Quantitative Aptitude Practice Question and Answer
8Q: A can build a wall in 16 days while B can destroy it in 8 days. A worked for 5 days. Then B joined with A for the next 2 days. Find in how many days could A build the remaining wall ? 2712 05b5cc6cee4d2b4197774e208
5b5cc6cee4d2b4197774e208- 112 daysfalse
- 214 daysfalse
- 313 daystrue
- 416 daysfalse
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Answer : 3. "13 days"
Explanation :
Answer: C) 13 days Explanation: Now, Total work = LCM(16, 8) = 48 A's one day work = + 48/16 = + 3 B's one day work = - 48/8 = -6 Given A worked for 5 days to build the wall => 5 days work = 5 x 3 = + 15 2days B joined with A in working = 2(3 - 6) = - 6 Remaining Work of building wall = 48 - (15 - 6) = 39 Now this remaining work will be done by A in = 39/3 = 13 days.
Q: Rs. 69 were divided among 115 family members so that each lady gets 50 paise less than each gentleman, and each gentleman received twice the paise as each lady received. Find the number of gentlemen in the family? 2710 05b5cc67be4d2b4197774c1f0
5b5cc67be4d2b4197774c1f0- 123true
- 292false
- 348false
- 452false
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Answer : 1. "23"
Explanation :
Answer: A) 23 Explanation: Total number of female members = 115 Let the number of males = x Number of females = y => x + y = 115 ......(1) According to the given data, x + y(0.50) = 69 ......(2) From (1) & (2), we get 0.5y = 46 => y = 46 x 2 = 92 => x = 115 - 92 = 23 Hence, required number of gentlemen in the family = x = 23.
Q: If x is a whole number, then x²(x² - 1) is always divisible by ? 2704 05b5cc761e4d2b4197774fd58
5b5cc761e4d2b4197774fd58- 14false
- 28false
- 312true
- 4Nonefalse
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Answer : 3. "12"
Explanation :
Answer: C) 12 Explanation: we can do this by trial and error method. Putting x = 2,we get 2²(2² - 1) = 12.checking with other integers, the above equation always gives a value which is a multiple of 12,So, x²(x² - 1) is always divisible by 12.
Q: Kamal consistently runs 240 meters a day and on Saturday he runs for 400 meters. How many kilometers will he have to run in four weeks ? 2701 05b5cc6c5e4d2b4197774dd23
5b5cc6c5e4d2b4197774dd23- 15.75 kmsfalse
- 27.36 kmstrue
- 38.2 kmsfalse
- 46.98 kmsfalse
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Answer : 2. "7.36 kms"
Explanation :
Answer: B) 7.36 kms Explanation: Total running distance in four weeks = (24 x 240) + (4 x 400) = 5760 + 1600 = 7360 meters = 7360/1000 => 7.36 kms
Q: A can do a piece of work in 21 days and B in 28 days. Together they started the work and B left after 4 days. In how many days can A alone do the remaining work ? 2700 05b5cc6e5e4d2b4197774ed3d
5b5cc6e5e4d2b4197774ed3d- 114 daystrue
- 218 daysfalse
- 321 deaysfalse
- 416 daysfalse
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Answer : 1. "14 days"
Explanation :
Answer: A) 14 days Explanation: Let A worked for x days. x/21 + 4/28 = 1 => x = 18 A worked for 18 days. So, A can complete the remaining work in 18 - 4 = 14 days.
Q: A number when subtracted by 1/7 th of itself gives the same value as the sum of all the angles of a triangle. What is the number? 2700 05b5cc619e4d2b4197774b700
5b5cc619e4d2b4197774b700- 1420false
- 2210true
- 370false
- 435false
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Answer : 2. "210"
Explanation :
Answer: B) 210 Explanation: Let the required number be 'p' We know, sum of angles in a triangle are 180 deg According to given data, p - p/7 = 180 7p - p = 180 x 7 => 6p = 1260 => p = 1260/6 = 210
Q: 5 men and 4 women are to be seated in a row so that the women occupy the even places . How many such arrangements are possible? 2695 15b5cc7d1e4d2b4197775129f
5b5cc7d1e4d2b4197775129f- 12880true
- 21440false
- 3720false
- 42020false
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Answer : 1. "2880"
Explanation :
Answer: A) 2880 Explanation: There are total 9 places out of which 4 are even and rest 5 places are odd. 4 women can be arranged at 4 even places in 4! ways. and 5 men can be placed in remaining 5 places in 5! ways. Hence, the required number of permutations = 4! x 5! = 24 x 120 = 2880
Q: Two trains 85 m and 75 m long are running in same direction with speeds of 62 km/hr and 44 km/hr respectively. In what time will the first train cross the second train ? 2693 15b5cc783e4d2b41977750214
5b5cc783e4d2b41977750214- 122 secfalse
- 232 sectrue
- 342 secfalse
- 452 secfalse
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Answer : 2. "32 sec"
Explanation :
Answer: B) 32 sec Explanation: Given that, 1st train speed = 62 km/hr 2nd train speed = 44 km/hr Hence the relative speed of two trains is : 62-44 = 18 km/hr = 18×518 m/s = 5 m/s. There fore, the first train crosses the second train i.e (85+75)mts of distance with a speed of 5m/s in, time = distancespeed = 85+755 = 32 sec.