Quantitative Aptitude Practice Question and Answer

Q: In How many ways can the letters of the word 'CAPITAL' be arranged in such a way that all the vowels always come together? 1638 0

  • 1
    360
    Correct
    Wrong
  • 2
    720
    Correct
    Wrong
  • 3
    120
    Correct
    Wrong
  • 4
    840
    Correct
    Wrong
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Answer : 1. "360"
Explanation :

Answer: A) 360 Explanation: CAPITAL = 7   Vowels = 3 (A, I, A)   Consonants = (C, P, T, L)   5 letters which can be arranged in  5P5=5!   Vowels A,I = 3!2!   No.of arrangements = 5! x 3!2!=360

Q: What will come in place of question mark (?) in the following number series? 4, 3, 4, 7, 15, ? 1637 0

  • 1
    42
    Correct
    Wrong
  • 2
    44
    Correct
    Wrong
  • 3
    53
    Correct
    Wrong
  • 4
    56
    Correct
    Wrong
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Answer : 2. "44"
Explanation :

Answer: B) 44 Explanation:   4             3             4             7               15        ? ×1-1      ×1+1       ×2-1       ×2+1           ×3-1   15x3 - 1 = 45 - 1 = 44

Q: 54, 60  LCM is 1635 0

  • 1
    600
    Correct
    Wrong
  • 2
    540
    Correct
    Wrong
  • 3
    60
    Correct
    Wrong
  • 4
    54
    Correct
    Wrong
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Answer : 2. "540"
Explanation :

Answer: B) 540 Explanation: Here the LCM of 54, 60 is   => 2 x 3 x 3 x 3 x 10 = 6 x 9 x 10 = 54 x 10 = 540.

Q: Two dice are rolled simultaneously. Find the probability of getting the sum of numbers on the on the two faces divisible by 3 or 4? 1634 0

  • 1
    3/7
    Correct
    Wrong
  • 2
    7/11
    Correct
    Wrong
  • 3
    5/9
    Correct
    Wrong
  • 4
    6/13
    Correct
    Wrong
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Answer : 3. "5/9"
Explanation :

Answer: C) 5/9 Explanation: Here n(S) = 6 x 6 = 36 E={(1,2),(1,5),(2,1),(2,4),(3,3),(3,6),(4,2),(4,5),(5,1),(5,4),(6,3) ,(6,6),(1,3),(2,2),(2,6),(3,1),(3,5), (4,4),(5,3),(6,2)} => n(E)=20 Required Probability n(P) = n(E)/n(S) = 20/36 = 5/9.

Q: In how many different ways could couples be picked from 6 men and 9 women ? 1629 0

  • 1
    26
    Correct
    Wrong
  • 2
    54
    Correct
    Wrong
  • 3
    52
    Correct
    Wrong
  • 4
    28
    Correct
    Wrong
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Answer : 2. "54"
Explanation :

Answer: B) 54 Explanation: Number of mens = 8 Number of womens = 5   Different ways could couples be picked = C16× 9C1 = 9 x 6 = 54 ways.

Q: A contractor undertake to finish a certain work in 124 days and employed 120 men. After 64 days, he found that he had already done 2/3 of the work. How many men can be discharged so that the work may finish in time ? 1621 0

  • 1
    64
    Correct
    Wrong
  • 2
    62
    Correct
    Wrong
  • 3
    58
    Correct
    Wrong
  • 4
    56
    Correct
    Wrong
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Answer : 4. "56"
Explanation :

Answer: D) 56 Explanation: Days remaining 124 – 64 = 60 days Remaining work = 1 - 2/3 = 1/3 Let men required men for working remaining days be 'm' So men required = (120 x 64)/2 = (m x 60)/1 => m = 64 Men discharge = 120 – 64 = 56 men.

Q: Find the regular polygon whose interior angel is 150 more than exterior angle. note the total sum of interior and exterior angle should be 180 at one point ? 1614 0

  • 1
    12
    Correct
    Wrong
  • 2
    24
    Correct
    Wrong
  • 3
    36
    Correct
    Wrong
  • 4
    6
    Correct
    Wrong
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Answer : 2. "24"
Explanation :

Answer: B) 24 Explanation: Sum of Interior angle is 180 .and it is given that interior angle is 150 more than exterior,so let exterior angle is x then interior will be x+150 now , interior + exterior =180x+150+x=180x=15 now , number of sides of polygon = 360 / exterior anglen = 360 / 15n = 24

Q: Two persons start running simultaneously around a circular track of length 600 m from the same point at speeds of 25 kmph and 35 kmph. When will they meet for the first time any where on the track  ? 1611 0

  • 1
    54 sec
    Correct
    Wrong
  • 2
    36 sec
    Correct
    Wrong
  • 3
    72 sec
    Correct
    Wrong
  • 4
    11 sec
    Correct
    Wrong
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Answer : 2. "36 sec"
Explanation :

Answer: B) 36 sec Explanation: Time taken to meet the first time = length of track/relative speed   Given the length of the track is 600 m   The relative speed = 25 + 35 = 60 kmph = 60 x 5/18 m   Therefore Time = 60025+35518= 600/60 x (18/5) = 36 sec.

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