cc6e0e4d2b4197774eb5c
5b5cc6e0e4d2b4197774eb5c- 14400true
- 23100false
- 32800false
- 45600false
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Answer : 1. "4400"
Explanation :
Answer: A) 4400 Explanation: Let 'P' be the original population at the beginning P x (95/100) x (85/100) = 3553 P = 4400.