Answer: B) 70 years Explanation: Let Kumar’s present age be "x" years and Sailesh’s present age be "y" years.Then, according to the first condition, x - 10 = 3(y - 10) => x - 3y = - 20 ........(1) Now, Kumar’s age after 10 years = (x + 10) years. Sailesh’s age after 10 years = (y + 10) years. (x + 10) = 2 (y + 10)  => x - 2y = 10 ......(2)   Solving (1) and (2), we get x = 70 and y = 30 Kumar’s present age = 70 years    and  Sailesh’s present age = 30 years.

Answer: A) 45 metric tonnes Explanation: 2 engines of former type for one hour consumes (2 x 24)/(6 x8) = 1 metric ton  i.e. 3 engines of latter type consumes 1 ton for one hour Hence 9 engines consumes 3 tons for one hour For 15 hours it is 15 x 3 = 45 metric tonnes.

Answer: D) 31 Explanation: Let y be the total number of loavesa be the remaining loaves after 1st thiefb be the remaining loaves after 2nd thiefand c, d..so on after 3 and 4 the = 0 be the remaining loaves after 5th thief a = y - (y/2 + 1/2)= y/2 - 1/2 b = a - (a/2 + 1/2)= a/2 - 1/2 c = b - (b/2 + 1/2)= b/2 - 1/2 d = c - (c/2 + 1/2)= c/2 - 1/2 e = d - (d/2 + 1/2)= d/2 - 1/2we know that, e = 0,thus by substitution, we getd = 1c = 3b = 7a = 15y = 31Therefore total number of bread loaves in bakery was 31.

Answer: D) Granite Explanation: Except Granite all other options belong to the group of precious stones.

Answer: A) 127.5 m Explanation: When A runs 1000 m, B runs 900 m and when B runs 800 m, C runs 700 m. When B runs 900 m, distance that C runs = (900 x 700)/800 = 6300/8 = 787.5 m. In a race of 1000 m, A beats C by (1000 - 787.5) = 212.5 m to C. In a race of 600 m, the number of meters by which A beats C = (600 x 212.5)/1000 = 127.5 m.

Answer: C) 3:2 Explanation: Let us assume S as number of shirts and T as number of trousersGiven that each trouser cost = Rs.70 and that of shirt = Rs.30Therefore, 70 T + 30 S = 810=> 7T + 3S = 81......(1)T = ( 81 - 3S )/7 We need to find the least value of S which will make (81 - 3S) divisible by 7 to get maximum value of TSimplifying by taking 3 as common factor i.e, 3(27-S) / 7In the above equation least value of S as 6 so that 27- 3S becomes divisible by 7 Hence T = (81-3xS)/7 = (81-3x6)/7 = 63/7 = 9 Hence for S, put T in eq(1), we getS = 81-7(9)/3 = 81-63 / 3 = 18/3 = 6.The ratio of T:S = 9:6 = 3:2.

Answer: D) 64 days Explanation: (P+Q)'s 1 day work = 1/24 P's 1 day work = 1/32 => Q's 1 day work = 1/24 - 1/32 = 1/96 Work done by (P+Q) in 8 days = 8/24 = 1/3 Remainining work = 1 - 1/3 = 2/3 Time taken by Q to complete the remaining work = 2/3 x 96 = 64 days.

Answer: C) 175 Explanation: Given that,  working days = 5  working hours = 8  A man get rupess per hour is Rs.2.40  So in one day the man get total rupees is 2.40 x 8 = 19.2  So in 5 days week the man get total rupees is 19.2 x 5 = 96  So in 4 week the man get total rupees is 96 x 4 = 384  So the man worked for = 160hours in 4 weeks    But given that the man earned Rs.432    Hence remaning money is (432-384 = 48)which is earn by doing overtime work   Overtime hours  = 48/3.20 = 15 So total worked hours is = 15 + 160 = 175.