5 men and 4 women are to be seated in a row so that the women occupy the even places . How many such arrangements are possible?5

## Q: 5 men and 4 women are to be seated in a row so that the women occupy the even places . How many such arrangements are possible?

- 12880true
- 21440false
- 3720false
- 42020false

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## Answer : 1. "2880"

Explanation :

Answer: A) 2880 Explanation: There are total 9 places out of which 4 are even and rest 5 places are odd. 4 women can be arranged at 4 even places in 4! ways. and 5 men can be placed in remaining 5 places in 5! ways. Hence, the required number of permutations = 4! x 5! = 24 x 120 = 2880