Quantitative Aptitude Practice Question and Answer
8Q: X can complete the work in 10 days, Y can do the same in 15 days. If they are hired for 5 days to do the work together, what is the work that left unfinished? 2116 05b5cc6bfe4d2b4197774da0a
5b5cc6bfe4d2b4197774da0a- 11/3false
- 22/3false
- 31/6true
- 45/6false
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Answer : 3. "1/6"
Explanation :
Answer: C) 1/6 Explanation: Given X can do in 10 days => 1 day work of X = 1/10 Y can do in 15 days => 1 day work of Y = 1/15 1day work of (X + Y) = 1/10 + 1/15 = 1/6 Given they are hired for 5 days => 5 days work of (X + Y) = 5 x 1/6 = 5/6 Therefore, Unfinished work = 1 - 5/6 = 1/6
Q: What approximate values should come in place of the question mark(?) in the following question?
2115 05d4ab07211160f2052373ec4
5d4ab07211160f2052373ec4- 157false
- 247true
- 367false
- 437false
- 527false
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Answer : 2. "47"
Q: K is 50% faster than L. If L starts at 9 A.M. and K starts at 10 A.M. L travels at a speed of 50 km/hr. If L and K are 300 kms apart, The time when they meet when they travel in opposite direction is ? 2113 05b5cc741e4d2b4197774f9e5
5b5cc741e4d2b4197774f9e5- 112 pmtrue
- 21 pmfalse
- 311 amfalse
- 411:30 amfalse
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Answer : 1. "12 pm"
Explanation :
Answer: A) 12 pm Explanation: let 't' be the time after which they met since L starts. Given K is 50% faster than L 50 t + 1.5*50(t-1) = 300 50 t +75 t = 300 + 75 t = 375 / 125 = 3 hrs past the time that L starts So they meet at (9 + 3)hrs = 12:00 noon.
Q: A man can row 6 kmph in still water. When the river is running at 1.2 kmph, it takes him 1 hour to row to a place and back. What is the total distance traveled by the man ? 2112 05b5cc6d7e4d2b4197774e728
5b5cc6d7e4d2b4197774e728- 14.58 kmsfalse
- 26.35 kmsfalse
- 35.76 kmstrue
- 45.24 kmsfalse
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Answer : 3. "5.76 kms"
Explanation :
Answer: C) 5.76 kms Explanation: Speed in still water = 6 kmph Stream speed = 1.2 kmph Down stream = 7.2 kmph Up Stream = 4.8 kmph x/7.2 + x/4.8 = 1 x = 2.88 Total Distance = 2.88 x 2 = 5.76 kms
Q: The product of two positive numbers is p. If each of the numbers is increased by 2, the new product is how much greater than twice the sum of the two original numbers ? 2111 05b5cc74ae4d2b4197774faae
5b5cc74ae4d2b4197774faae- 1p timesfalse
- 22p timesfalse
- 3(p + 4) timestrue
- 4(2p + 3) timesfalse
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Answer : 3. "(p + 4) times"
Explanation :
Answer: C) (p + 4) times Explanation: Let the two no's be a and b;Given product of the no's is p = ab;If the each nos is increased by 2 then the new product will be (a+2)(b+2) = ab + 2a + 2b + 4= ab + 2(a+b) + 4= p + 2(a+b) + 4Hence the new product is (p+4) times greater than twice the sum of the two original numbers.
Q: In a year, Holi was enjoyed on 6th March 9 AM and Deepawali was celebrated on 11th November 8 PM. The total time interval (in hours) between the two was ? 2109 05b5cc73ae4d2b4197774f8ab
5b5cc73ae4d2b4197774f8ab- 12101 hrsfalse
- 24125 hrsfalse
- 35124 hrsfalse
- 46011 hrstrue
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Answer : 4. "6011 hrs"
Explanation :
Answer: D) 6011 hrs Explanation: From March 6th to November 11th, there are 250 days and Thus 250 x 24 hoursSo from Mar 6th 9AM to Nov 11th 8PM, there will be 250 x 24 + 11 hours = 6011 hrs.
Q: Sonika invested an amount of Rs.5800 for 2 years. At what rate of compound interest will she get an amount of Rs.594.50 at the end of 2 years ? 2107 05b5cc73ae4d2b4197774f89c
5b5cc73ae4d2b4197774f89c- 16.5%false
- 26%false
- 35%true
- 44.5%false
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Answer : 3. "5%"
Explanation :
Answer: C) 5% Explanation: C.I = P1+r100t-1 594.5 = 58001+r1002-1 594.55800+1=1+r1002 r100=1.05-1=0.05=> r = 5 % .
Q: In how many ways word of 'GLACIOUS' can be arranged such that 'C' always comes at end? 2102 05b5cc626e4d2b4197774b825
5b5cc626e4d2b4197774b825- 13360false
- 25040true
- 3720false
- 41080false
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Answer : 2. "5040"
Explanation :
Answer: B) 5040 Explanation: Given word is GLACIOUS has 8 letters. => C is fixed in one of the 8 places Then, the remaining 7 letters can be arranged in 7! ways = 5040.