Quantitative Aptitude Practice Question and Answer
8Q: Equal quantities of three mixtures of milk and water are mixed in the ratio 1:2, 2:3 and 3:4. The ratio of water and milk in the mixture is ? 3471 05b5cc73ae4d2b4197774f8c9
5b5cc73ae4d2b4197774f8c9- 1193 : 122true
- 297 : 102false
- 3115 : 201false
- 4147 : 185false
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Answer : 1. "193 : 122"
Explanation :
Answer: A) 193 : 122 Explanation: Given the three mixtures ratio as (1:2),(2:3),(3:4) (1+2),(2+3),(3+4) Total content = 3,5,7 Given equal quantities of the three mixtures are mixed, then LCM of 3, 5, 7 = 105 105/3 = 35 , 105/5 = 21 , 105/7 = 15 Now, the individual equal quantity ratios are (35x1, 35x2), (21x2, 21x3), (15x3, 15x4) i.e (35,70), (42,63), (45,60) So overall mixture ratio of milk and water is 35+42+45 : 70+63+60 122:193 But in the question asked the ratio of water to milk = 193 : 122
Q: Ram can complete ¼ th part of work in 8 days and Shyam can complete 2/4 th of the work in 6 days and Naresh can complete ¾th the work in 12 days. In how many days can they together complete it? 3465 15d147f2b9aeb0a08f1e6721a
5d147f2b9aeb0a08f1e6721a- 1\(6 {11 \over 17 }\)false
- 2\(5 {11 \over 17 }\)true
- 3\(8 {11 \over 17 }\)false
- 4\(7 {11 \over 17 }\)false
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Answer : 2. "\(5 {11 \over 17 }\)"
Q: Find the next number in the given number series? 50, 51, 47, 56, 40, ? 3460 05b5cc669e4d2b4197774bf52
5b5cc669e4d2b4197774bf52- 158false
- 265true
- 376false
- 481false
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Answer : 2. "65"
Explanation :
Answer: B) 65 Explanation: The given number series is 50, 51, 47, 56, 40, ? 5050 + 12 = 5151 - 22 = 4747 + 32 = 5656 - 42 = 4040 + 52 = 65 Hence, the next number in the given number series is 65.
Q: Mother’s age today is thrice as her daughter’s. After 10 years it would be just double. How old is the daughter today ? 3459 05b5cc75ee4d2b4197774fcde
5b5cc75ee4d2b4197774fcde- 18 yearsfalse
- 29 yearsfalse
- 310 yearstrue
- 411 yearsfalse
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Answer : 3. "10 years"
Explanation :
Answer: C) 10 years Explanation: Let the age of the daughter today be ‘x’ years. Mother’s age today = 3x years After 10 years, we have 3x + 10 = 2(x + 10) x = 10 years.
Q: What approximate value should come at place of the question mark(?) in the following question?
3457 05d4ab44e108bca202e8a68d0
5d4ab44e108bca202e8a68d0- 18false
- 238false
- 358false
- 468false
- 518true
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Answer : 5. "18"
Q: If (89)2 is added to the square of a number, the answer so obtained is 16202. What is the (1/26) of that number? 3454 05b5cc6bde4d2b4197774d947
5b5cc6bde4d2b4197774d947- 15.65false
- 22.7false
- 33.5true
- 46.66false
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Answer : 3. "3.5"
Explanation :
Answer: C) 3.5 Explanation: Let the number is = x (89)2 + x2 = 16202 x2 = 8281 x = 91 => (1/26) of 91 = 3.5
Q: 96% of the population of a village is 23040. The total population of the village is ? 3450 05b5cc6e7e4d2b4197774ed92
5b5cc6e7e4d2b4197774ed92- 124000true
- 232256false
- 325478false
- 426587false
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Answer : 1. "24000"
Explanation :
Answer: A) 24000 Explanation: Let the total population be 'P' P x (96/100) = 23040 P = 240 * 100 P = 24000.
Q: fifteen persons are sitting around a circular table facing the centre. What is the probability that three particular persons sit together ? 3447 05b5cc731e4d2b4197774f7dd
5b5cc731e4d2b4197774f7dd- 13/91true
- 22/73false
- 31/91false
- 43/73false
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Answer : 1. "3/91"
Explanation :
Answer: A) 3/91 Explanation: In a circle of n different persons, the total number of arrangements possible = (n - 1)!Total number of arrangements = n(S) = (15 – 1)! = 14 !Taking three persons as a unit, total persons = 13 (in 4 units)Therefore no. of ways for these 13 persons to around the circular table = (13 - 1)! = 12!In any given unit, 3 particular person can sit in 3!. Hence total number of ways that any three person can sit =n(E) = 12! X 3!Therefore P (E) = probability of three persons sitting together = n(E) / n(S) = 12! X 3 ! / 14!= 12!x3x2 / 14x13x12! = 6/14x13 = 3/91