Quantitative Aptitude Practice Question and Answer
8Q: One-quarter of one-seventh of a land is sold for Rs. 30,000. What is the value of an four fifteenth of land ? 5305 05b5cc736e4d2b4197774f828
5b5cc736e4d2b4197774f828- 1Rs.1,92,000false
- 2Rs.2,24,000true
- 3Rs.1,26,000false
- 4Rs.3,42,000false
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Answer : 2. "Rs.2,24,000"
Explanation :
Answer: B) Rs.2,24,000 Explanation: One-quarter of one-seventh = 1/4 x 1/7= 1/28Now, 1/28 of a land costs = Rs. 30,000Thus, 8/35 of the land will cost = 30,000 x 28 x 4/15= Rs. 2,24,000.
Q: Find the odd man out of the number series? 18, 37, 76, 155, 314, 635 5303 05b5cc6a5e4d2b4197774cce0
5b5cc6a5e4d2b4197774cce0- 137false
- 2155false
- 3314false
- 4635true
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Answer : 4. "635"
Explanation :
Answer: D) 635 Explanation: Given Number series is 18 37 76 155 314 635 follows a pattern that, 18 18 x 2 +1 = 37 37 x 2 +2 = 76 76 x 2 +3 = 155 155 x 2 +4 = 314 314 x 2 +5 = 633 not 635 Hence, the odd man is 635.
Q: A cycle is sold for Rs.2070 at profit of 15%, at what profit of 15%, at what price it should be sold so as to earn 25% Profit. 5303 05d13299509a40f38019e53a2
5d13299509a40f38019e53a2- 12150false
- 22250true
- 32350false
- 42450false
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Answer : 2. "2250"
Q: Hari Ram’s present age is three times his son’s present age and two fifth of his father’s present age. The average of the present age of all of them is 46 years. What is the difference between Hari Ram’s son’s present age and Hari Ram’s father’s present age? 5291 05b5cc6b7e4d2b4197774d5d8
5b5cc6b7e4d2b4197774d5d8- 144 yrsfalse
- 256 yrsfalse
- 367 yrsfalse
- 478 yrstrue
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Answer : 4. "78 yrs"
Explanation :
Answer: D) 78 yrs Explanation: Let Hari Ram's present age = x Then, his son's age = x/3 Father's age = 5x/2 x + x3 + 52x3 = 46=> x = 36 yrs Now the required difference = 52x36 - 363 = 78 yrs
Q: Two boys and a girl can do a work in 5 days, while a boy and 2 girls can do it in 6 days. If the boy is paid at the rate of 28$ a week, what should be the wages of the girl a week ? 5279 05b5cc74ae4d2b4197774faa4
5b5cc74ae4d2b4197774faa4- 124 $false
- 222 $false
- 316 $true
- 414 $false
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Answer : 3. "16 $"
Explanation :
Answer: C) 16 $ Explanation: Let the 1 day work of a boy=b and a girl=g, then2b + g = 1/5 ---(i) andb + 2g = 1/6 ---(ii)On solving (i) & (ii), b=7/90, g=2/45As payment of work will be in proportion to capacity of work and a boy is paid $ 28/week, so a girl will be paid 28×245790 = 16 $.
Q: 56% of 225 + 20% of 150 = ? - 109 Find the value of '?' in the above equation 5202 05b5cc6bae4d2b4197774d7f8
5b5cc6bae4d2b4197774d7f8- 1264true
- 2220false
- 3241false
- 4Nonefalse
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Answer : 1. "264"
Explanation :
Answer: A) 264 Explanation: Given 56% of 225 + 20% of 150 = ? - 109 we know that a% of b = b% of a Now, 225% of 56 + 20% of 150 = ? - 109 200% of 56 + 25% of 56 + 20% of 150 = ? - 109 112 + 14 + 30 = ? - 109 ? = 112 + 14 + 30 + 109 ? = 264
Q: What was the day of the week on 17th June, 1998 ? 5201 75b5cc761e4d2b4197774fd16
5b5cc761e4d2b4197774fd16- 1Mondayfalse
- 2Tuesdayfalse
- 3Wednesdaytrue
- 4Fridayfalse
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Answer : 3. "Wednesday"
Explanation :
Answer: C) Wednesday Explanation: 17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)Odd days in 1600 years = 0Odd days in 300 years = 197 years has 24 leap years + 73 ordinary years.Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.Jan. Feb. March. April. May. June.(31 + 28 + 31 + 30 + 31 + 17) = 168 days168 days = 24 weeks = 0 odd day.Total number of odd days = (0 + 1 + 2 + 0) = 3.Given day is Wednesday.
Q: A man reaches his office 20 min late, if he walks from his home at 3 km per hour and reaches 30 min early if he walks 4 km per hour. How far is his office from his house ? 5153 05b5cc74ae4d2b4197774fa68
5b5cc74ae4d2b4197774fa68- 120 kmfalse
- 216 kmfalse
- 314 kmfalse
- 410 kmtrue
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Answer : 4. "10 km"
Explanation :
Answer: D) 10 km Explanation: Let distance = x km.Time taken at 3 kmph : dist/speed = x/3 = 20 min late.time taken at 4 kmph : x/4 = 30 min earlierdifference between time taken : 30-(-20) = 50 mins = 50/60 hours.x/3- x/4 = 50/60x/12 = 5/6x = 10 km.