Quantitative Aptitude Practice Question and Answer
8Q: Cost price of 21 objects is equal to selling price of 15 objects. What is the profit? 5422 05d132f44925caa2d5bbbff66
5d132f44925caa2d5bbbff66- 125%false
- 230%false
- 333%false
- 440%true
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Answer : 4. "40%"
Q: If (
5d1b1f6f1fc62311c773688d- 12:3false
- 21:2false
- 33:2true
- 42:1false
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Answer : 3. "3:2"
Q: Find the next number in the series 3, 4, 5, 5, 12, 13, 7, 24, 25, 8, 15, ... 5408 05b5cc771e4d2b4197774ffc6
5b5cc771e4d2b4197774ffc6- 126false
- 216false
- 317true
- 418false
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Answer : 3. "17"
Explanation :
Answer: C) 17 Explanation: The pattern is 32+42=52, 52+122=132, 72+242=252 The next number = 82+152=172 i.e. 17
Q: 30 Men contracts to complete a work in 50 days. But after 25 days, it is come to know that only 1/3rd of the work has been done. How many more workers are required to complete the work in time? 5393 25d149b7e97a68b089a7aa859
5d149b7e97a68b089a7aa859- 125false
- 230true
- 335false
- 440false
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Answer : 2. "30"
Q: A person takes 20 minutes more to cover a certain distance by decreasing his speed by 20%. What is the time taken to cover the distance at his original speed ? 5389 05b5cc6eee4d2b4197774eebe
5b5cc6eee4d2b4197774eebe- 11hrfalse
- 21 hr 20 mintrue
- 31 hr 10 minfalse
- 450 minfalse
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Answer : 2. "1 hr 20 min"
Explanation :
Answer: B) 1 hr 20 min Explanation: Let the distance and original speed be 'd' km and 'k' kmph respectively. d/0.8k - d/k = 20/60 => 5d/4k - d/k = 1/3 => (5d - 4d)/4k = 1/3 => d = 4/3 k Time taken to cover the distance at original speed = d/k = 4/3 hours = 1 hour 20 minutes.
Q: The number of females in the Marketing department are approximately what percent of the total employees in marketing and customer Relation department together?
5378 05d4aba5e11160f20523749fa
5d4aba5e11160f20523749fa- 126false
- 236false
- 36false
- 446false
- 516true
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Answer : 5. "16"
Q: The ratio of number of students taking admission in a organisation X and Y was 5:8. If 20% of students exceed in organisation X and 10% of students exceed in organisation Y, then new ratio of students is 5345 15d1b13e08a754124194a7564
5d1b13e08a754124194a7564- 115:22true
- 215:16false
- 35:4false
- 45:7false
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Answer : 1. "15:22"
Q: The average weight of 45 passengers in a bus is 52 kg. 5 of them whose average weight is 48 kg leave the bus and other 5 passengers whose average weight is 54 kg join the bus at the same stop. What is the new average weight of the bus? 5314 05b5cc6abe4d2b4197774d06c
5b5cc6abe4d2b4197774d06c- 154.21 kgsfalse
- 251.07 kgsfalse
- 352.66 kgstrue
- 453.45 kgsfalse
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Answer : 3. "52.66 kgs"
Explanation :
Answer: C) 52.66 kgs Explanation: Given total number of passengers in the bus = 45 First average weight of 45 passengers = 52 kgs Average weight of 5 passengers who leave bus = 48 Average weight of 5 passengers who joined the bus = 54 Therefore, the net average weight of the bus is given by = 45 x 52 - 5 x 48 + 5 x 5445 = 237045= 1583= 52.66 kgs.