Quantitative Aptitude Practice Question and Answer
8Q: The percentage discount offered for "Buy 6 get 1 free is" ? 3327 05b5cc72ce4d2b4197774f788
5b5cc72ce4d2b4197774f788- 185.78 %false
- 258. 48 %false
- 319.25 %false
- 414.285 %true
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Answer : 4. "14.285 %"
Explanation :
Answer: D) 14.285 % Explanation: Total Items = 7Discounted = 1Percentage = 1/7 x 100= 14.285%
Q: Running 3/4th of his usual rate, a man is 15min late. Find his usual time in hours ? 3300 05b5cc6d8e4d2b4197774e782
5b5cc6d8e4d2b4197774e782- 12/3 hrsfalse
- 23/4 hrstrue
- 31/3 hrsfalse
- 41/4 hrsfalse
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Answer : 2. "3/4 hrs"
Explanation :
Answer: B) 3/4 hrs Explanation: Walking at 3/4th of usual rate implies that time taken would be 4/3th of the usual time. In other words, the time taken is 1/3rd more than his usual time so 1/3rd of the usual time = 15minor usual time = 3 x 15 = 45min = 45/60 hrs = 3/4 hrs.
Q: Three taps P, Q and R can fill a tank in 12 hrs, 15 hrs and 20 hrs respectively. If P is open all the time and Q and R are open for one hour each alternately, starting with Q, then the tank will be full in how many hours ? 3297 05b5cc6c0e4d2b4197774dafb
5b5cc6c0e4d2b4197774dafb- 19 hrsfalse
- 27 hrstrue
- 313 hrsfalse
- 411 hrsfalse
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Answer : 2. "7 hrs"
Explanation :
Answer: B) 7 hrs Explanation: Given, P can fill in 12 hrs Q can fill in 15 hrs R can fill in 20 hrs => Volume of tank = LCM of 12, 15, 20 = 60 lit => P alone can fill the tank in 60/12 = 5 hrs => Q alone can fill the tank in 60/15 = 4 hrs => R alone can fill the tank in 60/20 = 3 hrs Tank can be filled in the way that (P+Q) + (P+R) + (P+Q) + (P+R) + .... => Tank filled in 2 hrs = (5+4) + (5+3) = 9 + 8 = 17 lit => In 6 hrs = 17 x 6/2 = 51 lit => In 7th hr = 51 + (5+4) = 51 + 9 = 60 lit => So, total tank will be filled in 7 hrs.
Q: If a2+b2 = c2 , then 1logc+ab + 1logc-ab = ? 3297 15b5cc761e4d2b4197774fd67
5b5cc761e4d2b4197774fd67- 11false
- 22true
- 34false
- 48false
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Answer : 2. "2"
Explanation :
Answer: B) 2 Explanation: Given a2 + b2 = c2 Now 1logc+ab + 1logc-ab = logbc+a + logbc-a = logbc2-a2 = 2logbb = 2
Q: In what time will Rs. 3300 becomes Rs. 3399 at 6% per annum interest compounded half-yearly ? 3286 05b5cc701e4d2b4197774f175
5b5cc701e4d2b4197774f175- 1Quarter monthsfalse
- 2Half yeartrue
- 32 yearsfalse
- 41 yearfalse
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Answer : 2. "Half year"
Explanation :
Answer: B) Half year Explanation: 3300 ----- 3% ↑ (1st time interval, 99) → 3399. Here, time interval is given as half-yearly i.e. 6 months.
Q: A bus is running at 80 kmph without any stoppage. But, with stoppages its average speed is 60 km/hour. Find the time of stoppage by bus per hour. 3280 15d1994467619fe30b9d338a6
5d1994467619fe30b9d338a6- 112 minutesfalse
- 220 minutesfalse
- 330 minutesfalse
- 415 minutestrue
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Answer : 4. "15 minutes"
Q: A, B, C and D enter into partnership. A subscribes 1/3 of the capital B 1/4, C 1/5 and D the rest. How much share did A get in a profit of Rs.2490 ? 3268 05b5cc6e1e4d2b4197774ebb1
5b5cc6e1e4d2b4197774ebb1- 1Rs. 820false
- 2Rs. 830true
- 3Rs. 840false
- 4Rs. 850false
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Answer : 2. "Rs. 830"
Explanation :
Answer: B) Rs. 830 Explanation: Let the total amount in the partnership be 'x'.Then A's share = x/3B's share = x/4C's share = x/5D's share = x - (x/3 + x/4 +x/5) = 13x/60 A : B : C : D = x/3 : x/4 : x/5 : 13x/60 = 20 : 15 : 12 : 13 A's share in the profit of Rs. 2490 = 20 (2490/60) = Rs. 830.
Q: At a dinner party every two guests used a bowl of rice between them, every three guests used a bowl of dal between them and every four used a bowl of meat between them. There were altogether 65 dishes. How many guests were present at the party ? 3266 05b5cc720e4d2b4197774f636
5b5cc720e4d2b4197774f636- 160true
- 274false
- 382false
- 458false
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Answer : 1. "60"
Explanation :
Answer: A) 60 Explanation: Let, no. of rice bowl = xno. of dal bowl = yno. of meat bowl = z Then, x + y + z = 65 ....(1) Also given that, 2x = 3y = 4z substituting value of y & z in terms of x i.e. y = 2x/3 and z = x/2 in eq (1),We get x = 30. As 1 rice bowl is shared between 2 guests, Therefore, there are 60 guests.