Quantitative Aptitude Practice Question and Answer
8Q: In a queue, Shankar is ninth from the rear end. Althaf's place is eighth from the front. Nitu is standing between the two. What could be the minimum numbers of boys standing in the queue ? 2960 05b5cc74ae4d2b4197774fa9a
5b5cc74ae4d2b4197774fa9a- 118false
- 214true
- 322false
- 424false
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Answer : 2. "14"
Explanation :
Answer: B) 14 Explanation: 1 2 3 4 5 6(Shankar) 7(Nitu) 8(Althaf) 9 10 11 12 13 14Here, Althaf is 8th from front, Shankar is 9th from rear end and Nitu is between themSo minimum no. of boys standing in the queue = 14
Q: A group consists of 4 men, 6 women and 5 children. In how many ways can 2 men , 3 women and 1 child selected from the given group ? 2930 05b5cc6dde4d2b4197774e9d3
5b5cc6dde4d2b4197774e9d3- 1600true
- 2610false
- 3609false
- 4599false
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Answer : 1. "600"
Explanation :
Answer: A) 600 Explanation: Two men, three women and one child can be selected in ⁴C₂ x ⁶C₃ x ⁵C₁ ways = 600 ways.
Q: Eight years ago, Ajay's age was 4/3 times that of Vijay. Eight years hence, Ajay's age will be 6/5 times that of Vijay. What is the present age of Ajay ? 2927 05b5cc6eee4d2b4197774ef04
5b5cc6eee4d2b4197774ef04- 141 yrsfalse
- 240 yrstrue
- 337 yrsfalse
- 433 yrsfalse
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Answer : 2. "40 yrs"
Explanation :
Answer: B) 40 yrs Explanation: Let the present ages of Ajay and Vijay be 'A' and 'V' years respectively. => A - 8 = 4/3 (V - 8) and A + 8 = 6/5 (V + 8) => 3/4(A - 8) = V - 8 and 5/6(A + 8) = V + 8 V = 3/4 (A - 8) + 8 = 5/6 (A + 8) - 8 => 3/4 A - 6 + 8 = 5/6 A + 20/3 - 8 => 10 - 20/3 = 10/12 A - 9/12 A => 10/3 = A/12 => A = 40.
Q: If (1 × 2 × 3 × 4 ........ × n) = n!, then 15! - 14! - 13! is equal to ___? 2921 05b5cc6bee4d2b4197774d997
5b5cc6bee4d2b4197774d997- 114 × 13 × 13!false
- 215 × 14 × 14!false
- 314 × 12 × 12!false
- 415 × 13 × 13!true
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Answer : 4. "15 × 13 × 13!"
Explanation :
Answer: D) 15 × 13 × 13! Explanation: 15! - 14! - 13! = (15 × 14 × 13!) - (14 × 13!) - (13!) = 13! (15 × 14 - 14 - 1) = 13! (15 × 14 - 15) = 13! x 15 (14 - 1) = 15 × 13 × 13!
Q: If 4th december 1999 is Monday then what day is 3rd january 2000 ? 2916 05b5cc73ae4d2b4197774f8ba
5b5cc73ae4d2b4197774f8ba- 1Sundayfalse
- 2Mondayfalse
- 3Tuesdayfalse
- 4Wednesdaytrue
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Answer : 4. "Wednesday"
Explanation :
Answer: D) Wednesday Explanation: Here from 4th December 1999 to 3rd January 2000,there is a difference of 30 days.Number of odd days = 30/7 = 2 odd days Then no. of odd days = 2 => tuesday and wednesday(from monday). Hence on 3rd january it is wednesday.
Q: A bus is running at 80 kmph without any stoppage. But, with stoppages its average speed is 60 km/hour. Find the time of stoppage by bus per hour. 2912 15d1994467619fe30b9d338a6
5d1994467619fe30b9d338a6- 112 minutesfalse
- 220 minutesfalse
- 330 minutesfalse
- 415 minutestrue
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Answer : 4. "15 minutes"
Q: In what time will Rs. 3300 becomes Rs. 3399 at 6% per annum interest compounded half-yearly ? 2911 05b5cc701e4d2b4197774f175
5b5cc701e4d2b4197774f175- 1Quarter monthsfalse
- 2Half yeartrue
- 32 yearsfalse
- 41 yearfalse
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Answer : 2. "Half year"
Explanation :
Answer: B) Half year Explanation: 3300 ----- 3% ↑ (1st time interval, 99) → 3399. Here, time interval is given as half-yearly i.e. 6 months.
Q: The percentage discount offered for "Buy 6 get 1 free is" ? 2889 05b5cc72ce4d2b4197774f788
5b5cc72ce4d2b4197774f788- 185.78 %false
- 258. 48 %false
- 319.25 %false
- 414.285 %true
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Answer : 4. "14.285 %"
Explanation :
Answer: D) 14.285 % Explanation: Total Items = 7Discounted = 1Percentage = 1/7 x 100= 14.285%