Quantitative Aptitude Practice Question and Answer
8Q: The average age of seven persons sitting in a row facing east is 26 years. If the average age of the first three persons is 19 years and the average age of the last three persons is 32 years, then find the age of the person sitting in the middle of the row ? 2741 05b5cc6dce4d2b4197774e97e
5b5cc6dce4d2b4197774e97e- 132 yrsfalse
- 229 yrstrue
- 324 yrsfalse
- 427 yrsfalse
- Show Answer
- Workspace
- SingleChoice
Answer : 2. "29 yrs"
Explanation :
Answer: B) 29 yrs Explanation: Total age seven persons = (26 x 7)yearsTotal age of the first three persons and the last three persons are (19 x 3) years and (32 x 3) years respectively.Age of the person sitting in the middle of the row = 26 x 7 - 19 x 3 - 32 x 3 = 182 - 57 - 96 = 29 years.
Q: A group consists of 4 men, 6 women and 5 children. In how many ways can 2 men , 3 women and 1 child selected from the given group ? 2739 05b5cc6dde4d2b4197774e9d3
5b5cc6dde4d2b4197774e9d3- 1600true
- 2610false
- 3609false
- 4599false
- Show Answer
- Workspace
- SingleChoice
Answer : 1. "600"
Explanation :
Answer: A) 600 Explanation: Two men, three women and one child can be selected in ⁴C₂ x ⁶C₃ x ⁵C₁ ways = 600 ways.
Q: If 4th december 1999 is Monday then what day is 3rd january 2000 ? 2738 05b5cc73ae4d2b4197774f8ba
5b5cc73ae4d2b4197774f8ba- 1Sundayfalse
- 2Mondayfalse
- 3Tuesdayfalse
- 4Wednesdaytrue
- Show Answer
- Workspace
- SingleChoice
Answer : 4. "Wednesday"
Explanation :
Answer: D) Wednesday Explanation: Here from 4th December 1999 to 3rd January 2000,there is a difference of 30 days.Number of odd days = 30/7 = 2 odd days Then no. of odd days = 2 => tuesday and wednesday(from monday). Hence on 3rd january it is wednesday.
Q: In what time will Rs. 3300 becomes Rs. 3399 at 6% per annum interest compounded half-yearly ? 2711 05b5cc701e4d2b4197774f175
5b5cc701e4d2b4197774f175- 1Quarter monthsfalse
- 2Half yeartrue
- 32 yearsfalse
- 41 yearfalse
- Show Answer
- Workspace
- SingleChoice
Answer : 2. "Half year"
Explanation :
Answer: B) Half year Explanation: 3300 ----- 3% ↑ (1st time interval, 99) → 3399. Here, time interval is given as half-yearly i.e. 6 months.
Q: Two trains of 440 metre and 260 metre lengths are running in the same direction and crosses each other in 35 sec. If the speed of slower train is 63 km/hr., then what is the speed of the faster train? 2708 05d15f90f5fdb2c68495d9df4
5d15f90f5fdb2c68495d9df4- 1135 km/hourtrue
- 2125 km/hourfalse
- 3138 km/hourfalse
- 4250 km/hourfalse
- Show Answer
- Workspace
- SingleChoice
Answer : 1. "135 km/hour"
Q: If a2+b2 = c2 , then 1logc+ab + 1logc-ab = ? 2705 15b5cc761e4d2b4197774fd67
5b5cc761e4d2b4197774fd67- 11false
- 22true
- 34false
- 48false
- Show Answer
- Workspace
- SingleChoice
Answer : 2. "2"
Explanation :
Answer: B) 2 Explanation: Given a2 + b2 = c2 Now 1logc+ab + 1logc-ab = logbc+a + logbc-a = logbc2-a2 = 2logbb = 2
Q: Simplify the following : 373+353+283-3x37x35x28372+352+282-37x35-35x28-37x28 ? 2704 05b5cc6cae4d2b4197774dffc
5b5cc6cae4d2b4197774dffc- 1100true
- 21false
- 34false
- 40false
- Show Answer
- Workspace
- SingleChoice
Answer : 1. "100"
Explanation :
Answer: A) 100 Explanation: Given 373+353+283-3x37x35x28372+352+282-37x35-35x28-37x28 It is in the form of a3+b3+c3-3abca2+b2+c2-ab-bc-ca= a + b + c Here a = 37, b = 35 & c = 28 => a + b + c = 37 + 35 + 28 = 100 Therefore, = 100
Q: Train X crosses a stationary train Y in 60 seconds and a pole in 25 seconds with the same speed. The length of the train X is 300 m. What is the length of the stationary train Y ? 2702 05b5cc6d8e4d2b4197774e7c6
5b5cc6d8e4d2b4197774e7c6- 1360 mfalse
- 2420 mtrue
- 3460 mfalse
- 4320 mfalse
- Show Answer
- Workspace
- SingleChoice
Answer : 2. "420 m"
Explanation :
Answer: B) 420 m Explanation: Let the length of the stationary train Y be LY Given that length of train X, LX = 300 m Let the speed of Train X be V. Since the train X crosses train Y and a pole in 60 seconds and 25 seconds respectively. => 300/V = 25 ---> ( 1 ) (300 + LY) / V = 60 ---> ( 2 ) From (1) V = 300/25 = 12 m/sec. From (2) (300 + LY)/12 = 60 => 300 + LY = 60 (12) = 720 => LY = 720 - 300 = 420 m Length of the stationary train = 420 m