Quantitative Aptitude Practice Question and Answer
8Q: 3 is what percent of 5? 1799 05b5cc64ae4d2b4197774bc0c
5b5cc64ae4d2b4197774bc0c- 145%false
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Answer : 2. "60%"
Explanation :
Answer: B) 60% Explanation: Here it is asked that 3 is what percent of 5 Let 3 is K percent of 5. => K x 5/100 = 3 => K = 300/5 = 60 Hence, 3 is 60% of 5.
Q: What will come in place of the question mark (?) in the following questions ? 22% of ? + 166.64 = 340 1799 05b5cc6fee4d2b4197774f102
5b5cc6fee4d2b4197774f102- 1788true
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Answer : 1. "788"
Explanation :
Answer: A) 788 Explanation: (kx22)/100 = 340 - 166.64 = 173.36 k = (173.36 x 100)/22 k = 788
Q: If y/(x - z) = (y + x)/z = x/y then find z : y : x ? 1799 05b5cc761e4d2b4197774fd4e
5b5cc761e4d2b4197774fd4e- 11:2:3false
- 23:2:4true
- 34:3:2false
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Answer : 2. "3:2:4"
Explanation :
Answer: B) 3:2:4 Explanation: Given, y/(x - z) = (y + x)/z = x/yyz = xy + x2 - yz - xz ....(1)Also xy = yx-z ⇒x2 -xz = y2 ....(2)Using (1) and (2), we get yz = xy - yz + y22yz = xy + y22z = x + y Only option (B) satisfies the equation.
Q: A, B and C can do a piece of work in 72, 48 and 36 days respectively. For first p/2 days, A & B work together and for next ((p+6))/3days all three worked together. Remaining 125/3% of work is completed by D in 10 days. If C & D worked together for p day then, what portion of work will be remained? 1798 05b5cc669e4d2b4197774bf4d
5b5cc669e4d2b4197774bf4d- 11/5false
- 21/6true
- 31/7false
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Answer : 2. "1/6"
Explanation :
Answer: B) 1/6 Explanation: Total work is given by L.C.M of 72, 48, 36 Total work = 144 units Efficieny of A = 144/72 = 2 units/day Efficieny of B = 144/48 = 3 units/day Efficieny of C = 144/36 = 4 units/day According to the given data, 2 x p/2 + 3 x p/2 + 2 x (p+6)/3 + 3 x (p+6)/3 + 4 x (p+6)/3 = 144 x (100 - 125/3) x 1/100 3p + 4.5p + 2p + 3p + 4p = 84 x 3 - 54 p = 198/16.5 p = 12 days. Now, efficency of D = (144 x 125/3 x 1/100)/10 = 6 unit/day (C+D) in p days = (4 + 6) x 12 = 120 unit Remained part of work = (144-120)/144 = 1/6.
Q: Sneha’s weight is 140% of Veena’s weight. Rina’s weight is 90% of Sana’s weight. Sana weighs twice as much as Veena. If Sneha’s weight is x% of Rina’s weight, then x is equal to: 1797 05b5cc699e4d2b4197774c750
5b5cc699e4d2b4197774c750- 1596/9false
- 2605/9false
- 3645/9false
- 4700/9true
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Answer : 4. "700/9"
Explanation :
Answer: D) 700/9 Explanation: Let Veena's weight = 1 kg Sana's weight = 2 kg Sneha's weight = 1.4 kg Rina's weight = 1.8 kg Now,according to the given data in the question, 1.8x100 = 1.4 x = 1.4 × 1001.8 = 7009 = 77 79.
Q: Tanks A and B are each in the shape of a right circular cylinder. The interior of tank A has a height of 10 meters and a circumference of 8 meters, and the interior of tank B has a height of 8 meters and a circumference of 10 meters. The capacity of tank A is what percent of the capacity of tank B ? 1797 05b5cc71ee4d2b4197774f568
5b5cc71ee4d2b4197774f568- 176%false
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Answer : 3. "80%"
Explanation :
Answer: C) 80% Explanation: circumference of A = 2πr = 8 => so r = 4πvolume = π×4π2×10 = 160πcircumference of B = 2πr = 10 => so r = 5πvolume = π×5π2×8 = 200πso ratio of capacities = 160/200 = 0.8 so capacity of A will be 80% of the capacity of B.
Q: There are 41 students in a class, number of girls is one more than number of guys. we need to form a team of four students. all four in the team cannot be from same gender. number of girls and guys in the team should NOT be equal. How many ways can such a team be made ? 1796 05b5cc709e4d2b4197774f262
5b5cc709e4d2b4197774f262- 149450false
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Answer : 2. "50540"
Explanation :
Answer: B) 50540 Explanation: Given G + B= 41 and B = G-1 Hence, G = 21 and B = 20Now we have 2 options, 1G and 3M (or) 3G and 1M(2G and 2M or 0G and 4M or 4G and oM are not allowed), Total : C121×C320+C321×C120= 50540 ways.
Q: A motorboat takes half time to cover a certain distance downstream than upstream. What is the ratio between rate of current and rate of boat in still water? 1793 05b5cc6afe4d2b4197774d1e7
5b5cc6afe4d2b4197774d1e7- 11 : 3true
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Answer : 1. "1 : 3"
Explanation :
Answer: A) 1 : 3 Explanation: Let the speed of the boat in still water is 'w' Speed of the current is 'c' Let the distance between two places is 'd' According to the question, motorboat takes half time to cover a certain distance downstream than upstream. dw+c = 12dw-c => 2w - 2c = w + c => w = 3c => c : w = 1 : 3 Hence, the ratio between rate of current(c) and rate of boat in still water(w) = 1 : 3